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Chemistry – Dec 1, 2017 Objective – Compare Ca and Ba.
P3 Challenge- Compare Ca and Ba. A) Which is larger and why? B) Which has the greater ionization energy and why? Objective – Review - obtain the 2 sheets on your table Get out Periodic Trends WS for Hmk Check
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Chemistry – Dec 1, 2017 Today’s Objective – Assignment:
Review Assignment: Study for Unit 3 Test on Dec 11 and Final on Dec 18 Agenda Homework Review Review Worksheet
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Homework Review 2. Ne, Al, S, O (noble gases = 0)
1. O, C, Al, K 2. Ne, Al, S, O (noble gases = 0) 3. F is smaller atom, higher on PT, harder to remove electron from F than I 4. same outer electron configuration only varies by size 5. a. decrease b. increase c. increase 6. Atomic Radii increase going down PT, Re: larger n value and larger orbitals 7. Ionization E increase going L R, Re: same size, but Z is increasing.
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Homework Review b. Ca Ca is smaller c. Na Na is smaller
8. a. Al Al is lower on PT, larger n b. Na same period, Al is smaller due to higher Z c. S S is lower on PT, larger n d. O same period, O is larger because it’s to the left with lower Z e. Br Br lower on PT, larger n f. Ca Ca lower on PT, larger n 9. a. Be I.E increases L R b. Ca Ca is smaller c. Na Na is smaller d. Ar Ar noble gas, I.E increases L R e. Cl I.E increases L R f. Li Li is smaller
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Homework Review 10. a. Ga Ga to the right b. Br Br to the right
c. O O to the right d. Sr Sr is above Ba e. Cl Cl is to the right f. O O is above S 11. a. Ca Cations get smaller b. Br– anions get larger c. Na+ Isoelectronic, Na has lower Z d. Ba+2 Ba is below Sr e. Cl– isoelectronic, Cl has lower Z f. S–2 S is below O
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Exit Slip - Homework Exit Slip: Calculate the atomic mass for chlorine using the following data. SHOW WORK. Chlorine-35 m = ab = 75.78% Chlorine-37 m = ab = 24.22% What’s Due? (Pending assignments to complete.) Study for Unit 3 Test on Dec 11 and Final on Dec 18 What’s Next? (How to prepare for the next day) Read Holt p
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