1. Chapter 11
Homework Answers

2. Mole Ratio Practice Pb + 2HCl  PbCl2 + H2 C + 2ZnO  2Zn + CO2
x mol
Pb + 2HCl  PbCl2 + H2
C + 2ZnO  2Zn + CO2
1 mol Pb = 2 mol HCl
0.38 mol
x mol
2 mol ZnO = 1 mol CO2

3. Mole Ratio Practice 3. P4 + 6Br2  4PBr3 4. C3H8 + 5O2  3CO2 + 4H2O
x mol
3. P4 + 6Br2  4PBr3
4. C3H8 + 5O2  3CO2 + 4H2O
6 mol Br2 = 4 mol PBr3
0.38 mol
x mol
1 mol C3H8 = 5 mol O2

4. Mole Ratio Practice 5. 4Fe + 3O2  2Fe2O3
x mol
Fe + 3O2  2Fe2O3
C6H6 + 15O2  12CO2 + 6H2O
4 mol Fe = 2 mol Fe2O3
2.35 mol
x mol
15 mol O2 = 6 mol H2O

5. Mole Ratio Practice 7. 2Al + 6HCl  2AlCl3 + 3H2
x mol
Al + 6HCl  2AlCl3 + 3H2
8. Zn + H2SO4  ZnSO4 + H2
2 mol Al = 6 mol HCl
0.36 mol
x mol
1 mol Zn = 1 mol H2

6. Stoichiometry Practice
0.284 mol
x mol
1. Mg + 2HCl  MgCl2 + H2
2. Br2 + 2NaI  2NaBr + I2
2 mol HCl = 1 mol H2
11.27 g
x mol
1 mol Br2 = 2 mol NaBr

7. Stoichiometry Practice
2.09 mol
x g
3. WO3 + 3H2  W + 3H2O
4. C3H8 + 5O2  3CO2 + 4H2O
1 mol WO3 = 3 mol H2O
6.4 L
x L
5 mol O2 = 3 mol CO2

8. Stoichiometry Practice
3 mol CCl4= 2 mol SbCl3
x g
186g
CCl4 + 2SbF3  3CCl2F2 + 2SbCl3
Al + 6HCl  2AlCl3 + 3H2
0.46 mol
x L
2 mol Al = 3 mol H2

9. Stoichiometry Practice
2 mol HCl = 1 mol MgCl2
x g
16.4 g
7. Mg + 2HCl  2AlCl3 + 3H2
Na + 2H2O  2NaOH + H2
x g
5.68 L
2 mol H2O = 1 mol H2

10. Stoichiometry Practice
227 g
x mol
2 mol CO = 1 mol O2
CO + O2  2CO2
Al + 3H2SO4  Al2(SO4)3 + 3H2
2 mol H2O = 1 mol H2
x atoms
4.72 L

11. Mixed Review Answers
1.) 40 L NH3 2.) 2.0 g O2 3.) 2.5 x 1022 formula units KCl 4.) 0.86 L H2 5.) mol H2O 6.) 9.03 x 1024 molecules Cl2

12. Stoichiometry Mixed Review
25 g
x L
1 mol N2 = 2 mol NH3
1. N2 + 3H2  2NH3
KClO3  2KCl + 3O2
5.0 g
x g
2 mol KClO3 = 3 mol O2

13. Stoichiometry Mixed Review
5.0 g
x F.U.
2 mol KClO3 = 2 mol KCl
2KClO3  2KCl + 3O2
4. Zn + HCl  ZnCl2 + H2
2.5 g
x L
1 mol Zn = 1 mol H2

14. Stoichiometry Mixed Review
2 mol H2O= 1 mol Na2SO4
x mol
2.0 g
5. H2SO4 + 2NaOH  2H2O + Na2SO4
AlCl3 2Al + 3Cl2
10 mol
x molecules
2 mol AlCl3 = 3 mol Cl2

15. Stoichiometry Mixed Review BACK
20 g
x L
7. 2K + 2H2O  2KOH + H2
Al + 6HCl  2AlCl3 + 3H2
2 mol K= 1 mol H2
30.2 g
x L
2 mol Al = 2 mol HCl

16. Stoichiometry Mixed Review BACK
5.7 L
x L
1 mol H2 = 2 mol HCl
9. H2 + Cl2  2HCl
H2 + O2  2H2O
x L
.45 mol
2 mol H2 = 1 mol O2

17. Stoichiometry Mixed Review BACK
26.9 L
x L
8 mol O2 = 8 mol SO2
11. S8 + 8O2  8SO2
Zn + Cl2  ZnCl2
16.8 L
x g
1 mol Cl2 = 1 mol ZnCl2

18. Limiting Reactant Practice
x g
1. 6Li + N2  2Li3N
Li is the limiting reactant
93.9 g Li3N produced

19. Limiting Reactant Practice
x g
2. C3H8 + 5O2  3CO2 + 4H2O
O2 is the limiting reactant
4.5 g H2O produced

20. Limiting Reactant Practice
x g
3. KOH + HNO3  KNO3 + H2O
HNO3 is the limiting reactant
19.3 g KNO3 produced

21. Limiting Reactant Practice
x g
4. 2C3H6 + 2NH3 + 3O2  C3H3N + 6H2O
O2 is the limiting reactant
20.4 g H2O produced

22. Percent Yield Practice
6.8 x 104 g
x g
1. 2H2 + CO  CH3OH

23. Percent Yield Practice
30.6 g
x g
2. C7H O2  7CO2 + 8H2O

24. Percent Yield Practice
65.3 g
x g
3. CCl4 + 2HF  CCl2F2 + 2HCl

25. Percent Yield Practice
58.5 g
98.0 g
x g
4. 4Al + 3O2  2Al2O3

26. Limiting Reactant & % Yield Practice
3.45 mol
4.85 mol
x mol
1. N2 + 3H2  2NH3
H2 is the limiting reactant
3.2 mol NH3 produced

27. Limiting Reactant & % Yield Practice
20.0 mol
10.0 mol
x mol
2. 2C2H2 + 5O2  4CO2 + 2H2O
O2 is the limiting reactant
8.0 mol CO2 produced

28. Limiting Reactant & % Yield Practice
2.36 mol
3.89 mol
x g
3. CH3CO2H + NaOH  NaCH3CO2 + H2O
CH3CO2H is the limiting reactant
42.5 g H2O produced

29. Limiting Reactant & % Yield Practice
x g
4. Na2SO4 + Ba(NO3)2  2NaNO3 + BaSO4
Ba(NO3)2 is the limiting reactant
44.7 g BaSO4 produced

30. Limiting Reactant & % Yield Practice
x g
5. 2CH3CO2H + Pb(OH)2  Pb(CH3CO2)2 + 2H2O
*CH3CO2H is in excess
[Pb(OH)2 is limiting]
13.5 g Pb(CH3CO2)2 produced

31. Limiting Reactant & % Yield Practice
x g
6. 2C6H6 + 15O2  12CO2 + 6H2O

32. Limiting Reactant & % Yield Practice
x g
7. C2H4 + Cl2  C2H4Cl2

33. Limiting Reactant & % Yield Practice
x g
8. Al2O3 + 3H2  2Al + 3H2O

34. Chapter 11 Review 2KClO3  2KCl + 3O2 2Na + 2H2O  2NaOH + H2 5.8 mol
x L
2KClO3  2KCl + 3O2
2Na + 2H2O  2NaOH + H2
20.0g
x g

35. Chapter 11 Review 3.
4. H2 + F2  2HF
16.8mol
x g

36. Chapter 11 Review 5. 2H2O  2H2 + O2 6. Ca(OH)2 + 2HCl  CaCl2 + 2H2O
x g
9.2 L
5. 2H2O  2H2 + O2
6. Ca(OH)2 + 2HCl  CaCl2 + 2H2O
126g
150g
x g
Ca(OH)2 is the limiting reactant.
61.2 g H2O is produced.

37. Chapter 11 Review
73.2g
120.5g
x g
7. CaCl2 + Na2CO3  CaCO3 + 2NaCl

38. Chapter 11 Review
Limiting reactant runs out first. It determines how much product is formed. Excess reactant will have some left over when limiting runs out.
1. Convert to moles (if needed)
2. Mole:Mole Ratio
3. Convert to what the question asks for (if needed)

39. Chapter 11 Review
Using the coefficient in the balanced chemical equation, we can relate the number of moles of each substance in the reaction.
When the reactants are present in exact molar ratio. Neither is limiting or excess because they run out at the same time .

40. “g” and “l” don’t affect the problem!
Extra Stoich Practice
1.20 mol
x mol
1.) 4NH3(g) + 5O2(g)  4NO(g) + 6H2O(l) 2.) C2H4(g) + 3 O2(g)  2 CO2(g) + 2 H2O(g)
1.25 L
x L

41. Extra Stoich Practice
X g
3.45 L
3.) CaCO3(s)  CO2(g) + CaO(s) 4.) H2SO4(aq) + 2NaOH(aq)  H2O(l) + Na2SO4(aq)
x mol
2.0 g

42. Extra Stoich Practice
70.0 L
X g
5.) 2 NaN3(s) → 2 Na (s) + 3 N2(g) 6.) 2 Cl2(g) + C2H2(g)  C2H2Cl4(l)
x g
75.0 g

43. Extra Lim. React. & % Practice
80 g
28 g
x mol
1.) I2O5(g) + 5 CO(g)  5 CO2(g) + I2(g)
Part A) CO is the limiting reactant
0.20 mol I2 is produced
Part B)

44. Extra Lim. React. & % Practice
25 g
30 g
x g
2.) Zn S  ZnS
Zn is the limiting reactant
37.3 g ZnS are produced

45. Extra Lim. React. & % Practice
5 g
10 g
x g
3.) 16Al S8  8Al2S3
Al is the limiting reactant
13.9 g Al2S3 are produced

46. Extra Lim. React. & % Practice
10 g
20 g
x g
4.) 3Zn MoO3  Mo2O3 + 3ZnO
Zn is the limiting reactant
12.4 g ZnO are produced

47. Extra Lim. React. & % Practice
x g
25 g
5.) 3AgNO3 + FeCl3 3AgCl + Fe(NO3)3

48. Extra Lim. React. & % Practice
x g
25 g
6.) CaCO3 + SO2 CaSO3 + CO2