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DO NOW: On the back of your worksheet! Fill in your table of contents!
1) If I have 5.6 liters of gas in a piston at a pressure of 1.5 atm and compress the gas until its volume is 4.8 L, what will the new pressure inside the piston be? 2) I have added 15 L of air to a balloon at sea level (1.0 atm). If I take the balloon with me to Denver, where the air pressure is 0.85 atm, what will the new volume of the balloon be?
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After today you will be able to…
Explain the effect on gas properties using Charles’s law Calculate an unknown temperature, or volume by solving algebraically
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Charles’s Law: Temperature and Volume
Jacques Charles studied the effect of temperature on volume of a gas at constant pressure. In 1787 Charles proposed a law to describe his observations.
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“For a given mass of a gas, at constant pressure, the volume of the gas is directly proportional to its temperature in Kelvin.”
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Charles’s Law: Temperature and Volume
We can simplify this relationship by the formula: Where, V1, V2 = volume in any unit (L or mL), BUT they must match! T1, T2 = temperature is always in Kelvin! (Recall, just add °C) V1 V2 T1 T2 =
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Charles’s Law: Example
A gas has a volume of 4.0L at 27°C. What is its volume at 153°C? V1= T1= V2= T2= V1 V2 T1 T2 4.0L = 27°C +273= 300K ? 153°C+273= 426K (4.0L) (V2) = (300K) (426K) V2 = 5.7L
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Complete your worksheet!
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Questions? Complete WS 2
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