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256 nm light strikes a metal and the ejected electrons have a stopping potential of 1.15 V. What is the work function of the metal in eV? (2) E = hf =

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Presentation on theme: "256 nm light strikes a metal and the ejected electrons have a stopping potential of 1.15 V. What is the work function of the metal in eV? (2) E = hf ="— Presentation transcript:

1 256 nm light strikes a metal and the ejected electrons have a stopping potential of 1.15 V. What is the work function of the metal in eV? (2) E = hf = hc/, 1 eV = x J Photon energy = Work function + Kinetic energy of electron E = hf = hc/ = (6.626 x Js)(3.00 x 108 m/s)/(256 x 10-9 m) E = x J E = ( x J)/(1.602 x J/eV) = eV Photon energy = Work function + Kinetic energy of electron 4.847 eV = Work function eV eV eV = 3.70 eV W 3.70 eV

2 Light Wave model Photon model Color is Brightness is

3 Max. Energy of Ejected Electrons Wave model Photon model Depends on: Is independent of:

4 Find the equation of this line. What does the slope mean
Find the equation of this line. What does the slope mean? What does the y-intercept mean? What kind of data is it?


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