1. Overview on multiplying binomials by foiling

2. First Look at the problem
(2+3) (4-2)
Remember the rules for multiplying negatives.
Multiplying a positive and negative = negative
Multiplying a negative and negative= positive
Multiplying a positive and positive = positive

3. Foiling
F: First = multiply the two beginning numbers in each parenthesis with each other. O: Outer = multiply the first number in the first set of parenthesis with the last number in the last set. The outer numbers. I: Inner = Multiply the second number in the first set on parenthesis with the first number in the second set. The inner numbers. L: Last = Multiply the last numbers in both sets of parenthesis with each other.

4. (2+3) (4-2) Multiply the first 2 numbers so 2x4=8.
F: First
(2+3) (4-2) Multiply the first 2 numbers so 2x4=8.

5. (2+3) (4-2) Multiply the two outer numbers 2x-2=-4 So far we have 8-4

6. (2+3) (4-2) I: inner Multiply the two inner numbers 3x4=12
Since this is a positive 12, we put it in as a +12.
So far we have

7. (2+3) (4-2) L: Last Multiply the two last numbers together 3x-2=-6
So to finish our answer it would be:
Then answer straight across and you should get: 10

8. By: Mrs. Thompson