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Efficiency of Heat Engines
Thermodynamics Efficiency of Heat Engines
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The Second Law of Thermodynamics
In an ideal cyclic process, internal energy is conserved Net work = net heat flow Wnet = Qnet = Qh – Qc Qh is the heat absorbed by the heat engine or refrigerator or whatever Qc is the heat given up to the surroundings
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The Second Law of Thermodynamics
Based on this, a heat engine could do more work on a hot day than it could a cold day and could always perform work as long as the engine’s temperature was less than the surrounding air temperature This situation never happens
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The Second Law of Thermodynamics
The second law of thermodynamics – no cyclic process that converts heat entirely into work is possible Some energy must always be transferred to the surroundings as heat
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Thermodynamic Efficiency
Efficiency is a rating of how well an engine works What percentage of heat absorbed is converted to useful work Efficiency = net work done by engine / energy added as heat Efficiency = (energy added as heat – energy removed as heat) / energy added as heat Efficiency = 1 – energy removed as heat / energy added as heat Efficiency = 1 – temperature of cold reservoir / temperature of hot reservoir eff = Wnet/Qh = (Qh-Qc)/Qh = 1-Qc/Qh = 1- (Tcold / Thot) You can multiply by 100 to get a percentage
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Laws of Thermodynamics
0th - You must play the game 1st – You can’t win, you can only break even 2nd – You can’t break even 3rd – You can’t quit the game
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