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Published byMolly Carr Modified over 5 years ago
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F = 1.75 cm 2F = C = 3.50 cm do = 3 cm ho = 1 cm F MEASURED
REFLECTION FROM A CONCAVE MIRROR - OBJECT BETWEEN F AND 2F (C-Radius of Curvature) Scale: 1 cm = 1 cm F = 1.75 cm 2F = C = 3.50 cm do = 3 cm ho = 1 cm MEASURED di = 4.6 cm hi = 1.6 cm Theoretical Distance to image Height of image 1/do + 1/di = 1/f m = -di/do hi = m(ho) 1/3 + 1/di = 1/ m = -4.2/ hi = 1.4(1) di = 4.2 cm m = hi = 1.4 % deviation = 9.52% % deviation = 14.29% Image is real, in front of mirror, inverted and larger F C do di ho hi An example of this situation is
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di hi ho do F F = 1.85 cm 2F = C = 3.70 do = 1 cm ho = 1 cm C
REFLECTION FROM A CONCAVE MIRROR - OBJECT BETWEEN F AND MIRROR Scale 2 cm = 1 cm F = 1.85 cm 2F = C = 3.70 do = 1 cm ho = 1 cm Measured di = 1.25 cm (scale 2.5) hi = 1.85 cm (scale 3.7) Theoretical Distance to image m = -di/do 1/do + 1/di = 1/f m = -(-2.18)/1 1/1 + 1/di = 1/ m = 2.18 di = cm hi = 2.18 cm %deviation 42.7% % deviation 15.14% - virtual erect Image is virtual, behind mirror, erect, larger An example of this situation is hi ho do C F di
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di do F ho C F = -1.85 cm 2F = C = 3.70 cm do = 1.85 cm ho = 1 cm hi
REFLECTION FROM A CONVEX MIRROR - OBJECT AT F BEHIND MIRROR Scale 2 cm = 1 cm Theoretical Distance to image Height of Image 1/do + 1/di = 1/f m = -di/d0 1/ /di = -1/ m = -(-0.93)/1.85 di = -0.93cm (virtual) hi = 0.50(1) = .5cm (erect) % deviation 29.03% % deviation 10% F = cm 2F = C = 3.70 cm do = 1.85 cm ho = 1 cm MEASURED di = 1.2 cm (scale 2.2) hi = 0.45 cm (scale 0.9) F C An example of this situation is do ho hi di
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