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Published byAniella Costanzo Modified over 5 years ago
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1.50 g. NH mol NH3 3.74 ( ) 1 mol = 17.00g STEP 1-Convert to moles mol O2 ( ) 2.75 g. O2 1 mol = 32.00g STEP 1.5 assess limiting reagent THEO ACTUAL The actual ratio is GREATER than the theoretical, therefore the reactant on top is in excess, the one on the bottom is limiting, oxygen limits! NH3 4 = = O2 5 = 0.80 1.02
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4 NH3 5 O2 4 NO 6 H2O 0.08823 0.08595(lim) - 4 X - 5 X + 4 X + 6 X
- 4 X - 5 X + 4 X + 6 X ( ) 4 ( ) 6 ( ) + + X IS CALIBRATED TO THE LIMITING REAGENT, OXYGEN. 5 X = MOL LET X = MOL MOL MOL MOL 2.06 g. THEO YEILD 1.85 g. THEO YEILD 0.330 g. REMAIN (( )+2.75=3.91 REACTED REACTANTS 3.91 g. PRODUCTS =
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