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Created for CVCA Physics By Dick Heckathorn 22 March 2K+5

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Presentation on theme: "Created for CVCA Physics By Dick Heckathorn 22 March 2K+5"— Presentation transcript:

1 Created for CVCA Physics By Dick Heckathorn 22 March 2K+5
Figure 8 Resistors Created for CVCA Physics By Dick Heckathorn 22 March 2K+5

2 Kirchhoff’s Current Law
At any junction point in an electric circuit, the total electric current into the junction is equal to the total electric current out of the junction.

3 Kirchhoff’s Voltage Law
Around any complete path through an electric circuit, the sum of the increases in electric potential is equal to the sum of the decreases in electric potential.

4 What is RT or REquivalent? Each resistance has value ‘R’
Figure 8 Resistors C F B I1 I2 I3 I1 I2 I3 I1 I2 I3 I1 I2 A I3 D I3 E I3 I3 VT What is RT or REquivalent? Each resistance has value ‘R’

5 A  B  C  D  A = 0 I1R + I1R + I1R - I2R + I1R - I3R
F B I1 I2 I3 I1 I2 I3 I1 I2 I3 I1 I2 A I3 D I3 E I3 I3 VT Blue Circuit A  B  C  D  A = 0 I1R + I1R + I1R - I2R + I1R - I3R 4 I1R - I2R - I3R = 0 #1

6 Green Circuit - I1R + 4 I2R - 2 I3R = 0
F B I1 I2 I3 I1 I2 I3 I1 I2 I3 I1 I2 A I3 D I3 E I3 I3 VT Green Circuit C  F  E  D  C + I2R + I2R - I3R + I2R - I3R + I2R -I1R = 0 - I1R + 4 I2R - 2 I3R = 0 #2

7 Red Circuit - I1R - 2 I2R + 3 I3R = VT
F B I1 I2 I3 I1 I2 I3 I1 I2 I3 I1 I2 A I3 D I3 E I3 I3 VT V Red Circuit A  D  E  F  A I3R - I1R + I3R - I2R + I3R - I2R = VT - I1R - 2 I2R + 3 I3R = VT #3

8 3 Equations with 3 Unknowns
4 I1R I2R I3R = 0 #1 - I1R + 4 I2R - 2 I3R = 0 #2 - I1R - 2 I2R + 3 I3R = VT #3

9 Now for the analysis Combine Equations 1 & 3 # 1 4 I1R - I2R - I3R = 0
[ ] x4 # 3 I1R - 2 I2R I3R = V # 3 - 4 I1R - 8 I2R + 12 I3R = 4V # 1 4 I1R - I2R I3R = 0 # 1&3 - 9 I2R + 11 I3R = 4V

10 Combine Equations 2 & 3 # 2 - I1R + 4 I2R - 2 I3R = 0 # 3 [ ] x-1
- I1R - 2 I2R + 3 I3R = VT # 3 + I1R + 2 I2R - 3 I3R = - VT # 2 - I1R + 4 I2R - 2 I3R = 0 # 2&3 + 6 I2R - 5 I3R = - VT

11 Continued analysis # 1&3 - 9 I2R + 11 I3R = 4 VT ] x2 ] x3 # 2&3

12 Continued analysis 7 I3R = 5 VT VT = IT RT 7 I3R = 5 IT RT I3 = IT
7 R = 5 RT RT = 7/5 R R = 10 Ω RT = 14 Ω


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