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Comparing Means from Two Data Sets

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Presentation on theme: "Comparing Means from Two Data Sets"— Presentation transcript:

1 Comparing Means from Two Data Sets
The t-test 6/16/2019 HK Dr. Sasho MacKenzie

2 Research Questions To improve muscular power, should an athlete perform heavy resistance exercises, or light plyometric exercises? Is it better to imagine the flight of the ball or the actions of your swing prior to striking a golf ball? Is running 5 km or walking 5 km better for burning calories? Do golfers sink more putts if they focus on the hole or on the ball during a putt? Will squatting to a lower depth during a vertical jump improve performance? 6/16/2019 HK Dr. Sasho MacKenzie

3 The t-test All of the questions posed on the previous slide can be statistically addressed using the t-test. A t-test determines if two groups of data are significantly different (not meaningfully different). A t-test is the ratio of the actual difference between two means to the difference that is expected due to chance alone. The bigger the actual difference is compared to the expected difference due to chance, the more statistically significant the t-test. 6/16/2019 HK Dr. Sasho MacKenzie

4 The t-test A t-test calculation produces a value (t-statistic) that is similar to a z-score. The t-distributions, are also very similar to the z-score distribution (normal distribution). The t-distribution changes depending on the sample size. 6/16/2019 HK Dr. Sasho MacKenzie

5 The t Distributions (3 examples)
N = 60 (same as normal curve) N = 10 N = 3 E.g., Area beyond t=3 increases as N decreases -4 -3 -2 -1 1 2 3 4 t 6/16/2019 HK Dr. Sasho MacKenzie

6 Let’s use an Example Question: Do HK students drink more or less alcohol than the average St.FX student? Assumptions: Every student on campus honestly completed a form and the average drinks/week is known. Therefore, we know the mean of the population. Methods: Determine the drinks/week for a sample of HK students. Determine if the sample mean is “different” than the population mean (perform a t-test). 6/16/2019 HK Dr. Sasho MacKenzie

7 What is “different”? Before the t-test, we must set a standard for statistical significance. This means determining the chance of error we are willing to have in our final decision. I.e., How confident do we want to be in our decision that HK students drink a different amount? This decision is represented by alpha (), which is typically set at .05 (5%). This value is arbitrary. Assume no difference and that the study is repeated 100 times. On 5 occasions, due to chance, we would incorrectly find that HK students drink more. 6/16/2019 HK Dr. Sasho MacKenzie

8 Expected difference due to chance
One-sample t-test We will use what’s called a one-sample t-test. This compares the mean of a sample to the mean of a population. Actual difference Expected difference due to chance X = sample mean  = population mean SEM = standard error of the mean 6/16/2019 HK Dr. Sasho MacKenzie

9 The Hypothesis In statistics you must clearly state a testable hypothesis. Typically the hypothesis tested is opposite to what you expect and is referred to as the null hypothesis. Our null hypothesis is that HK students do not drink a different amount than the average university student. X =  or X -  = 0 6/16/2019 HK Dr. Sasho MacKenzie

10 The Calculation University Population HK Sample of students
Average drinks per week = 10 HK Sample of students Mean = 12, SD = 5, N = 30 The odds of getting a t stat this big, or bigger, due to chance would then be determined by calculating a p-value. 6/16/2019 HK Dr. Sasho MacKenzie

11 The P-value In Excel, the function TDIST() can be used to calculate the p-value. The degrees of freedom are N-1. Our example is a two-tailed test because HK students may drink more, or less, than the average. I.e., the sample mean could be either more or less than the population. Since we set alpha = .05, if the p-value is less than .05, we will state HK students are statistically different. 6/16/2019 HK Dr. Sasho MacKenzie

12 Graphic of two-tailed one sample t-test
t distribution for N = 30 From TDIST, p = .037 Combined area beyond t=2.19 and t = is .037 -4 -3 -2 -1 1 2 3 4 t 6/16/2019 HK Dr. Sasho MacKenzie

13 Conclusion Since p=.037 is less than alpha = .05, we reject the null hypothesis and conclude that HK students consume significantly more drinks per week. The following shows how this would be explained in a study. It was determined that the average number of alcoholic drinks consumed by HK students (12 drinks), per week, was significantly more than the typical university student (10 drinks), t(29) = 2.19, p = .037. 6/16/2019 HK Dr. Sasho MacKenzie

14 Independent t-test Determines if two sample means are statistically different. The null hypothesis is that the means come from the same population, X1 -X2 = 0. The bottom part of the t-stat now reflects the SEM for both samples, but is still a measure of how much you could expect the means of two samples from the same population to differ due to chance. 6/16/2019 HK Dr. Sasho MacKenzie

15 The Equation The stuff on the bottom of the equation is called the standard error of the difference. 6/16/2019 HK Dr. Sasho MacKenzie

16 Independent t-test example
Do HK students drink more or less than Chemistry students? Null Hypothesis: HK students and Chemistry students drink the same amount of alcohol per week. 6/16/2019 HK Dr. Sasho MacKenzie

17 The Calculation HK sample of students Chemistry sample of students
Mean = 12, SD = 5, N = 30 Chemistry sample of students Mean = 10, SD = 3, N = 30 The odds of getting a t stat this big, or bigger, due to chance would then be determined by calculating a p-value. 6/16/2019 HK Dr. Sasho MacKenzie

18 Graphic of two-tailed independent sample t-test
t distribution for N = 60 From TDIST, p = .065 Combined area beyond t=1.88 and t = is .065 -4 -3 -2 -1 1 2 3 4 t 6/16/2019 HK Dr. Sasho MacKenzie

19 Conclusion Since p=.065 is greater than alpha = .05, we cannot reject the null hypothesis. There is not enough evidence to suggest HK students drink more or less than Chemistry students In a study it would be written as: It was determined that the average number of alcoholic drinks consumed by HK students (12 drinks), per week, was not significantly different than the Chemistry students (10 drinks), t(58) = 1.88, p = .065. 6/16/2019 HK Dr. Sasho MacKenzie

20 Dependent (Paired) t-test
Determines if two correlated sample means are statistically different. Required when the same subjects are measured twice. E.g., Pre-test, Post-test study. Adjustments are made in how the variability (SD) in the sample data is calculated. This reduces the denominator in the t-statistic and therefore increases the t-statistic. This accounts for reduction in the t-statistic due to the fact that the same subjects measured twice will show a smaller mean difference than two completely separate groups. 6/16/2019 HK Dr. Sasho MacKenzie

21 The Difference Before any group means or standard deviations are calculated, the difference scores between the two measurement times is determined. For example, if you have a column of pre-test scores and a column of post-test scores, then generate a third column of post minus pre scores. The t-statistic is then calculated using information from the column of difference scores. 6/16/2019 HK Dr. Sasho MacKenzie

22 The Equation The variables in this equations come from a single column of difference scores. 6/16/2019 HK Dr. Sasho MacKenzie

23 Dependent t-test example
Do HK students drink more alcohol on the Saturday prior to a Biomechanics midterm, or on the following Saturday? Null Hypothesis: HK students drink the same amount or less on the following Saturday, compared to the Saturday preceding a Biomechanics midterm. 6/16/2019 HK Dr. Sasho MacKenzie

24 The Data: Number of Drinks
Subject Sat. Before Sat. After Diff 1 16 21 5.0 2 6 9 3.0 3 18 25 7.0 4 11 10 -1.0 5 7 0.0 -3.0 8 12 4.0 2.0 14 15 1.0 6/16/2019 HK Dr. Sasho MacKenzie

25 The Calculation Difference Scores (Before – After)
Mean = 2.1, SD = 3.0, N = 10 The odds of getting a t stat this big, or bigger, due to chance would then be determined by calculating a p-value. 6/16/2019 HK Dr. Sasho MacKenzie

26 The P-value In Excel, the function TDIST() can be used to calculate the p-value. The degrees of freedom are (Npairs - 1). Our example is a one-tailed test because we are assuming HK students drink more following a midterm. This may not be a good assumption, but I needed a one-tailed example. Set alpha = .05, if the p-value is less than .05, we will state HK students drink significantly more following a biomechanics midterm. 6/16/2019 HK Dr. Sasho MacKenzie

27 Graphic of one-tailed dependent sample t-test
t distribution for N = 10 From TDIST, p = .0258 The area beyond t = 2.24 is .0258 -4 -3 -2 -1 1 2 3 4 t 6/16/2019 HK Dr. Sasho MacKenzie

28 Conclusion Since p=.0258 is less than alpha = .05, we reject the null hypothesis and conclude that HK students consume significantly more drinks on the Saturday following a midterm. The following shows how this would be explained in a study. It was determined that HK students consume significantly more alcoholic drinks (2.1 more) on a Saturday after a midterm than on a Saturday before a midterm, t(9) = 2.24, p = 6/16/2019 HK Dr. Sasho MacKenzie

29 What if the t-test was two-tailed?
The null hypothesis would not be: HK students drink the same amount or less on the following Saturday, compared to the Saturday preceding a Biomechanics midterm. But rather it would be: HK students drink the same amount on the following Saturday, compared to the Saturday preceding a Biomechanics midterm. 6/16/2019 HK Dr. Sasho MacKenzie

30 Graphic of two-tailed dependent sample t-test
t distribution for N = 10 From TDIST, p = .0516 Whoa! We no longer have significance at  =.05 Combined area beyond t=2.24 and t = is .0516 -4 -3 -2 -1 1 2 3 4 t 6/16/2019 HK Dr. Sasho MacKenzie

31 Interpreting the P-value
In an experiment of this size, if the populations really have the same mean, what is the probability of observing at least as large a difference between sample means as was, in fact, observed? There is a p% chance of observing a difference as large as you observed even if the two population means are identical (the null hypothesis is true). Random sampling from identical populations would lead to a difference smaller than you observed in 1-p% of experiments, and larger than you observed in p% of experiments. 6/16/2019 HK Dr. Sasho MacKenzie


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