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Sec. 12.4 Apply Other Angle Relationships in Circles p. 790
Objectives : Find the measures of angles formed by lines that intersect circles. Use angle measures to solve problems. Vocabulary: Review chord, secant, tangent Introduction: Why would a sailor climb to the top of a mast to watch for land? Today you will investigate how the height of the mast is related to the distance that can be seen.
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Find angle and arc measures
Line m is tangent to the circle. Find the measure of the red angle or arc. = 65o = 250o
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Find the indicated measure.
= 105o
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Find the indicated measure.
= 196o
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Find the indicated measure.
= 160o
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Using Tangent-Secant and
Tangent-Chord Angles Find each measure. mEFH = 65°
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Using Tangent-Secant and
Tangent-Chord Angles Find each measure.
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Find each measure. mSTU = 83
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Find each measure.
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Find an angle measure inside a circle
Find the value of x. xo = 143
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Finding Angle Measures Inside
a Circle Find each measure. mAEB = 126
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mABD Find each angle measure.
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Find each angle measure.
mRNM mRNM = 22°
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Finding Measures Using
Tangents and Secants Find the value of x. = 40 = 63
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Find the value of x. 50° = 83° – x x = 33°
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Find an angle measure outside a circle
Find the value of x. = 51 x
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Find the value of the variable.
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Finding Arc Measures V U Find Step 1 Find = 67 67
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Continued V U Step 2 Find
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Step 2 Find Find mLP Step 1 Find
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Design Application In the company logo shown, = 108°, and = 12°. What is mFKH?
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Two of the six muscles that control eye movement are attached to the eyeball and intersect behind the eye. If mAEB = 225, what is mACB?
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Lesson Quiz: Part I Find each measure. 1. mFGJ 2. mHJK 41.5° 65°
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Lesson Quiz: Part II 3. An observer watches people riding a Ferris wheel that has 12 equally spaced cars. Find x. 30°
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Lesson Quiz: Part III 4. Find mCE. 12°
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GUIDED PRACTICE 4. Find the value of the variable. y = 61o
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QS = 5, QT = 4, so ëQST is a right ë.
GUIDED PRACTICE 6. Find the value of the variable. QS = 5, QT = 4, so ëQST is a right ë. tan ÁTQS = ¾, so tan -1 (3/4) = 36.9à. 2 (36.9à) = ÁTQR = 73.7à Then, ÁTQR=1/2(x-(360-x)) 73.7 = 1/2(2x -360) 73.7 = x - 180 X = 253.7à
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Solve a real-world problem
SCIENCE The Northern Lights are bright flashes of colored light between 50 and 200 miles above Earth. Suppose a flash occurs 150 miles above Earth. What is the measure of arc BD, the portion of Earth from which the flash is visible? (Earth’s radius is approximately 4000 miles.)
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Use Theorem 10.13. Substitute. Solve for x. Solve a real-world problem
SOLUTION Because CB and CD are tangents, CB AB and CD AD Also,BC DC and CA CA . So, ABC ADC by the Hypotenuse-Leg Congruence Theorem, and BCA DCA.Solve right CBA to find that m BCA 74.5°. = 12 m BCD (mDEB – mBD) Use Theorem 149o 12 [(360o – xo) –xo] Substitute. xo 31 Solve for x. ANSWER The measure of the arc from which the flash is visible is about 31o.
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