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Predicting Products
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Single Displacement Use activity series of metals
If metal C is more active than A, then it replaces less active metal A. AB + C CB + A If metal F is less reactive than metal D, it cannot bump off D & reaction does not occur DE + F no reaction
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Activity Series p 148 General Trends of metal activity (how well they can displace): Lighter metals bump off heavier metals Metals with +1 charges will bump metals with +2 charges How to read table 4-12: the higher up a metal, the more active it is. Not perfect trends: Ca2+ displaces Na+
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NaCl + F2 ---> NaF + Cl2 NaF + Cl2 ---> No reaction
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MgCl2 + Na KBr + Cl2 FeCl3 + Cu Na2SO4 + Cu
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Double Displacement or Metathesis
Use solubility tables p134 – 135 For rxn to occur, precipitate (ppt) must form
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BaCl2(aq)+ K2SO4(aq) -----> BaSO4(s)+ KCl(aq)
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3 ways to write reactions (when they’re in aqueous solutions): (p136)
Formula unit equations 2 AgNO3 (aq) + Cu (s) 2 Ag (s) + Cu(NO3) (aq) Total Ionic equations 2 [Ag+(aq) + NO3- (aq)] + Cu(s) 2 Ag (s) + [Cu+(aq) + 2NO3- (aq) Net Ionic equations 2 Ag+ (aq) + Cu (s) 2 Ag (s) + Cu2+ (aq)
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NaCl(aq) + KBr(aq) -----> NaBr(aq) + KCl(aq)
How is this reaction written? Rewrite as total ionic. Can you rewrite as net ionic? No! Only spectator ions!
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Na+ (aq) + Cl- (aq) + K+ (aq) + Br- (aq). ----->
Na+ (aq) + Cl- (aq) + K+ (aq) + Br- (aq) > Na+ (aq) Br- (aq) + K+ (aq) + Cl- (aq)
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DD or Metathesis Acid-base:
When an acid is combined with a base, the products will be salt & water
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HCl(aq) + NaOH(aq) -----> NaCl(aq) + H2O(l)
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Mg(OH)2(aq) + H2SO4(aq) MgSO4(aq) + H2O(l)
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Ba(OH)2(aq) + CaCl2(aq) ZnCl2(aq) + K2CrO4(aq) KCl(aq) + Na2SO4(aq)
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HCl(aq) + NaOH(aq) H2SO4(aq) + KOH(aq) HCl(aq) + NH3(aq)
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Carbon compound + oxygen yields Carbon dioxide & water
Combustion Carbon compound + oxygen yields Carbon dioxide & water
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C3H6(g) + O2(g) C4H8O(l) + O2(g) C4H8O4(g) + O2(g)
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Predict Products & Balance Rxn
CaCl2 + F2 CaCl2 + Na CaCl2 + KNO3 CaCl2 + K2SO4
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Predict & Balance AlBr3 + F2 AlBr3 + Zn AlBr3 + Na
AlBr3 + Ba(NO3)2 AlBr3 + K2SO4
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Calculate the mass of solid product formed when 4
Calculate the mass of solid product formed when 4.16 g of barium chloride is added to 250 ml of 0.40 M potassium sulfate:
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