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Packet #29 Arithmetic and Geometric Sequences

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2 Packet #29 Arithmetic and Geometric Sequences
Math 160 Packet #29 Arithmetic and Geometric Sequences

3 An arithmetic sequence is a sequence of the form: π‘Ž, π‘Ž+𝑑, π‘Ž+2𝑑, π‘Ž+3𝑑, … π‘Ž is the first term, and 𝑑 is the common difference. The 𝒏th term is given by π‘Ž 𝑛 = ______________

4 An arithmetic sequence is a sequence of the form: π‘Ž, π‘Ž+𝑑, π‘Ž+2𝑑, π‘Ž+3𝑑, … π‘Ž is the first term, and 𝑑 is the common difference. The 𝒏th term is given by π‘Ž 𝑛 = ______________

5 An arithmetic sequence is a sequence of the form: π‘Ž, π‘Ž+𝑑, π‘Ž+2𝑑, π‘Ž+3𝑑, … π‘Ž is the first term, and 𝑑 is the common difference. The 𝒏th term is given by π‘Ž 𝑛 = ______________

6 An arithmetic sequence is a sequence of the form: π‘Ž, π‘Ž+𝑑, π‘Ž+2𝑑, π‘Ž+3𝑑, … π‘Ž is the first term, and 𝑑 is the common difference. The 𝒏th term is given by π‘Ž 𝑛 = ______________ 𝒂+ π’βˆ’πŸ 𝒅

7 Ex 1. Find the common difference and the 100th term of the following arithmetic sequence. 11, 6, 1, βˆ’4, βˆ’9, …

8 Ex 1. Find the common difference and the 100th term of the following arithmetic sequence. 11, 6, 1, βˆ’4, βˆ’9, …

9 Ex 1. Find the common difference and the 100th term of the following arithmetic sequence. 11, 6, 1, βˆ’4, βˆ’9, …

10 Ex 1. Find the common difference and the 100th term of the following arithmetic sequence. 11, 6, 1, βˆ’4, βˆ’9, …

11 Ex 1. Find the common difference and the 100th term of the following arithmetic sequence. 11, 6, 1, βˆ’4, βˆ’9, …

12 Ex 2. The 6th term of an arithmetic sequence is 10, and the 13th term is 31. Find the 𝑛th term and the 50th term.

13 Here’s a slick way to find the sum of the first 100 numbers:
𝑆 100 = … 𝑆 100 = …

14 Here’s a slick way to find the sum of the first 100 numbers:
𝑆 100 = … 𝑆 100 = …

15 Here’s a slick way to find the sum of the first 100 numbers:
𝑆 100 = … 𝑆 100 = …

16 Here’s a slick way to find the sum of the first 100 numbers:
𝑆 100 = … 𝑆 100 = …

17 Here’s a slick way to find the sum of the first 100 numbers:
𝑆 100 = … 𝑆 100 = …

18 Here’s a slick way to find the sum of the first 100 numbers:
𝑆 100 = … 𝑆 100 = …

19 Here’s a slick way to find the sum of the first 100 numbers:
𝑆 100 = … 𝑆 100 = …

20 Here’s a slick way to find the sum of the first 100 numbers:
𝑆 100 = … 𝑆 100 = …

21 Here’s a slick way to find the sum of the first 100 numbers:
𝑆 100 = … 𝑆 100 = …

22 Here’s a slick way to find the sum of the first 100 numbers:
𝑆 100 = … 𝑆 100 = …

23 This works for all arithmetic sequences, so that the sum of the first 𝑛 terms ( 𝑆 𝑛 ) is: 𝑺 𝒏 = 𝒂 𝟏 + 𝒂 𝒏 ⋅𝒏 𝟐 Ex 4. Find the sum: …+159

24 This works for all arithmetic sequences, so that the sum of the first 𝑛 terms ( 𝑆 𝑛 ) is: 𝑺 𝒏 = 𝒂 𝟏 + 𝒂 𝒏 ⋅𝒏 𝟐 Ex 3. Find the sum: …+159

25 This works for all arithmetic sequences, so that the sum of the first 𝑛 terms ( 𝑆 𝑛 ) is: 𝑺 𝒏 = 𝒂 𝟏 + 𝒂 𝒏 ⋅𝒏 𝟐 Ex 3. Find the sum: …+159

26 This works for all arithmetic sequences, so that the sum of the first 𝑛 terms ( 𝑆 𝑛 ) is: 𝑺 𝒏 = 𝒂 𝟏 + 𝒂 𝒏 ⋅𝒏 𝟐 Ex 3. Find the sum: …+159

27 This works for all arithmetic sequences, so that the sum of the first 𝑛 terms ( 𝑆 𝑛 ) is: 𝑺 𝒏 = 𝒂 𝟏 + 𝒂 𝒏 ⋅𝒏 𝟐 Ex 3. Find the sum: …+159

28 A geometric sequence is a sequence of the form: π‘Ž, π‘Žπ‘Ÿ, π‘Ž π‘Ÿ 2 , π‘Ž π‘Ÿ 3 , π‘Ž π‘Ÿ 4 , … π‘Ž is the first term, and π‘Ÿ is the common ratio. The 𝑛th term is given by π‘Ž 𝑛 = _________

29 A geometric sequence is a sequence of the form: π‘Ž, π‘Žπ‘Ÿ, π‘Ž π‘Ÿ 2 , π‘Ž π‘Ÿ 3 , π‘Ž π‘Ÿ 4 , … π‘Ž is the first term, and π‘Ÿ is the common ratio. The 𝑛th term is given by π‘Ž 𝑛 = _________

30 A geometric sequence is a sequence of the form: π‘Ž, π‘Žπ‘Ÿ, π‘Ž π‘Ÿ 2 , π‘Ž π‘Ÿ 3 , π‘Ž π‘Ÿ 4 , … π‘Ž is the first term, and π‘Ÿ is the common ratio. The 𝑛th term is given by π‘Ž 𝑛 = _________

31 A geometric sequence is a sequence of the form: π‘Ž, π‘Žπ‘Ÿ, π‘Ž π‘Ÿ 2 , π‘Ž π‘Ÿ 3 , π‘Ž π‘Ÿ 4 , … π‘Ž is the first term, and π‘Ÿ is the common ratio. The 𝑛th term is given by π‘Ž 𝑛 = _________ 𝒂 𝒓 π’βˆ’πŸ

32 Ex 4. Find the common ratio and the nth term of the following geometric sequence. 2, βˆ’10, 50, βˆ’250, 1250, …

33 Ex 4. Find the common ratio and the nth term of the following geometric sequence. 2, βˆ’10, 50, βˆ’250, 1250, …

34 Ex 4. Find the common ratio and the nth term of the following geometric sequence. 2, βˆ’10, 50, βˆ’250, 1250, …

35 Ex 4. Find the common ratio and the nth term of the following geometric sequence. 2, βˆ’10, 50, βˆ’250, 1250, …

36 Ex 4. Find the common ratio and the nth term of the following geometric sequence. 2, βˆ’10, 50, βˆ’250, 1250, …

37 Subtract the equations to get: 𝑆 𝑛 βˆ’π‘Ÿ 𝑆 𝑛 =π‘Žβˆ’π‘Ž π‘Ÿ 𝑛 𝑆 𝑛 1βˆ’π‘Ÿ =π‘Ž(1βˆ’ π‘Ÿ 𝑛 )
We can find the partial sums of a geometric sequence with another slick trick: 𝑆 𝑛 =π‘Ž+π‘Žπ‘Ÿ+π‘Ž π‘Ÿ 2 +π‘Ž π‘Ÿ 3 +π‘Ž π‘Ÿ 4 +…+π‘Ž π‘Ÿ π‘›βˆ’1 π‘Ÿ 𝑆 𝑛 = π‘Žπ‘Ÿ+π‘Ž π‘Ÿ 2 +π‘Ž π‘Ÿ 3 +π‘Ž π‘Ÿ 4 +…+π‘Ž π‘Ÿ π‘›βˆ’1 +π‘Ž π‘Ÿ 𝑛 Subtract the equations to get: 𝑆 𝑛 βˆ’π‘Ÿ 𝑆 𝑛 =π‘Žβˆ’π‘Ž π‘Ÿ 𝑛 𝑆 𝑛 1βˆ’π‘Ÿ =π‘Ž(1βˆ’ π‘Ÿ 𝑛 ) 𝑺 𝒏 = 𝒂 πŸβˆ’ 𝒓 𝒏 πŸβˆ’π’“

38 Subtract the equations to get: 𝑆 𝑛 βˆ’π‘Ÿ 𝑆 𝑛 =π‘Žβˆ’π‘Ž π‘Ÿ 𝑛 𝑆 𝑛 1βˆ’π‘Ÿ =π‘Ž(1βˆ’ π‘Ÿ 𝑛 )
We can find the partial sums of a geometric sequence with another slick trick: 𝑆 𝑛 =π‘Ž+π‘Žπ‘Ÿ+π‘Ž π‘Ÿ 2 +π‘Ž π‘Ÿ 3 +π‘Ž π‘Ÿ 4 +…+π‘Ž π‘Ÿ π‘›βˆ’1 π‘Ÿ 𝑆 𝑛 = π‘Žπ‘Ÿ+π‘Ž π‘Ÿ 2 +π‘Ž π‘Ÿ 3 +π‘Ž π‘Ÿ 4 +…+π‘Ž π‘Ÿ π‘›βˆ’1 +π‘Ž π‘Ÿ 𝑛 Subtract the equations to get: 𝑆 𝑛 βˆ’π‘Ÿ 𝑆 𝑛 =π‘Žβˆ’π‘Ž π‘Ÿ 𝑛 𝑆 𝑛 1βˆ’π‘Ÿ =π‘Ž(1βˆ’ π‘Ÿ 𝑛 ) 𝑺 𝒏 = 𝒂 πŸβˆ’ 𝒓 𝒏 πŸβˆ’π’“

39 Subtract the equations to get: 𝑆 𝑛 βˆ’π‘Ÿ 𝑆 𝑛 =π‘Žβˆ’π‘Ž π‘Ÿ 𝑛 𝑆 𝑛 1βˆ’π‘Ÿ =π‘Ž(1βˆ’ π‘Ÿ 𝑛 )
We can find the partial sums of a geometric sequence with another slick trick: 𝑆 𝑛 =π‘Ž+π‘Žπ‘Ÿ+π‘Ž π‘Ÿ 2 +π‘Ž π‘Ÿ 3 +π‘Ž π‘Ÿ 4 +…+π‘Ž π‘Ÿ π‘›βˆ’1 π‘Ÿ 𝑆 𝑛 = π‘Žπ‘Ÿ+π‘Ž π‘Ÿ 2 +π‘Ž π‘Ÿ 3 +π‘Ž π‘Ÿ 4 +…+π‘Ž π‘Ÿ π‘›βˆ’1 +π‘Ž π‘Ÿ 𝑛 Subtract the equations to get: 𝑆 𝑛 βˆ’π‘Ÿ 𝑆 𝑛 =π‘Žβˆ’π‘Ž π‘Ÿ 𝑛 𝑆 𝑛 1βˆ’π‘Ÿ =π‘Ž(1βˆ’ π‘Ÿ 𝑛 ) 𝑺 𝒏 = 𝒂 πŸβˆ’ 𝒓 𝒏 πŸβˆ’π’“

40 Subtract the equations to get: 𝑆 𝑛 βˆ’π‘Ÿ 𝑆 𝑛 =π‘Žβˆ’π‘Ž π‘Ÿ 𝑛 𝑆 𝑛 1βˆ’π‘Ÿ =π‘Ž(1βˆ’ π‘Ÿ 𝑛 )
We can find the partial sums of a geometric sequence with another slick trick: 𝑆 𝑛 =π‘Ž+π‘Žπ‘Ÿ+π‘Ž π‘Ÿ 2 +π‘Ž π‘Ÿ 3 +π‘Ž π‘Ÿ 4 +…+π‘Ž π‘Ÿ π‘›βˆ’1 π‘Ÿ 𝑆 𝑛 = π‘Žπ‘Ÿ+π‘Ž π‘Ÿ 2 +π‘Ž π‘Ÿ 3 +π‘Ž π‘Ÿ 4 +…+π‘Ž π‘Ÿ π‘›βˆ’1 +π‘Ž π‘Ÿ 𝑛 Subtract the equations to get: 𝑆 𝑛 βˆ’π‘Ÿ 𝑆 𝑛 =π‘Žβˆ’π‘Ž π‘Ÿ 𝑛 𝑆 𝑛 1βˆ’π‘Ÿ =π‘Ž(1βˆ’ π‘Ÿ 𝑛 ) 𝑺 𝒏 = 𝒂 πŸβˆ’ 𝒓 𝒏 πŸβˆ’π’“

41 Subtract the equations to get: 𝑆 𝑛 βˆ’π‘Ÿ 𝑆 𝑛 =π‘Žβˆ’π‘Ž π‘Ÿ 𝑛 𝑆 𝑛 1βˆ’π‘Ÿ =π‘Ž(1βˆ’ π‘Ÿ 𝑛 )
We can find the partial sums of a geometric sequence with another slick trick: 𝑆 𝑛 =π‘Ž+π‘Žπ‘Ÿ+π‘Ž π‘Ÿ 2 +π‘Ž π‘Ÿ 3 +π‘Ž π‘Ÿ 4 +…+π‘Ž π‘Ÿ π‘›βˆ’1 π‘Ÿ 𝑆 𝑛 = π‘Žπ‘Ÿ+π‘Ž π‘Ÿ 2 +π‘Ž π‘Ÿ 3 +π‘Ž π‘Ÿ 4 +…+π‘Ž π‘Ÿ π‘›βˆ’1 +π‘Ž π‘Ÿ 𝑛 Subtract the equations to get: 𝑆 𝑛 βˆ’π‘Ÿ 𝑆 𝑛 =π‘Žβˆ’π‘Ž π‘Ÿ 𝑛 𝑆 𝑛 1βˆ’π‘Ÿ =π‘Ž(1βˆ’ π‘Ÿ 𝑛 ) 𝑺 𝒏 = 𝒂 πŸβˆ’ 𝒓 𝒏 πŸβˆ’π’“

42 Subtract the equations to get: 𝑆 𝑛 βˆ’π‘Ÿ 𝑆 𝑛 =π‘Žβˆ’π‘Ž π‘Ÿ 𝑛 𝑆 𝑛 1βˆ’π‘Ÿ =π‘Ž(1βˆ’ π‘Ÿ 𝑛 )
We can find the partial sums of a geometric sequence with another slick trick: 𝑆 𝑛 =π‘Ž+π‘Žπ‘Ÿ+π‘Ž π‘Ÿ 2 +π‘Ž π‘Ÿ 3 +π‘Ž π‘Ÿ 4 +…+π‘Ž π‘Ÿ π‘›βˆ’1 π‘Ÿ 𝑆 𝑛 = π‘Žπ‘Ÿ+π‘Ž π‘Ÿ 2 +π‘Ž π‘Ÿ 3 +π‘Ž π‘Ÿ 4 +…+π‘Ž π‘Ÿ π‘›βˆ’1 +π‘Ž π‘Ÿ 𝑛 Subtract the equations to get: 𝑆 𝑛 βˆ’π‘Ÿ 𝑆 𝑛 =π‘Žβˆ’π‘Ž π‘Ÿ 𝑛 𝑆 𝑛 1βˆ’π‘Ÿ =π‘Ž(1βˆ’ π‘Ÿ 𝑛 ) 𝑺 𝒏 = 𝒂 πŸβˆ’ 𝒓 𝒏 πŸβˆ’π’“

43 Ex 5. Find the sum: 4βˆ’ βˆ’ β€¦βˆ’

44 Ex 5. Find the sum: 4βˆ’ βˆ’ β€¦βˆ’

45 Ex 5. Find the sum: 4βˆ’ βˆ’ β€¦βˆ’

46 Notice that the sum of the first 𝑛 terms of the previous example is 𝑆 𝑛 = 4β‹… 1βˆ’ βˆ’ 1 3 𝑛 1βˆ’ βˆ’ What happens as we add more and more (and more!) terms? In other words, what happens as π‘›β†’βˆž?

47 Notice that the sum of the first 𝑛 terms of the previous example is 𝑆 𝑛 = 4β‹… 1βˆ’ βˆ’ 1 3 𝑛 1βˆ’ βˆ’ What happens as we add more and more (and more!) terms? In other words, what happens as π‘›β†’βˆž?

48 Notice that the sum of the first 𝑛 terms of the previous example is 𝑆 𝑛 = 4β‹… 1βˆ’ βˆ’ 1 3 𝑛 1βˆ’ βˆ’ What happens as we add more and more (and more!) terms? In other words, what happens as π‘›β†’βˆž?

49 Well, βˆ’ 1 3 𝑛 β†’0, so 𝑆 𝑛 β†’ 4β‹… 1βˆ’0 1βˆ’ βˆ’ 1 3 = So, the infinite number of terms add up to 3 4 ! 1βˆ’ βˆ’ … is an example of an infinite series.

50 Well, βˆ’ 1 3 𝑛 β†’0, so 𝑆 𝑛 β†’ 4β‹… 1βˆ’0 1βˆ’ βˆ’ 1 3 =3. So, the infinite number of terms add up to 3 4 ! 1βˆ’ βˆ’ … is an example of an infinite series.

51 Well, βˆ’ 1 3 𝑛 β†’0, so 𝑆 𝑛 β†’ 4β‹… 1βˆ’0 1βˆ’ βˆ’ 1 3 =3. So, the infinite number of terms add up to 3! 1βˆ’ βˆ’ … is an example of an infinite series.

52 Well, βˆ’ 1 3 𝑛 β†’0, so 𝑆 𝑛 β†’ 4β‹… 1βˆ’0 1βˆ’ βˆ’ 1 3 =3. So, the infinite number of terms add up to 3! 4βˆ’ βˆ’ … is an example of an infinite series.

53 To the right is a visual picture of the infinite geometric series 1 2 + 1 4 + 1 8 + 1 16 + 1 32 +…

54 In general, if βˆ’1<π‘Ÿ<1, then as π‘›β†’βˆž, π‘Ÿ 𝑛 β†’0, so 𝑆 𝑛 = π‘Ž 1βˆ’ π‘Ÿ 𝑛 1βˆ’π‘Ÿ β†’ π‘Ž 1βˆ’π‘Ÿ . In this case, we say that the infinite series converges to π‘Ž 1βˆ’π‘Ÿ . However, if π‘Ÿβ‰₯1 or π‘Ÿβ‰€βˆ’1, then the infinite series diverges.

55 In general, if βˆ’1<π‘Ÿ<1, then as π‘›β†’βˆž, π‘Ÿ 𝑛 β†’0, so 𝑆 𝑛 = π‘Ž 1βˆ’ π‘Ÿ 𝑛 1βˆ’π‘Ÿ β†’ π‘Ž 1βˆ’π‘Ÿ . In this case, we say that the infinite series converges to π‘Ž 1βˆ’π‘Ÿ . However, if π‘Ÿβ‰₯1 or π‘Ÿβ‰€βˆ’1, then the infinite series diverges.

56 Ex 6. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum …

57 Ex 6. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum …

58 Ex 6. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum …

59 Ex 7. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum …

60 Ex 7. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum …

61 Ex 7. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum …

62 Ex 7. Determine whether the infinite geometric series converges or diverges. If it converges, find its sum …


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