1. Credit Bearings Questions.

2. 2001 Paper 2 Question 6.
Three radio masts K , W and P are situated in the Australian outback.
K is 250 km due south of w xo
W is 410 km from P w
410km
P is on a bearing of 130o from K.
250km
130o k p
Calculate the bearing of P from W

3. w k p
250km
410km
130o xo
Find angle yo zo
Use sine rule.
250
410 =
solve
Sin y
Sin 130o yo
Yo = 27.8o
Now calculate Xo
Find angle zo
= 180-( )= 22.2o
180 –22.2
= 157.8o
Hence angle xo =

4. Model Paper F Credit. N Q A ship at P observes a lighthouse at Q 40o
on a bearing of 040o.
The ship travels 30km
on a bearing
of 125o d
85o P
(125 – 40 = 85o)
The ship
Observes the lighthouse on a bearing of 340o
From position R
30km R
(360 –340 = 20o)
When the ship is at position R how far is it from the lighthouse?
Ship to lighthouse distance = d

5. d N P
40o
30km
85o R
20o Q
The problem requires us to find the triangle angle at corner R.
60o
Extend the North line and consider alternate angles.
35o
Angle PRS =
125o
125o
Now calculate angle QRP
=180 – ( ) = 35o S
Now calculate angle PQR.
=180 – ( 85+35) = 60o

6. Yes it really can be this hard !!!!
At this stage re-draw your diagram with the interior angle information and distances only. N
85o
60o
35o
30km d
Now use sine rule to find d.
30km d =
solve
Sin 60o
Sin 85o
d =
34.5km
Yes it really can be this hard !!!!