1. #5 of 11-6 LIMITING REAGENT SET
INTRODUCTION OF ICE BOX STOICHIOMETRY SOLUTION TABLES.
ICE BOX SOLUTION TABLES:
ARE THE MOST EFFICIENT TO SOLVE FOR EVERYTHING
WHAT IS EVERYTHING?
REAGENTS LEFT OVER (UNCONSUMED)
PRODUCT YIELD
REACTANTS CONSUMED TO 0.0 MOLES.
5) Sulfur and oxygen react in a combination reaction to produce sulfur trioxide, an environmental 5)
pollutant:
2S (s) + 3O2 (g)  2SO3 (g)
In a particular experiment, the reaction of 1.0 g S with 1.0 g O2 produced 0.80 g of SO3. Calculate the amount of excess reagent that remains not having reacted (in excess).

2. Defining X
X is defined by the LIMMITING REAGENT. Divide the moles of the limiting reagent by the coefficient of the balanced reaction. In this example oxygen is the limiting reagent, therefore X = mol
X = mole 2S
3O 
2SO3
mol
mol
0.0
-2 X
-3 X
+2 X
mol -2x
2 ( ) =
mol -2x : mol - 2 ( mol)
mol -( ) = mol S remains