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Intersection of Straight lines
Objectives To be able to find the intersection Pt of 2 lines To solve simultaneous equations To solve the intersection of a curve and a line To Sketch some specific types of curve You should know how to find the equation of a line (from the previous lesson) 31 May, 2019 INTO Foundation L6 MH
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Find the area of the triangle ABC
How do we do this ?? Find which line is which Solve equations for ABC Find Perpendicular line to BC through A 31 May, 2019 INTO Foundation L6 MH
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Solve for coordinates of A,B,C
Pt A Intersection of y = 2x y = -2x 2y= Add to remove x y= x=(5.5 – 5)/ Subst y into 1. x= 0.25 A = (0.25, 5.5) 31 May, 2019 INTO Foundation L6 MH
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Solve for coordinates of A,B,C
Pt B Intersection of y = x y = -2x 0 = x Subtract to remove y 3.5= x x=3.5/1.25 x= Subst x into (y=-5.6+6) y= 0.40 B = (2.80, 0.40) 31 May, 2019 INTO Foundation L6 MH
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Solve for coordinates of A,B,C
Pt C Intersection of y = x y = 2x 0 = x Subtract to remove y 2.5= x x=2.5/-2.75 x= (~-10/11) Subst x into 1. (y=30/44+2.5) y= (378/99 or 42/11) C = (-10/11, 42/11) 31 May, 2019 INTO Foundation L6 MH
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Found A,B,C A (0.25,0.55) C(-10/11, 43/11) B(2.80,0.40)
Find the line that is perpendicular to BC through the point A 31 May, 2019 INTO Foundation L6 MH
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Find Pt D D y = 4/3x +0.217 Grad BC is -0.75 Grad AD is +4/3 m1m2=-1
AD is y = 4/3x +c through A is 0.55=4/3(1/4)+c => c= 31 May, 2019 INTO Foundation L6 MH
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Find Pt D Pt C Intersection of y = -0.75x + 2.50 1. y = 1.33 + 2.17 2.
To eliminate mult eqn1.x1.33 eqn 2.x0.75 1.33y = x 0.75y = x 2.08y = y= /2.08 = Subst into 2. x = (0.75(2.08) )/ = D= (0.157, 2.38) 31 May, 2019 INTO Foundation L6 MH
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Now Find Pt D Area For a triangle this is ½ x base x Perpendicular height So ½ x BC x AD C = (-10/11, 42/11) B(2.80,0.40) D= (0.157, 2.38) Length of BC is [(-10/11-2.8)2 + (42/ )2]1/2 = 5.04 Length of AD is [( )2 + ( )2] = 3.12 So Area is 0.50 x 5.04 x 3.12 = 7.9m2 (1 dec pl) A ≡ (0.25, 5.5) 31 May, 2019 INTO Foundation L6 MH
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Exercises Do worksheet If you finish do the following
Plot on graph paper on the same graph the curves : y = x2 y = x3 y = 1/x y = 1/x2 y = x4 31 May, 2019 INTO Foundation L6 MH
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