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Copyright ©2014 Pearson Education, All Rights Reserved
Chapter Objectives Determine stresses developed in thin-walled pressure vessels Determine stresses developed in a member’s cross section when axial load, torsion, bending and shear occur simultaneously. Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
In-class Activities Thin-Walled Pressure Vessels Review of Stress Analyses Copyright ©2014 Pearson Education, All Rights Reserved
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THIN-WALLED PRESSURE VESSELS
Assumptions: Inner-radius-to-wall-thickness ratio ≥ 10 Stress distribution in thin wall is uniform or constant Cylindrical vessels: Copyright ©2014 Pearson Education, All Rights Reserved
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THIN-WALLED PRESSURE VESSELS (cont)
Spherical vessels: Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 1 A cylindrical pressure vessel has an inner diameter of 1.2 m and a thickness of 12 mm. Determine the maximum internal pressure it can sustain so that neither its circumferential nor its longitudinal stress component exceeds 140 MPa. Under the same conditions, what is the maximum internal pressure that a similar-size spherical vessel can sustain? Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 1 (cont) Solutions The maximum stress occurs in the circumferential direction. The stress in the longitudinal direction will be The maximum stress in the radial direction occurs on the material at the inner wall of the vessel and is Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 1 (cont) Solutions The maximum stress occurs in any two perpendicular directions on an element of the vessel is Copyright ©2014 Pearson Education, All Rights Reserved
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REVIEW OF STRESS ANALYSES
Normal force P leads to: Shear force V leads to: Bending moment M leads to: Copyright ©2014 Pearson Education, All Rights Reserved
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REVIEW OF STRESS ANALYSES (cont)
Torsional moment T leads to: Resultant stresses by superposition: Once the normal and shear stress components for each loading have been calculated, use the principal of superposition to determine the resultant normal and shear stress components. Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 2 A force of 15 kN is applied to the edge of the member shown in Fig. 8–3a. Neglect the weight of the member and determine the state of stress at points B and C. Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 2 (cont) Solutions For equilibrium at the section there must be an axial force of N acting through the centroid and a bending moment of N•mm about the centroidal or principal axis. Stress components Normal Force Bending moments The maximum stress is Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 2 (cont) Solutions Super Position The location of the line of zero stress can be determined by proportional triangles Elements of material at B and C are subjected only to normal or uniaxial stress. Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 3 The tank in Fig. 8–4a has an inner radius of 600 mm and a thickness of 12 mm. It is filled to the top with water having a specific weight of γw = 10 kNm3. If it is made of steel having a specific weight of γst = 78 kNm3, determine the state of stress at point A. The tank is open at the top. Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 3 (cont) Solutions The weight of the tank is The pressure on the tank at level A is For circumferential and longitudinal stress, we have Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 4 The member shown in Fig. 8–5a has a rectangular cross section. Determine the state of stress that the loading produces at point C. Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 4 (cont) Solutions The resultant internal loadings at the section consist of a normal force, a shear force, and a bending moment. Solving, Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 4 (cont) Solutions The uniform normal-stress distribution acting over the cross section is produced by the normal force. At Point C, In Fig. 8–5e, the shear stress is zero. Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 4 (cont) Solutions Point C is located at y = c = 0.125m from the neutral axis, so the normal stress at C, Fig. 8–5f, is Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 4 (cont) Solutions The shear stress is zero. Adding the normal stresses determined above gives a compressive stress at C having a value of Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 5 The rectangular block of negligible weight in Fig. 8–6a is subjected to a vertical force of 40 kN, which is applied to its corner. Determine the largest normal stress acting on a section through ABCD. Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 5 (cont) Solutions For uniform normal-stress distribution the stress is For 8 kNm, the maximum stress is For 16 kNm, the maximum stress is Copyright ©2014 Pearson Education, All Rights Reserved
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Copyright ©2014 Pearson Education, All Rights Reserved
EXAMPLE 5 (cont) Solutions By inspection the normal stress at point C is the largest since each loading creates a compressive stress there Copyright ©2014 Pearson Education, All Rights Reserved
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