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Body centered cubic Note that each corner atom is in eight cubes so only 1/8 of the corner atom is in this cell Number of atoms = 1 center + 8 x 1/8 corners.

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Presentation on theme: "Body centered cubic Note that each corner atom is in eight cubes so only 1/8 of the corner atom is in this cell Number of atoms = 1 center + 8 x 1/8 corners."— Presentation transcript:

1 Body centered cubic Note that each corner atom is in eight cubes so only 1/8 of the corner atom is in this cell Number of atoms = 1 center + 8 x 1/8 corners = 2 in the unit cell

2 Face centered cubic Eight atoms at the corners
Six atoms at the face centers Each face atom is in two cubes Number of atoms = 6 x ½ faces + 8 x 1/8 corners = 4 in the unit cell

3 Hexagonal close packed
This unit cell has the same packing as the fcc – WHY?

4 Stacking of hexagonal planes
First layer is labeled A Two ways of placing 2nd layer: Can use only 3 of the 6 “holes”, so have two sets: Sites B or Sites C

5 Stacking of hexagonal planes (2)
Alternating sites A with sites B leads to Hexagonal close packed

6 Stacking of hexagonal planes (3)
Stacking of the sequence ABC leads to FCC An oblique plane shows the hexagonal planes

7 Scattering of radiation
Radiation absorbed by atoms is re-emitted in all directions In-phase rays reinforce Out-of phase rays annihilate each other Rays out of phase by an exact number of wavelengths reinforce each other

8 Xray Diffraction For certain specific angles of incidence rays re-emitted from two parallel planes of a crystal are out of phase by exactly multiple wavelengths (n) Path difference between two rays shown is SQT. If SQT equals nλ reinforcement occurs and a diffracted beam is found. SQT = 2d sin  where d is separation of planes


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