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Gradient of a line Recap
Gradient is a measure of steepness. The gradient of this line is 1. Gradient = Ξπ¦ Ξπ₯
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What is the gradient of this line?
How do you know?
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What is the gradient of this line?
How do you know?
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What is the gradient of this line?
How do you know?
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What is the gradient of this line?
How do you know?
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What is the gradient of this line?
How do you know?
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x : y = 2 : 1 (a) Draw the graph of y as a function of x.
(b) Write down the equation of your graph. A table of values can help draw a graph Complete the table: π 1 2 3 4 π Demonstrate The π₯ values must be double the π¦ values. The π¦ values must be half of the π₯ values.
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x : y = 2 : 1 (a) Draw the graph of y as a function of x.
(b) Write down the equation of your graph. π 1 2 3 4 π 0.5 1.5 Demonstrate
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Remember a table of values represents a set of coordinates.
π 2 4 π 1 (0,0) (2,1) (4,2) Remember a table of values represents a set of coordinates.
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x : y = 2 : 1 (a) Draw the graph of y as a function of x.
(b) Write down the equation of your graph. The y-intercept is 0. Letβs calculate the gradient of the lineβ¦
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x : y = 2 : 1 (a) Draw the graph of y as a function of x.
(b) Write down the equation of your graph. Gradient = Ξπ¦ Ξπ₯ Gradient = 3 6 Gradient = 2 4 Gradient = 1 2
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So the equation of the graph isβ¦
x : y = 2 : 1 (a) Draw the graph of y as a function of x. (b) Write down the equation of your graph. The y-intercept is 0. The gradient is 1 2 So the equation of the graph isβ¦ π¦= 1 2 π₯ π¦=ππ₯+π π¦= 1 2 π₯+0
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Your turn. On your whiteboards..
x : y = 1 : 2 (a) Draw the graph of y as a function of x. (b) Write down the equation of your graph.
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x : y = 1 : 2 (a) Draw the graph of y as a function of x.
(b) Write down the equation of your graph. Your table of values could look like thisβ¦ π 1 2 3 π Possible Scaffolding
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π 1 2 3 π 4 6 π¦=2π₯ Answer
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In your booksβ¦ π₯ :π¦=1:4 π₯ :π¦=2:4 π₯ :π¦=3:4 π₯ :π¦=4:4 π₯:π¦=1:5
Draw the graph of π¦ as a function of π₯ for each ratio π₯ :π¦=1:4 π₯ :π¦=2:4 π₯ :π¦=3:4 π₯ :π¦=4:4 π₯:π¦=1:5 Work out the equation for each of your graphs.
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If you are stuck this table could help you start:
Draw the graph of π¦ as a function of π₯ for each ratio π₯ :π¦=1:4 π 1 2 3 π 4
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Mark your work.. π₯:π¦=1:4 βΉπ¦= 4 1 π₯ π₯ :π¦=2:4 βΉ π¦= 4 2 π₯
π₯ :π¦=2:4 βΉ π¦= 4 2 π₯ π₯ :π¦=3:4 βΉπ¦= 4 3 π₯ π₯ :π¦=4:4 βΉ π¦= 4 4 π₯ π₯:π¦=1:5βΉπ¦= 5 1 π₯
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More consolidationβ¦ π₯ :π¦=1:3 π₯ :π¦=3:1 π₯ :π¦=2:3 π₯ :π¦=3:2
Draw the graph of π¦ as a function of π₯ for each ratio π₯ :π¦=1:3 π₯ :π¦=3:1 π₯ :π¦=2:3 π₯ :π¦=3:2 Work out the equation for each of your graphs. y = 3x y = 1/3x y = 3/2x y = 2/3x
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Any three coordinatesβ¦
Mark your work π₯ :π¦=1:3 Any three coordinatesβ¦ π 1 2 3 π 6 9 y = 3x y = 1/3x y = 3/2x y = 2/3x π¦=3π₯
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(b) π₯ :π¦=3:1 Any three coordinatesβ¦
Mark your work (b) π₯ :π¦=3:1 Any three coordinatesβ¦ π 1 2 3 4 5 6 π π π π π π π π π y = 3x y = 1/3x y = 3/2x y = 2/3x π¦= 1 3 π₯
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π π₯ :π¦=2:3 Any three coordinatesβ¦
Mark your work π π₯ :π¦=2:3 Any three coordinatesβ¦ π 1 2 3 4 5 6 π 1.5 4.5 7.5 9 y = 3/2x y = 2/3x π¦= 3 2 π₯
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π π₯ :π¦=3:2 Any three coordinatesβ¦
Mark your work π π₯ :π¦=3:2 Any three coordinatesβ¦ π 1 2 3 4 5 6 π π π π π π π ππ π y = 3/2x y = 2/3x π¦= 2 3 π₯
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Challenge The line π¦= 2 5 π₯ passes through the point with coordinates (π,π) where π,π β 0 Write down the ratio π:π in its simplest form
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In general πΌπ π₯:π¦=π:π Write as many different possible linear equations as you can.
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In general πΌπ π₯:π¦=π:π π¦= π π π₯ π₯ π¦ = π π ππ₯=ππ¦ π₯= π π π¦ π¦ π₯ = π π
There are moreβ¦ π₯= π π π¦ π¦ π₯ = π π
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