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AP Calculus Chapter 1, Section 5
Infinite Limits
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Graph the function π π₯ = 3 π₯β2
Evaluate the limit from the left and the right as the function approaches 2.
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A limit in which f(x) increases or decreases without bound as x approaches c is called an infinite limit. Just because you see the equal sign in lim f(x)=β doesnβt mean the limit exists. As you learned, the limit fails to exist since there is unbounded behavior.
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Graph the equation. Find the value of c that does not exist in the domain. Then find the limit as the function approaches c from the left and right. π π₯ = 3 π₯β4
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π π₯ = 1 2βπ₯
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π π₯ = 2 (π₯β3) 2
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π π₯ = β3 (π₯+2) 2
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Vertical Asymptotes Vertical asymptotes occur when the denominator is equal to 0 (and the numerator is not 0). Function will never touch an asymptote, but will forever become arbitrarily close.
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Find the vertical asymptotes of the given functions.
π π₯ = 1 2(π₯+1) π π₯ = π₯ π₯ 2 β1 π π₯ = cot π₯
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Determine all vertical asymptotes and discuss the limit of the function as it approaches the VA from the left and right π π₯ = π₯ 2 +2π₯β8 π₯ 2 β4
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Properties of Infinite Limits
Let c and L be real numbers and let f and g be functions such that lim π₯βπ π(π₯) =β and lim π₯βπ π π₯ =πΏ Sum or difference: lim π₯βπ π π₯ Β±π π₯ =β Product: lim π₯βπ π π₯ π π₯ =β , πΏ>0 lim π₯βπ π π₯ π π₯ =ββ , πΏ<0 Quotient: lim π₯βπ π(π₯) π(π₯) =0 Similar properties hold for one-sided limits and for functions for which the limit f(x) as x approaches c is -β.
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Because lim π₯β0 1=1 and lim π₯β0 π₯ 2 =β , you can write lim π₯β0 1+ 1 π₯ 2 =β
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Because lim π₯β 1 β π₯ 2 +1 =2 and lim π₯β 1 β ( cot ππ₯)=ββ , you can write lim π₯β 1 β π₯ 2 +1 cot ππ₯ =0
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Because lim π₯β 0 + 3=3 and lim π₯β 0 + cot π₯ =β, you can write lim π₯β 0 + 3 cot π₯=β
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Before you leave class, page 90 #65
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Homework Pg. 88 β 90: #βs 1 β 49 every other odd, 59, 67,
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