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Published byเธชเธฒเธขเธชเธกเธฃ เธเธฑเนเธเธเธฃเธฐเธเธนเธฅ Modified over 5 years ago
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Warm up honors algebra 2 3/7/19
Find the inverse function: 1. ๐ฆ=2๐ฅ ๐ฆ=3 ln ๐ฅ+1 2. ๐ ๐ฅ =2 ๐ฅ ๐ ๐ฅ =4 5 ๐ฅ
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Find the inverse function
๐ ๐ฅ = ๐ฅ ๐ฅ= ๐ฆ ๐ฅ 5 = ๐ฆ ๐๐๐ ๐ฅ 5 =๐ฆ= ๐ โ1 (๐ฅ)
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Which equations are true for all values of x? Select all that apply.
B) ( 3 ๐ฅ ) 2 = (3 2 ) ๐ฅ C) 27 ๐ฅ = ( 3 ๐ฅ ) 3 D) 3 ๐ฅ+2 =9( 3 ๐ฅ ) E) 9 ๐ฅ+2 = 3 2๐ฅ+4
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Same exponential bases
What happens if exponential terms have the same bases? 2 (2๐ฅ) = 2 (๐ฅ+4) 2๐ฅ=๐ฅ+4 ๐ฅ=4
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Solve 8 ๐ฅ = 2 ๐ฅ+6 8 ๐ฅ ๏ (2 3 ) ๐ฅ ๏ 2 3๐ฅ 2 3๐ฅ = 2 ๐ฅ+6 3๐ฅ=๐ฅ+6 2๐ฅ=6 ๐ฅ=3
Rewrite each side so that they have the same base 8 ๐ฅ ๏ (2 3 ) ๐ฅ ๏ 2 3๐ฅ 2 3๐ฅ = 2 ๐ฅ+6 3๐ฅ=๐ฅ+6 2๐ฅ=6 ๐ฅ=3
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16 ๐ฅ ๏ (4 2 ) ๐ฅ ๏ 4 2๐ฅ 4 4๐ฅ+1 =4 2๐ฅ 4๐ฅ+1=2๐ฅ 1=โ2๐ฅ ๐ฅ=โ 1 2
Solve 4 4๐ฅ+1 = 16 ๐ฅ 16 ๐ฅ ๏ (4 2 ) ๐ฅ ๏ 4 2๐ฅ 4 4๐ฅ+1 =4 2๐ฅ 4๐ฅ+1=2๐ฅ 1=โ2๐ฅ ๐ฅ=โ 1 2
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144 2๐ฅ ๏ ( 12 2 ) 2๐ฅ ๏ 12 4๐ฅ 12 4๐ฅ = 12 6๐ฅโ1 4๐ฅ=6๐ฅโ1 โ2๐ฅ=โ1 ๐ฅ= 1 2
Solve ๐ฅ = 12 6๐ฅโ1 144 2๐ฅ ๏ ( 12 2 ) 2๐ฅ ๏ 12 4๐ฅ 12 4๐ฅ = 12 6๐ฅโ1 4๐ฅ=6๐ฅโ1 โ2๐ฅ=โ1 ๐ฅ= 1 2
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25 5๐ฅ ๏ (5 2 ) 5๐ฅ ๏ 5 10๐ฅ 5 ๐ฅ+3 = 5 10๐ฅ ๐ฅ+3=10๐ฅ 3=9๐ฅ ๐ฅ=1/3
Solve 5 ๐ฅ+3 = 25 5๐ฅ 25 5๐ฅ ๏ (5 2 ) 5๐ฅ ๏ 5 10๐ฅ 5 ๐ฅ+3 = 5 10๐ฅ ๐ฅ+3=10๐ฅ 3=9๐ฅ ๐ฅ=1/3
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Solve 36 โ3๐ฅ = 6 2๐ฅโ1 36 โ3๐ฅ ๏ (6 2 ) โ3๐ฅ ๏ 6 โ6๐ฅ 6 โ6๐ฅ = 6 2๐ฅโ1
36 โ3๐ฅ ๏ (6 2 ) โ3๐ฅ ๏ 6 โ6๐ฅ 6 โ6๐ฅ = 6 2๐ฅโ1 โ6๐ฅ=2๐ฅโ1 โ8๐ฅ=โ1 ๐ฅ=1/8
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Solve โ49 โ๐ฅ = 7 3๐ฅโ1 โ49 โ๐ฅ ๏ โ( 7 2 ) โ๐ฅ ๏ โ( 7 โ2๐ฅ ) โ(7) โ2๐ฅ = 7 3๐ฅโ1 โ โ2๐ฅ =3๐ฅโ1 2๐ฅ=3๐ฅโ1 โ๐ฅ=โ1 ๐ฅ=1
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A bank pays depositors a 2% interest rate compounded semi-annually
A bank pays depositors a 2% interest rate compounded semi-annually. Let P represent an initial deposit, and t represent the number of years that the deposit is in the bank. The expression ๐ ๐ก can be used to determine the account balance after t years. Which expression accurately reflects the annual interest rate? A) ๐ ๐ก B) ๐ ๐ก C) ๐ ๐ก D) ๐ ๐ก
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Solve for n ๐ =4.305 ๐ =0.316 ๐ =14,521 ๐ = log =๐ log =๐ log 14,521 =๐ log =๐ ๐=.634 ๐=โ.5003 ๐=4.162 ๐=2.684
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