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Subject :- Applied Mathematics
Matrices Created By, Subject Teacher :- Rahi Sonar
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Matrix Operations Matrix addition/subtraction Matrix multiplication
Matrices must be of same size. Matrix multiplication m x n q x p m x p Condition: n = q
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Identity Matrix
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Matrix Transpose
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Symmetric Matrices Example:
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Determinants 2 x 2 3 x 3 n x n
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Determinants (cont’d)
diagonal matrix:
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Matrix Inverse The inverse A-1 of a matrix A has the property:
AA-1=A-1A=I A-1 exists only if Terminology Singular matrix: A-1 does not exist Ill-conditioned matrix: A is close to being singular
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Matrix Inverse (cont’d)
Properties of the inverse:
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Pseudo-inverse The pseudo-inverse A+ of a matrix A (could be non-square, e.g., m x n) is given by: It can be shown that:
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Matrix trace properties:
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Rank of matrix Equal to the dimension of the largest square sub-matrix of A that has a non-zero determinant. Example: has rank 3
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Rank of matrix (cont’d)
Alternative definition: the maximum number of linearly independent columns (or rows) of A. Therefore, rank is not 4 ! Example:
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Rank and singular matrices
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Orthogonal matrices Notation: A is orthogonal if: Example:
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Orthonormal matrices A is orthonormal if:
Note that if A is orthonormal, it easy to find its inverse: Property:
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Eigenvalues and Eigenvectors
The vector v is an eigenvector of matrix A and λ is an eigenvalue of A if: Interpretation: the linear transformation implied by A cannot change the direction of the eigenvectors v, only their magnitude. (assume non-zero v)
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Computing λ and v To find the eigenvalues λ of a matrix A, find the roots of the characteristic polynomial: Example:
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Properties Eigenvalues and eigenvectors are only defined for square matrices (i.e., m = n) Eigenvectors are not unique (e.g., if v is an eigenvector, so is kv) Suppose λ1, λ2, ..., λn are the eigenvalues of A, then:
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Properties (cont’d) xTAx > 0 for every
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Matrix diagonalization
Given A, find P such that P-1AP is diagonal (i.e., P diagonalizes A) Take P = [v1 v vn], where v1,v2 ,. . . vn are the eigenvectors of A:
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Matrix diagonalization (cont’d)
Example:
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Are all n x n matrices diagonalizable?
Only if P-1 exists (i.e., A must have n linearly independent eigenvectors, that is, rank(A)=n) If A has n distinct eigenvalues λ1, λ2, ..., λn , then the corresponding eigevectors v1,v2 ,. . . vn form a basis: (1) linearly independent (2) span Rn
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Diagonalization Decomposition
Let us assume that A is diagonalizable, then:
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Decomposition: symmetric matrices
The eigenvalues of symmetric matrices are all real. The eigenvectors corresponding to distinct eigenvalues are orthogonal. P-1=PT A=PDPT=
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