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Exam II: Wed, November 3. Review session: Mon, November 1.

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Presentation on theme: "Exam II: Wed, November 3. Review session: Mon, November 1."— Presentation transcript:

1 Exam II: Wed, November 3. Review session: Mon, November 1. SI Review session: Tue, November 2. Topics: FTC 5.3, Net Change Th 5.4, substitution rule 5.5, integration by parts 7.1, trigonometric integrals 7.2, trigonometric substitution 7.3, integration of rational functions 7.4, areas between curves 6.1.

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3 Problems 1. FTC, Part 1: Differentiation of integrals. Sec 2. Net change Th. Motion in a straight line. Given velocity function v(t), find displacement and total distance. Sec 3. Substitution indefinite integrals: definite integrals: Sec 4. By parts: Sec , 63-64 5. Trigonometric integrals: Sec 6. Trigonometric substitution: Sec etc.

4 7. Rational functions: Sec Completing square: Sec 8. Area between curves Set up the area between the following curves: a) b) Sec

5 General strategy for integration: some recommendations
Simplify the integrand; Try obvious substitution; Classify the integrand according to its form: Trigonometric f-n try substitution as in Sec. 7.2 (if applicable) Product of f-ns try by parts Rational f-n try partial fractions Radicals if if   try try trigonometric rational substitution substitution as in Sec. 7.3 4. Manipulate the integrand (e.g. algebraic, trigonometric manipulations); 5. Combine different methods; 6. Be creative!!!

6 Areas between curves S x y a y=f(x) b y=g(x)
Consider region S between y=f(x), y=g(x), x=a, x=b, where f, g – continuous, f(x)g(x) x[a,b]. A – area of region S x y a y=f(x) b y=g(x) Divide [a,b] into n subintervals of width Approximate an area of i-th strip by a rectangle with base x and height where is some sample point in the interval [xi,xi+1]. Then

7 y S2 x a y=f(x) b y=g(x) S1 f(x)g(x) for some x[a,b] g(x)f(x) for some x[a,b] Then split S into sub-regions and find an area of each. Total area is S x y c x=f(y) d x=g(y) Consider region S between x=f(y), x=g(y), y=c, y=d, where f, g – continuous, f(y)g(y) y[c,d]. Then

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