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Packet #29 Arithmetic and Geometric Sequences
Math 160 Packet #29 Arithmetic and Geometric Sequences
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An arithmetic sequence is a sequence of the form: π, π+π, π+2π, π+3π, β¦ π is the first term, and π is the common difference. The πth term is given by π π = ______________
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An arithmetic sequence is a sequence of the form: π, π+π, π+2π, π+3π, β¦ π is the first term, and π is the common difference. The πth term is given by π π = ______________
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An arithmetic sequence is a sequence of the form: π, π+π, π+2π, π+3π, β¦ π is the first term, and π is the common difference. The πth term is given by π π = ______________
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An arithmetic sequence is a sequence of the form: π, π+π, π+2π, π+3π, β¦ π is the first term, and π is the common difference. The πth term is given by π π = ______________ π+ πβπ π
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Ex 1. Find the common difference and the 100th term of the following arithmetic sequence. 11, 6, 1, β4, β9, β¦
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Ex 1. Find the common difference and the 100th term of the following arithmetic sequence. 11, 6, 1, β4, β9, β¦
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Ex 1. Find the common difference and the 100th term of the following arithmetic sequence. 11, 6, 1, β4, β9, β¦
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Ex 1. Find the common difference and the 100th term of the following arithmetic sequence. 11, 6, 1, β4, β9, β¦
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Ex 1. Find the common difference and the 100th term of the following arithmetic sequence. 11, 6, 1, β4, β9, β¦
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Ex 2. The 6th term of an arithmetic sequence is 10, and the 13th term is 31. Find the πth term and the 50th term.
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Hereβs a slick way to find the sum of the first 100 numbers:
π 100 = β¦ π 100 = β¦
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Hereβs a slick way to find the sum of the first 100 numbers:
π 100 = β¦ π 100 = β¦
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Hereβs a slick way to find the sum of the first 100 numbers:
π 100 = β¦ π 100 = β¦
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Hereβs a slick way to find the sum of the first 100 numbers:
π 100 = β¦ π 100 = β¦
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Hereβs a slick way to find the sum of the first 100 numbers:
π 100 = β¦ π 100 = β¦
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Hereβs a slick way to find the sum of the first 100 numbers:
π 100 = β¦ π 100 = β¦
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Hereβs a slick way to find the sum of the first 100 numbers:
π 100 = β¦ π 100 = β¦
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Hereβs a slick way to find the sum of the first 100 numbers:
π 100 = β¦ π 100 = β¦
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Hereβs a slick way to find the sum of the first 100 numbers:
π 100 = β¦ π 100 = β¦
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Hereβs a slick way to find the sum of the first 100 numbers:
π 100 = β¦ π 100 = β¦
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This works for all arithmetic sequences, so that the sum of the first π terms ( π π ) is: πΊ π = π π + π π β
π π Ex 4. Find the sum: β¦+159
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This works for all arithmetic sequences, so that the sum of the first π terms ( π π ) is: πΊ π = π π + π π β
π π Ex 3. Find the sum: β¦+159
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This works for all arithmetic sequences, so that the sum of the first π terms ( π π ) is: πΊ π = π π + π π β
π π Ex 3. Find the sum: β¦+159
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This works for all arithmetic sequences, so that the sum of the first π terms ( π π ) is: πΊ π = π π + π π β
π π Ex 3. Find the sum: β¦+159
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This works for all arithmetic sequences, so that the sum of the first π terms ( π π ) is: πΊ π = π π + π π β
π π Ex 3. Find the sum: β¦+159
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A geometric sequence is a sequence of the form: π, ππ, π π 2 , π π 3 , π π 4 , β¦ π is the first term, and π is the common ratio. The πth term is given by π π = _________
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A geometric sequence is a sequence of the form: π, ππ, π π 2 , π π 3 , π π 4 , β¦ π is the first term, and π is the common ratio. The πth term is given by π π = _________
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A geometric sequence is a sequence of the form: π, ππ, π π 2 , π π 3 , π π 4 , β¦ π is the first term, and π is the common ratio. The πth term is given by π π = _________
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A geometric sequence is a sequence of the form: π, ππ, π π 2 , π π 3 , π π 4 , β¦ π is the first term, and π is the common ratio. The πth term is given by π π = _________ π π πβπ
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Ex 4. Find the common ratio and the nth term of the following geometric sequence. 2, β10, 50, β250, 1250, β¦
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Ex 4. Find the common ratio and the nth term of the following geometric sequence. 2, β10, 50, β250, 1250, β¦
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Ex 4. Find the common ratio and the nth term of the following geometric sequence. 2, β10, 50, β250, 1250, β¦
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Ex 4. Find the common ratio and the nth term of the following geometric sequence. 2, β10, 50, β250, 1250, β¦
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Ex 4. Find the common ratio and the nth term of the following geometric sequence. 2, β10, 50, β250, 1250, β¦
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Subtract the equations to get: π π βπ π π =πβπ π π π π 1βπ =π(1β π π )
We can find the partial sums of a geometric sequence with another slick trick: π π =π+ππ+π π 2 +π π 3 +π π 4 +β¦+π π πβ1 π π π = ππ+π π 2 +π π 3 +π π 4 +β¦+π π πβ1 +π π π Subtract the equations to get: π π βπ π π =πβπ π π π π 1βπ =π(1β π π ) πΊ π = π πβ π π πβπ
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Subtract the equations to get: π π βπ π π =πβπ π π π π 1βπ =π(1β π π )
We can find the partial sums of a geometric sequence with another slick trick: π π =π+ππ+π π 2 +π π 3 +π π 4 +β¦+π π πβ1 π π π = ππ+π π 2 +π π 3 +π π 4 +β¦+π π πβ1 +π π π Subtract the equations to get: π π βπ π π =πβπ π π π π 1βπ =π(1β π π ) πΊ π = π πβ π π πβπ
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Subtract the equations to get: π π βπ π π =πβπ π π π π 1βπ =π(1β π π )
We can find the partial sums of a geometric sequence with another slick trick: π π =π+ππ+π π 2 +π π 3 +π π 4 +β¦+π π πβ1 π π π = ππ+π π 2 +π π 3 +π π 4 +β¦+π π πβ1 +π π π Subtract the equations to get: π π βπ π π =πβπ π π π π 1βπ =π(1β π π ) πΊ π = π πβ π π πβπ
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Subtract the equations to get: π π βπ π π =πβπ π π π π 1βπ =π(1β π π )
We can find the partial sums of a geometric sequence with another slick trick: π π =π+ππ+π π 2 +π π 3 +π π 4 +β¦+π π πβ1 π π π = ππ+π π 2 +π π 3 +π π 4 +β¦+π π πβ1 +π π π Subtract the equations to get: π π βπ π π =πβπ π π π π 1βπ =π(1β π π ) πΊ π = π πβ π π πβπ
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Subtract the equations to get: π π βπ π π =πβπ π π π π 1βπ =π(1β π π )
We can find the partial sums of a geometric sequence with another slick trick: π π =π+ππ+π π 2 +π π 3 +π π 4 +β¦+π π πβ1 π π π = ππ+π π 2 +π π 3 +π π 4 +β¦+π π πβ1 +π π π Subtract the equations to get: π π βπ π π =πβπ π π π π 1βπ =π(1β π π ) πΊ π = π πβ π π πβπ
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Subtract the equations to get: π π βπ π π =πβπ π π π π 1βπ =π(1β π π )
We can find the partial sums of a geometric sequence with another slick trick: π π =π+ππ+π π 2 +π π 3 +π π 4 +β¦+π π πβ1 π π π = ππ+π π 2 +π π 3 +π π 4 +β¦+π π πβ1 +π π π Subtract the equations to get: π π βπ π π =πβπ π π π π 1βπ =π(1β π π ) πΊ π = π πβ π π πβπ
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Ex 5. Find the sum: 4β β β¦β
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Ex 5. Find the sum: 4β β β¦β
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Ex 5. Find the sum: 4β β β¦β
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Notice that the sum of the first π terms of the previous example is π π = 4β
1β β 1 3 π 1β β What happens as we add more and more (and more!) terms? In other words, what happens as πββ?
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Notice that the sum of the first π terms of the previous example is π π = 4β
1β β 1 3 π 1β β What happens as we add more and more (and more!) terms? In other words, what happens as πββ?
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Notice that the sum of the first π terms of the previous example is π π = 4β
1β β 1 3 π 1β β What happens as we add more and more (and more!) terms? In other words, what happens as πββ?
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Well, β 1 3 π β0, so π π β 4β
1β0 1β β 1 3 = So, the infinite number of terms add up to 3 4 ! 1β β β¦ is an example of an infinite series.
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Well, β 1 3 π β0, so π π β 4β
1β0 1β β 1 3 =3. So, the infinite number of terms add up to 3 4 ! 1β β β¦ is an example of an infinite series.
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Well, β 1 3 π β0, so π π β 4β
1β0 1β β 1 3 =3. So, the infinite number of terms add up to 3! 1β β β¦ is an example of an infinite series.
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Well, β 1 3 π β0, so π π β 4β
1β0 1β β 1 3 =3. So, the infinite number of terms add up to 3! 4β β β¦ is an example of an infinite series.
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To the right is a visual picture of the infinite geometric series 1 2 + 1 4 + 1 8 + 1 16 + 1 32 +β¦
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In general, if β1<π<1, then as πββ, π π β0, so π π = π 1β π π 1βπ β π 1βπ . In this case, we say that the infinite series converges to π 1βπ . However, if πβ₯1 or πβ€β1, then the infinite series diverges.
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In general, if β1<π<1, then as πββ, π π β0, so π π = π 1β π π 1βπ β π 1βπ . In this case, we say that the infinite series converges to π 1βπ . However, if πβ₯1 or πβ€β1, then the infinite series diverges.
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Ex 6. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum β¦
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Ex 6. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum β¦
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Ex 6. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum β¦
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Ex 7. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum β¦
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Ex 7. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum β¦
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Ex 7. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum β¦
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Ex 7. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum β¦
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