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Torque Wrench
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Torque calculation 30cm pivot 10N ⏆ = F⏊d ⏆ = (10)⏊(.3) ⏆ = 3 Nm
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Torque calculation 1 ? F ⏊ Sin ⍬ = O/h O = sin ⍬ (h) O = sin 60 (10)
F ⏊ = 8.66 N ⏆ = F⏊d 8.66 N (.3) = 2.60 Nm
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Approaches to Torque Where is the pivot point?
What was the force applied ⏊ to the axis of rotation? How far from the pivot point was the force applied? Consider the sign conventions for the torque: Clockwise is NEGATIVE Counterclockwise is POSITIVE *do not blame me – I did not make it up!!!!
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Torque calculation 2 - + F⏊ = 40 cos ⍬ = 40 cos 50 F⏊ = 60N cos ⍬
⏆ = F⏊d = 40N (cos 50) (.2m) = Nm ⏆ = F⏊d = 60N (cos 50) (.1m) = Nm Sum: 3.86 – 5.14 = Nm
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Torque calculation 3 try this one on your own
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Torque calculation 3 - + + ⏆ = F⏊d = + 40N 1m F⏊ = 60N sin 40 = +40 Nm
⏆ total = = + 21 Nm
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