1. Functions Test Review

2. What kind of slope is it? Purple Line: Red Line: Blue Line:
Green Line:

3. What kind of slope is it? Purple Line: Undefined Red Line: Blue Line:
Green Line:

4. What kind of slope is it? Purple Line: Undefined Red Line: Negative
Blue Line:
Green Line:

5. What kind of slope is it? Purple Line: Undefined Red Line: Negative
Blue Line:
Positive
Green Line:

6. What kind of slope is it? Purple Line: Undefined Red Line: Negative
Blue Line:
Positive
Green Line: Zero

7. Find the equation in slope intercept form given the following:
Slope is -2
Passes through (5,-1)

8. Find the equation in slope intercept form given the following:
Slope is -2
Passes through (5,-1)
Plug in:
y– y1 = m ( x – x1)

9. Find the equation in slope intercept form given the following:
Slope is -2
Passes through (5,-1)
Plug in:
y– y1 = m ( x – x1)
y – (-1) = (-2)(x-5)

10. Find the equation in slope intercept form given the following:
Slope is -2
Passes through (5,-1)
Plug in:
y– y1 = m ( x – x1)
y +1 = (-2)(x-5) distribute

11. Find the equation in slope intercept form given the following:
Slope is -2
Passes through (5,-1)
Plug in:
y– y1 = m ( x – x1)
y +1 = (-2)(x-5)
y + 1 = -2x +10

12. Find the equation in slope intercept form given the following:
Slope is -2
Passes through (5,-1)
Plug in:
y– y1 = m ( x – x1)
y +1 = (-2)(x-5)
y + 1 = -2x +10

13. Find the equation in slope intercept form given the following:
Slope is -2
Passes through (5,-1)
Plug in:
y– y1 = m ( x – x1)
y +1 = (-2)(x-5)
y + 1 = -2x +10
y = -2x +9

14. What is the equation of line RS if R(-2,3) and S(2,-5)

15. What is the equation of line RS if R(-2,3) and S(2,-5)
First, find the slope

16. What is the equation of line RS if R(-2,3) and S(2,-5)
First, find the slope
y2 – y1
x2 – x1

17. What is the equation of line RS if R(-2,3) and S(2,-5)
First, find the slope
y2 – y1
x2 – x1
-5– 3
2 – (-2) =

18. What is the equation of line RS if R(-2,3) and S(2,-5)
First, find the slope
y2 – y1
x2 – x1
-5– 3
2 – (-2) = -8 4 =

19. What is the equation of line RS if R(-2,3) and S(2,-5)
First, find the slope
y2 – y1
x2 – x1
-5– 3
2 – (-2) = -8 4 =
= -2

20. What is the equation of line RS if R(-2,3) and S(2,-5)
Slope = -2
Now we plug in:

21. What is the equation of line RS if R(-2,3) and S(2,-5)
Slope = -2
Now we plug in:
y– y1 = m ( x – x1)

22. What is the equation of line RS if R(-2,3) and S(2,-5)
Slope = -2
Now we plug in:
y– y1 = m ( x – x1)
y – 3 = (-2)(x-(-2))

23. What is the equation of line RS if R(-2,3) and S(2,-5)
Slope = -2
Now we plug in:
y– y1 = m ( x – x1)
y – 3 = (-2)(x+2)

24. What is the equation of line RS if R(-2,3) and S(2,-5)
Slope = -2
Now we plug in:
y– y1 = m ( x – x1)
y – 3 = (-2)(x+2)
distribute

25. What is the equation of line RS if R(-2,3) and S(2,-5)
Slope = -2
Now we plug in:
y– y1 = m ( x – x1)
y – 3 = (-2)(x+2)
y – 3 = -2x -4

26. What is the equation of line RS if R(-2,3) and S(2,-5)
Slope = -2
Now we plug in:
y– y1 = m ( x – x1)
y – 3 = (-2)(x+2)
y – 3 = -2x -4

27. What is the equation of line RS if R(-2,3) and S(2,-5)
Slope = -2
Now we plug in:
y– y1 = m ( x – x1)
y – 3 = (-2)(x+2)
y – 3 = -2x -4
y = -2x -1

28. What is the equation of line RS if R(-2,3) and S(2,-5)
y– y1 = m ( x – x1)
y – 3 = (-2)(x+2)
y – 3 = -2x -4
y = -2x -1
So RS has the equation y=-2x-1

29. Find the equation of the line that passes through P and Q

30. Find the equation of the line that passes through P and Q
Record the points Q P

31. Find the equation of the line that passes through P and Q
Record the points
P(-6,-3)
Q(-2,3) Q P

32. Find the equation of the line that passes through P and Q
Find the slope Q P

33. Find the equation of the line that passes through P and Q
Find the slope Q
y2 – y1
x2 – x1 P

34. Find the equation of the line that passes through P and Q
Find the slope Q
y2 – y1
x2 – x1 =
3-(-3)
-2-(-6) P

35. Find the equation of the line that passes through P and Q
Find the slope Q
y2 – y1
x2 – x1 =
3 + 3
-2+6 P

36. Find the equation of the line that passes through P and Q
Find the slope Q
y2 – y1
x2 – x1 =
3 + 3
-2+6 P = 6 4

37. Find the equation of the line that passes through P and Q
Find the slope Q
y2 – y1
x2 – x1 =
3 + 3
-2+6 P = 6 4 3 2 =

38. Find the equation of the line that passes through P and Q
m= 3/2 Q P

39. Find the equation of the line that passes through P and Q
m= 3/2 P Q
y– y1 = m ( x – x1)

40. Find the equation of the line that passes through P and Q
m= 3/2 P Q
y– y1 = m ( x – x1)
y – 3 = (3/2)(x-(-2))

41. Find the equation of the line that passes through P and Q
m= 3/2 P Q
y– y1 = m ( x – x1)
y – 3 = (3/2)(x+2)

42. Find the equation of the line that passes through P and Q
m= 3/2 P Q
y– y1 = m ( x – x1)
y – 3 = (3/2)(x+2)
y – 3 = (3/2)x+3

43. Find the equation of the line that passes through P and Q
m= 3/2 P Q
y– y1 = m ( x – x1)
y – 3 = (3/2)(x+2)
y – 3 = (3/2)x+3
y = (3/2)x + 6

44. What makes lines PARALLEL?

45. What makes lines PARALLEL?
They have the SAME slope
y = mx + b

46. What makes lines PARALLEL?
They have the SAME slope
y = mx + b
Give me a line parallel to the given lines:
y = 3x y = -(1/2)x +(3/2) y = (1/3)x-1
y= x=3

47. What makes lines PARALLEL?
They have the SAME slope
y = mx + b
Give me a line parallel to the given lines:
y = 3x y = -(1/2)x +(3/2) y = (1/3)x-1
y = 3x y = -(1/2)x y = (1/3)x+1777
y= x=3
y=7 x=-15

48. What makes lines PERPENDICULAR?

49. What makes lines PERPENDICULAR?
Slopes are NEGATIVE RECIPROCALS
y = mx + b

50. What makes lines PERPENDICULAR?
Slopes are NEGATIVE RECIPROCALS
y = mx + b
Give me a line perpendicular to the given lines:
y = 3x y = -(1/2)x +(3/2) y = (1/3)x-1
y= x=3

51. What makes lines PERPENDICULAR?
Slopes are NEGATIVE RECIPROCALS
y = mx + b
Give me a line perpendicular to the given lines:
y = 3x y = -(1/2)x +(3/2) y = (1/3)x-1
y = -(1/3)x y = 2x y = -3x+5
y= x=3
x=7 y=-15

52. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD

53. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD
Find the slopes of line AB and line CD

54. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD
Find the slopes of line AB and line CD
Line AB
y2 – y1
x2 – x1

55. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD
Find the slopes of line AB and line CD
Line AB
y2 – y1
x2 – x1
9 - 3
1-(-2) =

56. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD
Find the slopes of line AB and line CD
Line AB
y2 – y1
x2 – x1
9 -3
1+2 =

57. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD
Find the slopes of line AB and line CD
Line AB
y2 – y1
x2 – x1
9 -3
1+2 6 3 = =

58. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD
Find the slopes of line AB and line CD
Line AB
y2 – y1
x2 – x1
9 -3
1+2 6 3 = =
= 2

59. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD
Find the slopes of line AB and line CD
Line AB: m = 2
Line CD:
y2 – y1
x2 – x1 =

60. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD
Find the slopes of line AB and line CD
Line AB: m = 2
Line CD:
y2 – y1
x2 – x1
7 - 5
-4-0 =

61. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD
Find the slopes of line AB and line CD
Line AB: m = 2
Line CD:
y2 – y1
x2 – x1 2 -4
7 - 5
-4-0 = =

62. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD
Find the slopes of line AB and line CD
Line AB: m = 2
Line CD: m=(-1/2)
y2 – y1
x2 – x1 2 -4
7 - 5
-4-0 1 -2 = = =

63. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD
Find the slopes of line AB and line CD
Line AB: m = 2
Line CD: m=(-1/2)
Now that we have both slopes, are these lines parallel, perpendicular, or neither?

64. Given A(1,9), B(-2,3), C(0,5), and D(-4,7): describe the relationship between line AB and line CD
Find the slopes of line AB and line CD
Line AB: m = 2
Line CD: m=(-1/2)
Now that we have both slopes, are these lines parallel, perpendicular, or neither?
Perpendicular

65. If line AB has a slope of -3 and B(1,-2)
If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4

66. If line AB has a slope of -3 and B(1,-2)
If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4
We know our slope and we have a point, so we plug in:
y– y1 = m ( x – x1)

67. If line AB has a slope of -3 and B(1,-2)
If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4
We know our slope and we have a point, so we plug in:
y– y1 = m ( x – x1)
y – (-2) = (-3) (x-1)

68. If line AB has a slope of -3 and B(1,-2)
If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4
We know our slope and we have a point, so we plug in:
y– y1 = m ( x – x1)
y +2 = (-3) (x-1)

69. If line AB has a slope of -3 and B(1,-2)
If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4
We know our slope and we have a point, so we plug in:
y– y1 = m ( x – x1)
y +2 = (-3) (x-1)
y +2=-3x +3

70. If line AB has a slope of -3 and B(1,-2)
If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4
We know our slope and we have a point, so we plug in:
y– y1 = m ( x – x1)
y +2 = (-3) (x-1)
y +2=-3x +3

71. If line AB has a slope of -3 and B(1,-2)
If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4
We know our slope and we have a point, so we plug in:
y– y1 = m ( x – x1)
y +2 = (-3) (x-1)
y +2=-3x +3
y = -3x +1

72. If line AB has a slope of -3 and B(1,-2)
If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4
We know our slope and we have a point, so we plug in:
y– y1 = m ( x – x1)
y +2 = (-3) (x-1)
y +2=-3x +3
y = -3x +1
Now that we have the equation, we plug in 4 for x and solve to get the
y value

73. If line AB has a slope of -3 and B(1,-2)
If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4
We know our slope and we have a point, so we plug in:
y = -3x +1
y = (-3)(4) +1

74. If line AB has a slope of -3 and B(1,-2)
If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4
We know our slope and we have a point, so we plug in:
y = -3x +1
y = (-3)(4) +1
y =

75. If line AB has a slope of -3 and B(1,-2)
If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4
We know our slope and we have a point, so we plug in:
y = -3x +1
y = (-3)(4) +1
y =
y = -11

76. If line AB has a slope of -3 and B(1,-2)
If line AB has a slope of -3 and B(1,-2). What is the coordinate of A if x=4
We know our slope and we have a point, so we plug in:
y = -3x +1
y = (-3)(4) +1
y =
y = -11
So A(4,-11)

77. Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3)

78. Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3)
Get the equation into y = mx + b form
5x -2y = 8

79. Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3)
Get the equation into y = mx + b form
5x -2y = 8
-2y = -5x +8

80. Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3)
Get the equation into y = mx + b form
5x -2y = 8
-2y = -5x +8
y = (5/2)x -4

81. Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3)
Get the equation into y = mx + b form
So m = (5/2)
5x -2y = 8
-2y = -5x +8
y = (5/2)x -4

82. Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3)
Get the equation into y = mx + b form
So m = (5/2)
Since we are looking for the line PARALLEL to the above equation, the slope for our new equation is also 5/2
5x -2y = 8
-2y = -5x +8
y = (5/2)x -4

83. Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3)
m = (5/2)
Now that we have our slope and a point, Plug in:
y– y1 = m ( x – x1)

84. Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3)
m = (5/2)
Now that we have our slope and a point, Plug in:
y– y1 = m ( x – x1)
y –(-3) = (5/2) (x-(-2))

85. Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3)
m = (5/2)
Now that we have our slope and a point, Plug in:
y– y1 = m ( x – x1)
y +3 = (5/2) (x+2)

86. Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3)
m = (5/2)
Now that we have our slope and a point, Plug in:
y– y1 = m ( x – x1)
y +3 = (5/2) (x+2)
y +3 = (5/2)x +5

87. Find the equation of the line that is parallel to 5x-2y=8 and passes through (-2,-3)
m = (5/2)
Now that we have our slope and a point, Plug in:
y– y1 = m ( x – x1)
y +3 = (5/2) (x+2)
y +3 = (5/2)x +5
y = (5/2)x +2

88. Find the distance of AB if A(-2,-3) and B(5,3)

89. Find the distance of AB if A(-2,-3) and B(5,3)
PLUG IN:

90. Find the distance of AB if A(-2,-3) and B(5,3)
PLUG IN:
d = √(5-(-2)) 2+ (3-(-3))2

91. Find the distance of AB if A(-2,-3) and B(5,3)
PLUG IN:
d = √(5-(-2)) 2+ (3-(-3))2
d = √(5+2) 2+ (3+3)2

92. Find the distance of AB if A(-2,-3) and B(5,3)
PLUG IN:
d = √(5-(-2)) 2+ (3-(-3))2
d = √(5+2) 2+ (3+3)2
d = √(7) 2+ (6)2

93. Find the distance of AB if A(-2,-3) and B(5,3)
PLUG IN:
d = √(5-(-2)) 2+ (3-(-3))2
d = √(5+2) 2+ (3+3)2
d = √(7) 2+ (6)2
d = √49+ 36

94. Find the distance of AB if A(-2,-3) and B(5,3)
PLUG IN:
d = √(5-(-2)) 2+ (3-(-3))2
d = √(5+2) 2+ (3+3)2
d = √(7) 2+ (6)2
d = √49+ 36
= √85

95. Find the distance of AB if A(-2,-3) and B(5,3)
PLUG IN:
d = √(5-(-2)) 2+ (3-(-3))2
d = √(5+2) 2+ (3+3)2
d = √(7) 2+ (6)2
d = √49+ 36
= √85

96. Q is the bisector of segment PR
Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R

97. Q is the bisector of segment PR
Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R
We are given the midpoint, and 1 endpoint. We must find the other endpoint.

98. Q is the bisector of segment PR
Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R
We are given the midpoint, and 1 endpoint. We must find the other endpoint.
We find the X coordinate first. PLUG IN:
x1 + x2 2
= x

99. Q is the bisector of segment PR
Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R
We are given the midpoint, and 1 endpoint. We must find the other endpoint.
We find the X coordinate first. PLUG IN:
x1 + x2 2
= x
3 + x2 2
= 3

100. Q is the bisector of segment PR
Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R
We are given the midpoint, and 1 endpoint. We must find the other endpoint.
We find the X coordinate first. PLUG IN:
x1 + x2 2
= x
3 + x2 2
= 3
3 + x2 = 6

101. Q is the bisector of segment PR
Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R
We are given the midpoint, and 1 endpoint. We must find the other endpoint.
We find the X coordinate first. PLUG IN:
x1 + x2 2
= x
3 + x2 2
= 3
3 + x2 = 6
x2 = 3

102. Q is the bisector of segment PR
Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R
We are given the midpoint, and 1 endpoint. We must find the other endpoint.
Now we find the y coordinate. PLUG IN:
x1 + x2 2
= x
y1 + y2 2
= y
3 + x2 2
= 3
3 + x2 = 6
x2 = 3

103. Q is the bisector of segment PR
Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R
We are given the midpoint, and 1 endpoint. We must find the other endpoint.
Now we find the y coordinate. PLUG IN:
x1 + x2 2
= x
y1 + y2 2
= y
3 + x2 2
= 3
4 + y2 2
= -2
3 + x2 = 6
x2 = 3

104. Q is the bisector of segment PR
Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R
We are given the midpoint, and 1 endpoint. We must find the other endpoint.
Now we find the y coordinate. PLUG IN:
x1 + x2 2
= x
y1 + y2 2
= y
3 + x2 2
= 3
4 + y2 2
= -2
3 + x2 = 6
4 + y2 = -4
x2 = 3

105. Q is the bisector of segment PR
Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R
We are given the midpoint, and 1 endpoint. We must find the other endpoint.
Now we find the y coordinate. PLUG IN:
x1 + x2 2
= x
y1 + y2 2
= y
3 + x2 2
= 3
4 + y2 2
= -2
3 + x2 = 6
4 + y2 = -4
x2 = 3
y2 = -8

106. Q is the bisector of segment PR
Q is the bisector of segment PR. If P(3,4) and Q(3,-2), find the coordinates of R
We are given the midpoint, and 1 endpoint. We must find the other endpoint.
Now we find the y coordinate. PLUG IN:
x2 = 3
y2 = -8
So R(3,-8)

107. Use the grid to complete the questions. Point A(-4,5)
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA

108. Plot your points, and find the coordinates of B and C
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
Plot your points, and find the coordinates of B and C

109. Plot your points, and find the coordinates of B and C
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
Plot your points, and find the coordinates of B and C A

110. 5 4 Plot your points, and find the coordinates of B and C
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
Plot your points, and find the coordinates of B and C A 5 4

111. Use the grid to complete the questions. Point A(-4,5)
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
So B(0,0) A 5 B 4

112. Use the grid to complete the questions. Point A(-4,5)
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
So B(0,0) A B 8

113. Use the grid to complete the questions. Point A(-4,5)
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0)
And
C(0,-8) A B 8 C

114. Use the grid to complete the questions. Point A(-4,5)
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB
d = √(0-(-4)) 2+ (0-5)2 A B C

115. Use the grid to complete the questions. Point A(-4,5)
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB
d = √(0+4) 2+ (0-5)2 A B C
d = √(4) 2+ (-5)2

116. d = √(0+4) 2+ (0-5)2 d = √(4) 2+ (-5)2 d = √16+ 25
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB
d = √(0+4) 2+ (0-5)2 A B C
d = √(4) 2+ (-5)2
d = √16+ 25

117. d = √(0+4) 2+ (0-5)2 d = √(4) 2+ (-5)2 d = √16+ 25 d = √41 ≈6.4
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB
d = √(0+4) 2+ (0-5)2 A B C
d = √(4) 2+ (-5)2
d = √16+ 25
d = √41
≈6.4

118. Segment AB= √41 d = √(0-0) 2+ (0-(-8))2
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC A B C
d = √(0-0) 2+ (0-(-8))2

119. Segment AB= √41 d = √(0-0) 2+ (0+8)2
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC A B C
d = √(0-0) 2+ (0+8)2

120. Use the grid to complete the questions. Point A(-4,5)
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC A B C
d = √(0) 2+ (8)2

121. Segment AB= √41 d = √(0) 2+ (8)2 d = √0 + 64
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC A B C
d = √(0) 2+ (8)2
d = √0 + 64

122. Segment AB= √41 d = √(0) 2+ (8)2 d = √64
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC A B C
d = √(0) 2+ (8)2
d = √64

123. Segment AB= √41 d = √(0) 2+ (8)2 d = √64 d = 8
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC A B C
d = √(0) 2+ (8)2
d = √64
d = 8

124. Segment AB= √41 Segment BC= 8
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC= 8
Segment AC A B C

125. Segment AB= √41 Segment BC= 8 d = √(0-(-4)) 2+ (-8-5)2
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC= 8
Segment AC A B C
d = √(0-(-4)) 2+ (-8-5)2

126. Segment AB= √41 Segment BC= 8 d = √(0+4) 2+ (-8-5)2
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC= 8
Segment AC A B C
d = √(0+4) 2+ (-8-5)2

127. Segment AB= √41 Segment BC= 8 d = √(0+4) 2+ (-8-5)2 d = √4 2+ (-13)2
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC= 8
Segment AC A B C
d = √(0+4) 2+ (-8-5)2
d = √4 2+ (-13)2

128. Segment AB= √41 Segment BC= 8 d = √(0+4) 2+ (-8-5)2 d = √4 2+ (-13)2
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC= 8
Segment AC A B C
d = √(0+4) 2+ (-8-5)2
d = √4 2+ (-13)2
d = √

129. Segment AB= √41 Segment BC= 8 d = √(0+4) 2+ (-8-5)2 d = √4 2+ (-13)2
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC= 8
Segment AC A B C
d = √(0+4) 2+ (-8-5)2
d = √4 2+ (-13)2
d = √

130. Segment AB= √41 Segment BC= 8 d = √(0+4) 2+ (-8-5)2 d = √4 2+ (-13)2
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now that we have our coordinates we need to find our distances.
Segment AB= √41
Segment BC= 8
Segment AC A B C
d = √(0+4) 2+ (-8-5)2
d = √4 2+ (-13)2
d = √
d = √185
≈13.6

131. Now we find the midpoint of CA Segment AB= √41 Segment BC= 8
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now we find the midpoint of CA
Segment AB= √41
Segment BC= 8
Segment AC = √185 A B C

132. Now we find the midpoint of CA Segment AB= √41 Segment BC= 8
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now we find the midpoint of CA
Segment AB= √41
Segment BC= 8
Segment AC = √185
x1 + x2 , y1 + y2 A B C

133. Now we find the midpoint of CA Segment AB= √41 Segment BC= 8
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now we find the midpoint of CA
Segment AB= √41
Segment BC= 8
Segment AC = √185
x1 + x2 , y1 + y2 A B C
-4+0, 5+-8

134. Now we find the midpoint of CA Segment AB= √41 Segment BC= 8
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now we find the midpoint of CA
Segment AB= √41
Segment BC= 8
Segment AC = √185
x1 + x2 , y1 + y2 A B C
-4, 5+-8

135. = Now we find the midpoint of CA Segment AB= √41 Segment BC= 8
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
Now we find the midpoint of CA
Segment AB= √41
Segment BC= 8
Segment AC = √185
x1 + x2 , y1 + y2 A B C
-4, 5+-8
-4, -3
2 2 =

136. = midpoint of CA = (-2, (-3/2)) Segment AB= √41 Segment BC= 8
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
midpoint of CA =
(-2, (-3/2))
Segment AB= √41
Segment BC= 8
Segment AC = √185
x1 + x2 , y1 + y2 A B C
-4, 5+-8
-4, -3
2 2 =

137. = midpoint of CA = (-2, (-3/2)) Segment AB= √41 Segment BC= 8
Use the grid to complete the questions. Point A(-4,5). Point B is located 5 units down and 4 units to the right. Point C is located 8 units down from B. Find AB, BC, AC, and the midpoint of CA
B(0,0) And C(0,-8)
midpoint of CA =
(-2, (-3/2))
Segment AB= √41
Segment BC= 8
Segment AC = √185
x1 + x2 , y1 + y2 A B C
-4, 5+-8
-4, -3
2 2 =

138. Using the above questions,Find the perimete of triangle ABC
Segment AB= √41
≈6.4
Segment BC= 8
≈13.6
Segment AC = √185 A B C

139. Find the perimete of triangle ABC
≈6.4
Segment AB= √41 A B C
Segment BC= 8
≈13.6
Segment AC = √185
Now that we have the lengths of the three sides, we can find the perimeter.

140. Find the perimete of triangle ABC
Segment AB= √41
≈6.4 A B C
Segment BC= 8
≈13.6
Segment AC = √185
Now that we have the lengths of the three sides, we can find the perimeter.
AB + BC + AC = Perimeter

141. Find the perimete of triangle ABC
Segment AB= √41
≈6.4 A B C
Segment BC= 8
≈13.6
Segment AC = √185
Now that we have the lengths of the three sides, we can find the perimeter.
AB + BC + AC = Perimeter =P

142. Find the perimete of triangle ABC
Segment AB= √41
≈6.4 A B C
Segment BC= 8
≈13.6
Segment AC = √185
Now that we have the lengths of the three sides, we can find the perimeter.
AB + BC + AC = Perimeter =P
P=28

143. Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept

144. Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept
Since the function is given, USE THE CALCULATOR
Go to y= and plug in the function

145. Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept
Since the function is given, USE THE CALCULATOR
Go to y= and plug in the function
To find the vertex,
Hit graph
2nd TRACE to get to CALC
3-minimum
Go to left hit ENTER
Go to right hit ENTER
ENTER
Displays x=2, y=2 so the VERTEX is (2,2)

146. Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept
To get the axis of symmetry
Use the x value of the vertex[(2,2)] is the axis of symmetry

147. Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept
To get the axis of symmetry
Use the x value of the vertex[(2,2)] is the axis of symmetry
So the axis of symmetry is x=2

148. Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept
To find the y intercept:
Hit 2nd, GRAPH to get to TABLE
Look at the table and find where x=0, what is y?

149. Use the function y=x2-4x+6 to find the vertex, the axis of symmetry, and the y intercept
To find the y intercept:
Hit 2nd, GRAPH to get to TABLE
Look at the table and find where x=0, what is y?
x=0, y=6
So the y intercept is (0,6)