Download presentation
Presentation is loading. Please wait.
Published byAmanda Andresen Modified over 5 years ago
1
Two hungry Math 160 students are waiting in line at Chipotle
Two hungry Math 160 students are waiting in line at Chipotle. First math student: βOh, no! I forgot my wallet! What should I do?β Second math student: βπ+πβ
2
Packet #31 The Binomial Theorem
Math 160 Packet #31 The Binomial Theorem
3
How can we find π+π π for any natural number π
How can we find π+π π for any natural number π? Letβs try π=1, 2, 3, 4,β¦ and find patterns. π+π 1 = π+π π+π 2 = π 2 +2ππ+ π 2 π+π 3 = π 3 +3 π 2 π+3π π 2 + π 3 π+π 4 = π 4 +4 π 3 π+6 π 2 π 2 +4π π 3 + π 4 π+π 5 = π 5 +5 π 4 π+10 π 3 π π 2 π 3 +5π π 4 + π 5 Notice the exponent pattern (π goes from π to 0, and π goes from 0 to π).
4
How can we find π+π π for any natural number π
How can we find π+π π for any natural number π? Letβs try π=1, 2, 3, 4,β¦ and find patterns. π+π 1 = π+π π+π 2 = π 2 +2ππ+ π 2 π+π 3 = π 3 +3 π 2 π+3π π 2 + π 3 π+π 4 = π 4 +4 π 3 π+6 π 2 π 2 +4π π 3 + π 4 π+π 5 = π 5 +5 π 4 π+10 π 3 π π 2 π 3 +5π π 4 + π 5 Notice the exponent pattern (π goes from π to 0, and π goes from 0 to π).
5
How can we find π+π π for any natural number π
How can we find π+π π for any natural number π? Letβs try π=1, 2, 3, 4,β¦ and find patterns. π+π 1 = π+π π+π 2 = π 2 +2ππ+ π 2 π+π 3 = π 3 +3 π 2 π+3π π 2 + π 3 π+π 4 = π 4 +4 π 3 π+6 π 2 π 2 +4π π 3 + π 4 π+π 5 = π 5 +5 π 4 π+10 π 3 π π 2 π 3 +5π π 4 + π 5 Notice the exponent pattern (π goes from π to 0, and π goes from 0 to π).
6
How can we find π+π π for any natural number π
How can we find π+π π for any natural number π? Letβs try π=1, 2, 3, 4,β¦ and find patterns. π+π 1 = π+π π+π 2 = π 2 +2ππ+ π 2 π+π 3 = π 3 +3 π 2 π+3π π 2 + π 3 π+π 4 = π 4 +4 π 3 π+6 π 2 π 2 +4π π 3 + π 4 π+π 5 = π 5 +5 π 4 π+10 π 3 π π 2 π 3 +5π π 4 + π 5 Notice the exponent pattern (π goes from π to 0, and π goes from 0 to π).
7
How can we find π+π π for any natural number π
How can we find π+π π for any natural number π? Letβs try π=1, 2, 3, 4,β¦ and find patterns. π+π 1 = π+π π+π 2 = π 2 +2ππ+ π 2 π+π 3 = π 3 +3 π 2 π+3π π 2 + π 3 π+π 4 = π 4 +4 π 3 π+6 π 2 π 2 +4π π 3 + π 4 π+π 5 = π 5 +5 π 4 π+10 π 3 π π 2 π 3 +5π π 4 + π 5 Notice the exponent pattern (π goes from π to 0, and π goes from 0 to π).
8
How can we find π+π π for any natural number π
How can we find π+π π for any natural number π? Letβs try π=1, 2, 3, 4,β¦ and find patterns. π+π 1 = π+π π+π 2 = π 2 +2ππ+ π 2 π+π 3 = π 3 +3 π 2 π+3π π 2 + π 3 π+π 4 = π 4 +4 π 3 π+6 π 2 π 2 +4π π 3 + π 4 π+π 5 = π 5 +5 π 4 π+10 π 3 π π 2 π 3 +5π π 4 + π 5 Notice the exponent pattern (π goes from π to 0, and π goes from 0 to π).
9
How can we find π+π π for any natural number π
How can we find π+π π for any natural number π? Letβs try π=1, 2, 3, 4,β¦ and find patterns. π+π 1 = π+π π+π 2 = π 2 +2ππ+ π 2 π+π 3 = π 3 +3 π 2 π+3π π 2 + π 3 π+π 4 = π 4 +4 π 3 π+6 π 2 π 2 +4π π 3 + π 4 π+π 5 = π 5 +5 π 4 π+10 π 3 π π 2 π 3 +5π π 4 + π 5 Notice the exponent pattern (π goes from π to 0, and π goes from 0 to π).
10
The coefficient pattern is whatβs known as Pascalβs triangle:
1 1 1
11
Ex 1. Find the expansion of π+π 7 using Pascalβs triangle. Ex 2
Ex 1. Find the expansion of π+π 7 using Pascalβs triangle. Ex 2. Find the expansion of 2β3π₯ 5 using Pascalβs triangle.
12
Ex 1. Find the expansion of π+π 7 using Pascalβs triangle. Ex 2
Ex 1. Find the expansion of π+π 7 using Pascalβs triangle. Ex 2. Find the expansion of 2β3π₯ 5 using Pascalβs triangle.
13
To figure out the 15th row of Pascalβs triangle, you first need to figure out rows 1 through 14. When expanding π+π π for a large π, thereβs a more direct way to get the coefficients. But firstβ¦
14
To figure out the 15th row of Pascalβs triangle, you first need to figure out rows 1 through 14. When expanding π+π π for a large π, thereβs a more direct way to get the coefficients. But firstβ¦
15
Definitions: π. =πβ
πβ1 β
β¦β
3β
2β
1 (π. is read βπ factorialβ) 0
Definitions: π!=πβ
πβ1 β
β¦β
3β
2β
1 (π! is read βπ factorialβ) 0!=1 π π = π! π! πβπ ! ( π π is called the binomial coefficient) The Binomial Theorem: π+π π = π 0 π π + π 1 π πβ1 π+ π 2 π πβ2 π 2 +β¦+ π πβ1 π π πβ1 + π π π π
16
Definitions: π. =πβ
πβ1 β
β¦β
3β
2β
1 (π. is read βπ factorialβ) 0
Definitions: π!=πβ
πβ1 β
β¦β
3β
2β
1 (π! is read βπ factorialβ) 0!=1 π π = π! π! πβπ ! ( π π is called the binomial coefficient) The Binomial Theorem: π+π π = π 0 π π + π 1 π πβ1 π+ π 2 π πβ2 π 2 +β¦+ π πβ1 π π πβ1 + π π π π
17
Definitions: π. =πβ
πβ1 β
β¦β
3β
2β
1 (π. is read βπ factorialβ) 0
Definitions: π!=πβ
πβ1 β
β¦β
3β
2β
1 (π! is read βπ factorialβ) 0!=1 π π = π! π! πβπ ! ( π π is called the binomial coefficient) The Binomial Theorem: π+π π = π 0 π π + π 1 π πβ1 π+ π 2 π πβ2 π 2 +β¦+ π πβ1 π π πβ1 + π π π π
18
Definitions: π. =πβ
πβ1 β
β¦β
3β
2β
1 (π. is read βπ factorialβ) 0
Definitions: π!=πβ
πβ1 β
β¦β
3β
2β
1 (π! is read βπ factorialβ) 0!=1 π π = π! π! πβπ ! ( π π is called the binomial coefficient) The Binomial Theorem: π+π π = π 0 π π + π 1 π πβ1 π+ π 2 π πβ2 π 2 +β¦+ π πβ1 π π πβ1 + π π π π
19
π!=πβ
πβ1 β
β¦β
3β
2β
1 (π! is read βπ factorialβ) 0!=1
Definitions: π!=πβ
πβ1 β
β¦β
3β
2β
(π! is read βπ factorialβ) 0!=1 π π = π! π! πβπ ! ( π π is called the binomial coefficient) The Binomial Theorem: π+π π = π 0 π π + π 1 π πβ1 π+ π 2 π πβ2 π 2 +β¦+ π πβ1 π π πβ1 + π π π π (or, more compactly, π+π π = π=0 π π π π πβπ π π )
20
Note: In combinatorics, π π counts the number of ways to choose π objects from π objects, where order doesnβt matter. For example, the number of ways to choose a group of 4 students from a class of 36 students is 36 4 = 36! 4! 36β4 ! =58905 ways.
21
Note: In combinatorics, π π counts the number of ways to choose π objects from π objects, where order doesnβt matter. For example, the number of ways to choose a group of 4 students from a class of 36 students is 36 4 = 36! 4! 36β4 ! =58905 ways.
22
For the Binomial Theorem, when you multiply out π+π π = π+π π+π π+π β
β
β
(π+π), each term is the product of πβs and πβs chosen from each factor. For example, if you donβt choose any πβs, then youβre just multiplying all of the πβs to get π π , and thereβs only one way to do this. There are π 1 =π ways to choose one π and πβ1 πβs (that is, the term π πβ1 π). In general, you can think of it like this: there are π π to choose π πβs from the π factors of π+π.
23
For the Binomial Theorem, when you multiply out π+π π = π+π π+π π+π β
β
β
(π+π), each term is the product of πβs and πβs chosen from each factor. For example, if you donβt choose any πβs, then youβre just multiplying all of the πβs to get π π , and thereβs only one way to do this. There are π 1 =π ways to choose one π and πβ1 πβs (that is, the term π πβ1 π). In general, you can think of it like this: there are π π to choose π πβs from the π factors of π+π.
24
For the Binomial Theorem, when you multiply out π+π π = π+π π+π π+π β
β
β
(π+π), each term is the product of πβs and πβs chosen from each factor. For example, if you donβt choose any πβs, then youβre just multiplying all of the πβs to get π π , and thereβs only one way to do this. There are π 1 =π ways to choose one π and πβ1 πβs (that is, the term π πβ1 π). In general, you can think of it like this: there are π π to choose π πβs from the π factors of π+π.
25
For the Binomial Theorem, when you multiply out π+π π = π+π π+π π+π β
β
β
(π+π), each term is the product of πβs and πβs chosen from each factor. For example, if you donβt choose any πβs, then youβre just multiplying all of the πβs to get π π , and thereβs only one way to do this. There are π 1 =π ways to choose one π and πβ1 πβs (that is, the term π πβ1 π). In general, you can think of it like this: there are π π to choose π πβs from the π factors of π+π.
26
Ex = = =
27
Note: π 0 = π 1 =π π π =1
28
Ex 4. Use the Binomial Theorem to expand 2π₯β1 4 .
29
Note: The term that contains π πβπ in the expansion of π+π π is: π π π πβπ π π Ex 5. Find the term that contains π₯ 5 in the expansion of 2π₯+π¦ 20 . Ex 6. Find the coefficient of π₯ 8 in the expansion of π₯ π₯ 10 .
30
Note: The term that contains π πβπ in the expansion of π+π π is: π π π πβπ π π Ex 5. Find the coefficient of π₯ 4 in the expansion of 3π₯β2 6 . Ex 6. Find the coefficient of π₯ 8 in the expansion of π₯ π₯ 10 .
31
Note: The Binomial Theorem can be proved by induction
Note: The Binomial Theorem can be proved by induction! (see book for details)
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.