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Gradient of a line Recap

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Presentation on theme: "Gradient of a line Recap"β€” Presentation transcript:

1 Gradient of a line Recap
Gradient is a measure of steepness. The gradient of this line is 1. Gradient = Δ𝑦 Ξ”π‘₯

2 What is the gradient of this line?
How do you know?

3 What is the gradient of this line?
How do you know?

4 What is the gradient of this line?
How do you know?

5 What is the gradient of this line?
How do you know?

6 What is the gradient of this line?
How do you know?

7 x : y = 2 : 1 (a) Draw the graph of y as a function of x.
(b) Write down the equation of your graph. A table of values can help draw a graph Complete the table: 𝒙 1 2 3 4 π’š Demonstrate The π‘₯ values must be double the 𝑦 values. The 𝑦 values must be half of the π‘₯ values.

8 x : y = 2 : 1 (a) Draw the graph of y as a function of x.
(b) Write down the equation of your graph. 𝒙 1 2 3 4 π’š 0.5 1.5 Demonstrate

9 Remember a table of values represents a set of coordinates.
𝒙 2 4 π’š 1 (0,0) (2,1) (4,2) Remember a table of values represents a set of coordinates.

10 x : y = 2 : 1 (a) Draw the graph of y as a function of x.
(b) Write down the equation of your graph. The y-intercept is 0. Let’s calculate the gradient of the line…

11 x : y = 2 : 1 (a) Draw the graph of y as a function of x.
(b) Write down the equation of your graph. Gradient = Δ𝑦 Ξ”π‘₯ Gradient = 3 6 Gradient = 2 4 Gradient = 1 2

12 So the equation of the graph is…
x : y = 2 : 1 (a) Draw the graph of y as a function of x. (b) Write down the equation of your graph. The y-intercept is 0. The gradient is 1 2 So the equation of the graph is… 𝑦= 1 2 π‘₯ 𝑦=π‘šπ‘₯+𝑐 𝑦= 1 2 π‘₯+0

13 Your turn. On your whiteboards..
x : y = 1 : 2 (a) Draw the graph of y as a function of x. (b) Write down the equation of your graph.

14 x : y = 1 : 2 (a) Draw the graph of y as a function of x.
(b) Write down the equation of your graph. Your table of values could look like this… 𝒙 1 2 3 π’š Possible Scaffolding

15 𝒙 1 2 3 π’š 4 6 𝑦=2π‘₯ Answer

16 In your books… π‘₯ :𝑦=1:4 π‘₯ :𝑦=2:4 π‘₯ :𝑦=3:4 π‘₯ :𝑦=4:4 π‘₯:𝑦=1:5
Draw the graph of 𝑦 as a function of π‘₯ for each ratio π‘₯ :𝑦=1:4 π‘₯ :𝑦=2:4 π‘₯ :𝑦=3:4 π‘₯ :𝑦=4:4 π‘₯:𝑦=1:5 Work out the equation for each of your graphs.

17 If you are stuck this table could help you start:
Draw the graph of 𝑦 as a function of π‘₯ for each ratio π‘₯ :𝑦=1:4 𝒙 1 2 3 π’š 4

18 Mark your work.. π‘₯:𝑦=1:4 βŸΉπ‘¦= 4 1 π‘₯ π‘₯ :𝑦=2:4 ⟹ 𝑦= 4 2 π‘₯
π‘₯ :𝑦=2:4 ⟹ 𝑦= 4 2 π‘₯ π‘₯ :𝑦=3:4 βŸΉπ‘¦= 4 3 π‘₯ π‘₯ :𝑦=4:4 ⟹ 𝑦= 4 4 π‘₯ π‘₯:𝑦=1:5βŸΉπ‘¦= 5 1 π‘₯

19 More consolidation… π‘₯ :𝑦=1:3 π‘₯ :𝑦=3:1 π‘₯ :𝑦=2:3 π‘₯ :𝑦=3:2
Draw the graph of 𝑦 as a function of π‘₯ for each ratio π‘₯ :𝑦=1:3 π‘₯ :𝑦=3:1 π‘₯ :𝑦=2:3 π‘₯ :𝑦=3:2 Work out the equation for each of your graphs. y = 3x y = 1/3x y = 3/2x y = 2/3x

20 Any three coordinates…
Mark your work π‘₯ :𝑦=1:3 Any three coordinates… 𝒙 1 2 3 π’š 6 9 y = 3x y = 1/3x y = 3/2x y = 2/3x 𝑦=3π‘₯

21 (b) π‘₯ :𝑦=3:1 Any three coordinates…
Mark your work (b) π‘₯ :𝑦=3:1 Any three coordinates… 𝒙 1 2 3 4 5 6 π’š 𝟏 πŸ‘ 𝟐 πŸ‘ πŸ’ πŸ‘ πŸ“ πŸ‘ y = 3x y = 1/3x y = 3/2x y = 2/3x 𝑦= 1 3 π‘₯

22 𝑐 π‘₯ :𝑦=2:3 Any three coordinates…
Mark your work 𝑐 π‘₯ :𝑦=2:3 Any three coordinates… 𝒙 1 2 3 4 5 6 π’š 1.5 4.5 7.5 9 y = 3/2x y = 2/3x 𝑦= 3 2 π‘₯

23 𝑑 π‘₯ :𝑦=3:2 Any three coordinates…
Mark your work 𝑑 π‘₯ :𝑦=3:2 Any three coordinates… 𝒙 1 2 3 4 5 6 π’š 𝟐 πŸ‘ πŸ’ πŸ‘ πŸ– πŸ‘ 𝟏𝟎 πŸ‘ y = 3/2x y = 2/3x 𝑦= 2 3 π‘₯

24 Challenge The line 𝑦= 2 5 π‘₯ passes through the point with coordinates (π‘Ž,𝑏) where π‘Ž,𝑏 β‰ 0 Write down the ratio π‘Ž:𝑏 in its simplest form

25 In general 𝐼𝑓 π‘₯:𝑦=π‘Ž:𝑏 Write as many different possible linear equations as you can.

26 In general 𝐼𝑓 π‘₯:𝑦=π‘Ž:𝑏 𝑦= 𝑏 π‘Ž π‘₯ π‘₯ 𝑦 = π‘Ž 𝑏 𝑏π‘₯=π‘Žπ‘¦ π‘₯= π‘Ž 𝑏 𝑦 𝑦 π‘₯ = 𝑏 π‘Ž
There are more… π‘₯= π‘Ž 𝑏 𝑦 𝑦 π‘₯ = 𝑏 π‘Ž


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