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Ch. 14.3 – Ideal Gases -Avogadro’s Law (extension) -STP & molar volume of gas (review) -Ideal Gas Law (most important)

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Presentation on theme: "Ch. 14.3 – Ideal Gases -Avogadro’s Law (extension) -STP & molar volume of gas (review) -Ideal Gas Law (most important)"— Presentation transcript:

1 Ch – Ideal Gases -Avogadro’s Law (extension) -STP & molar volume of gas (review) -Ideal Gas Law (most important)

2 Avogadro’s Law Equal volumes of gases contain equal numbers of molecules (moles) at constant temp & pressure true for any gas V n

3 22.4 L Volume of Gas at STP At 1 atm and 273 K the volume of 1 mol
According to Avogadro’s law, 1 mole of any gas will occupy the same volume as one mole of any other gas at the same temperature and pressure At 1 atm and 273 K the volume of 1 mol of gas is 22.4 L

4 Volume of Gas at STP

5 PV=nRT P= pressure (atm) V=volume (L) n= number of moles
Ideal Gas Law PV=nRT P= pressure (atm) V=volume (L) n= number of moles R=universal gas constant T=temperature in Kelvins

6 PV = nRT (at STP and 1 mole)
How do we get R PV = nRT (at STP and 1 mole) (1.0 atm)(22.4L) = (1 mole)(R)(273K) (1.0 atm)(22.4L) = R (1 mole)(273K)

7 Universal Gas Constant R
R = Latm/molK or R = J/molK

8 Ideal Gas Law Problems P = ? atm n = 0.412 mol T = 16°C = 289 K
Calculate the pressure in atmospheres of mol of He at 16°C & occupying L. GIVEN: P = ? atm n = mol T = 16°C = 289 K V = 3.25 L R = Latm/molK WORK: PV = nRT P(3.25)=(0.412)(0.0821)(289) L mol Latm/molK K P = 3.01 atm

9 Cool Down What pressure is exerted by mol of gas at 25 C if the gas is in a L container? P = 16.9 atm


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