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Molecular Composition of Gases
Chapter 11 Chemistry Chapter 11
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Gay-Lussac’s law of combining volumes of gases
At constant temperature and pressure, the volumes of gaseous reactants and products can be expressed as ratios of small whole numbers Chemistry Chapter 11
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Example When 2 L of hydrogen react with 1 L of oxygen 2 L of water vapor are produced. Write the balanced chemical equation: Chemistry Chapter 11
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You try When 1 L of hydrogen gas reacts with 1 L of chlorine gas, 2 L of hydrogen chloride gas are produced. Write the balanced chemical equation: Chemistry Chapter 11
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Avogadro's Law Equal volumes of gases at the same pressure and temperature contain the same number of molecules Atoms can’t split diatomic molecules Gas volume is proportional to the number of molecules Chemistry Chapter 11
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Molar Volume 1 mole of any gas contains 6.022 x 1023 molecules.
According to Avogadro’s law, 1 mole of any gas must have the same volume. Standard molar volume: volume of 1 mole of any gas at STP 22.4 L Chemistry Chapter 11
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Example You are planning an experiment that requires mol of nitrogen monoxide gas. What volume in liters is occupied by this gas at STP? 1.30 L NO Chemistry Chapter 11
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You try A chemical reaction produces 2.56 L of oxygen gas at STP. How many moles of oxygen are in this sample? 0.114 mol O2 Chemistry Chapter 11
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Example Suppose you need 4.22 g of chlorine gas. What volume at STP would you need to use? 1.33 L Cl2 Chemistry Chapter 11
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You try What is the mass of 1.33 x 104 mL of oxygen gas at STP?
19.0 g O2 Chemistry Chapter 11
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Discuss Explain Gay-Lussac’s law of combining volumes
State Avogadro’s law and explain its significance. Chemistry Chapter 11
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Review Boyles Law: Charles Law: Avogadro’s Law: Chemistry Chapter 11
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Math A quantity that is proportional to each of several quantities is also proportional to their product. Therefore: Chemistry Chapter 11
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More math Convert a proportionality
to an equality by multiplying by a constant Chemistry Chapter 11
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Therefore We can covert to Chemistry Chapter 11
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More neatly Chemistry Chapter 11
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This means…. The volume of a gas varies directly with the number of moles and the temperature in Kelvin. The volume varies indirectly with pressure. Chemistry Chapter 11
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What if… n and T are constant? n and P are constant?
nRT is a constant, k Boyle’s Law n and P are constant? nR/P is a constant, k Charles’s Law Chemistry Chapter 11
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What if… P and T are constant? RT/P is a constant, k Avogadro’s law
Chemistry Chapter 11
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The ideal gas constant R Value depends on units SI units:
Chemistry Chapter 11
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Other units Chemistry Chapter 11
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Solving ideal gas problems
Make sure the R you use matches the units you have. Make sure all your units cancel out correctly. Chemistry Chapter 11
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Example A 2.07 L cylinder contains 2.88 mol of helium gas at 22 °C. What is the pressure in atmospheres of the gas in the cylinder? 33.7 atm Chemistry Chapter 11
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You try A tank of hydrogen gas has a volume of 22.9 L and holds 14.0 mol of the gas at 12 °C. What is the reading on the pressure gauge in atmospheres? 14.3 atm Chemistry Chapter 11
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Example A reaction yields mol of oxygen gas. What volume in mL will the gas occupy if it is collected at 43 °C and atm pressure? 240. mL Chemistry Chapter 11
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You try A researcher collects 9.09 x 10-3 mol of an unknown gas by water displacement at a temperature of 16 °C and atm pressure (after the partial pressure of the water vapor has been subtracted). What volume of gas in mL does the researcher have? 247 mL Chemistry Chapter 11
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Finding mass Number of moles (n) equals mass (m) divided by molar mass (M). Chemistry Chapter 11
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Example What mass of ethene gas, C2H4, is contained in a 15.0 L tank that has a pressure of 4.40 atm at a temperature of 305 K? 74.0 g Chemistry Chapter 11
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You try NH3 gas is pumped into the reservoir of a refrigeration unit at a pressure of 4.45 atm. The capacity of the reservoir is 19.4 L. The temperature is 24 °C. What is the mass of the gas in kg? 6.03 x 10-2 kg Chemistry Chapter 11
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Example A chemist determines the mass of a sample of gas to be 3.17 g. Its volume is 942 mL at a temperature of 14 °C and a pressure of 1.09 atm. What is the molar mass of the gas? 72.7 g/mol Chemistry Chapter 11
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Density Chemistry Chapter 11
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You try The density of dry air at sea level (1 atm) is g/L at 15 °C. What is the average molar mass of the air? 29.0 g/mol Chemistry Chapter 11
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Stoichiometry Involves mass relationships between reactants and products in a chemical reaction For gases, the coefficients in the balanced chemical equation show volume ratios as well as mole ratios All volumes must be measured at the same temperature and pressure Chemistry Chapter 11
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Volume-Volume calculations
From volume of one gas to volume of another gas Use volume ratios just like mole ratios in chapter 9 Chemistry Chapter 11
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Example Xenon gas reacts with fluorine gas to produce the compound xenon hexafluoride, XeF6. Write the balanced equation for this reaction. Xe(g) + 3F2(g) XeF6(g) If a researcher needs 3.14 L of XeF6 for an experiment, what volumes of xenon and fluorine should be reacted? 3.14 L of Xe and 9.42 L of F2 Chemistry Chapter 11
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Example Nitric acid can be produced by the reaction of gaseous nitrogen dioxide with water. 3NO2(g) + H2O(l) 2HNO3(l) + NO(g) If 708 L of NO2 gas react with water, what volume of NO gas will be produced? 236 L Chemistry Chapter 11
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You try What volume of hydrogen gas is needed to react completely with 4.55 L of oxygen gas to produce water vapor? 9.10 L Chemistry Chapter 11
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You try At STP, what volume of oxygen gas is needed to react completely with 2.79 x 10-2 mol of carbon monoxide gas, CO, to form gaseous carbon dioxide? 0.312 L Chemistry Chapter 11
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You try Fluorine gas reacts violently with water to produce hydrogen fluoride and ozone according to the following equation: 3F2(g) + 3H2O(l) 6HF(g) + O3(g) What volumes of O3 and HF gas would be produced by the complete reaction of 3.60 x 104 mL of fluorine gas? 1.20 x 104 mL O3 and 7.20 x 104 mL HF Chemistry Chapter 11
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You try Ammonia is oxidized to make nitrogen monoxide and water 4NH3(g) + 5O2(g) 4NO(g) + 6H2O(l) At STP, what volume of oxygen will be used in a reaction of 125 mol of NH3? What volume of NO will be produced? 3.50 x 103 L O2 and 2.80 x 103 L NO Chemistry Chapter 11
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Volume-mass and mass-volume
Converting from volume to mass or from mass to volume Must convert to moles in the middle Ideal gas law may be useful for finding standard conditions Chemistry Chapter 11
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Example Aluminum granules are a component of some drain cleaners because they react with sodium hydroxide to release both heat and gas bubbles, which help clear the drain clog. The reaction is: 2NaOH(aq) + 2Al(s) + 6H2O (l) 2NaAl(OH)4(aq) + 3 H2(g) What mass of aluminum would be needed to produce 4.00 L of hydrogen gas at STP? 3.21 g Chemistry Chapter 11
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Example Air bags in cars are inflated by the sudden decomposition of sodium azide, NaN3 by the following reaction: 2NaN3(s) 3N2(g) + 2Na(s) What volume of N2 gas, measured at 1.30 atm and 87 °C, would be produced by the reaction of 70.0 g of NaN3? 36.6 L Chemistry Chapter 11
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You try What volume of chlorine gas at 38°C and 1.63 atm is needed to react completely with 10.4 g of sodium to form NaCl? 3.54 L Cl2 Chemistry Chapter 11
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Example A sample of ethanol burns in O2 to form CO2 and H2O according to the following reaction. C2H5OH + 3O2 2CO2 + 3H2O If the combustion uses 55.8 mL of oxygen measured at 2.26 atm and 40.°C, what volume of CO2 is produced when measured at STP? 73.3 mL CO2 Chemistry Chapter 11
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You try Dinitrogen pentoxide decomposes into nitrogen dioxide and oxygen. If 5.00 L of N2O5 reacts at STP, what volume of NO2 is produced when measured at 64.5 °C and 1.76 atm? 7.02 L NO2 Chemistry Chapter 11
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Review Diffusion: the gradual mixing of gases due to their random motion Effusion: gases in a container randomly pass through a tiny opening in the container Chemistry Chapter 11
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Rate of effusion Depends on relative velocities of gas molecules.
Velocity varies inversely with mass Lighter particles move faster Chemistry Chapter 11
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Kinetic energy Depends only on temperature Equals
For two gases, A and B, at the same temperature Each M stands for molar mass Chemistry Chapter 11
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Algebra time Chemistry Chapter 11
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Rate of effusion Depends on relative velocities of gas molecules.
Chemistry Chapter 11
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Graham’s law of effusion
The rates of effusion of gases at the same temperature and pressure are inversely proportional to the square roots of their molar masses. Chemistry Chapter 11
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Graham’s law Graham experimented with densities of gases, not molar masses. Density and molar mass are directly proportional So we can replace molar mass with density in the equation Chemistry Chapter 11
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Use of Graham’s law Finding the molar mass
Compare rates of effusion of a gas with known molar mass and a gas with unknown molar mass Use Graham’s law equation to solve for the unknown M Used to separate isotopes of uranium Chemistry Chapter 11
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Example Compare the rates of effusion of hydrogen and helium at the same temperature and pressure. Hydrogen diffuses about 1.41 times faster Chemistry Chapter 11
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Example Nitrogen effuses through a pinhole 1.7 times as fast as another gaseous element at the same conditions. Estimate the other element’s molar mass and determine its probable identity. 81 g/mol, krypton Chemistry Chapter 11
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You try Estimate the molar mass of a gas that effuses at 1.6 times the effusion rate of carbon dioxide. 17 g/mol Chemistry Chapter 11
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