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Restrictions on sums over

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1 Restrictions on sums over
Yiannis Koutis Computer Science Department Carnegie Mellon University

2 Vectors over p: prime d: dimension of the vectors
point-wise multiplication mod p p = 3, d=3

3 Work on sum of vectors f(n,1) = 2n-1 [ Erdos, Ginzburg, Ziv]
f(n,d) : the minimum number such that every subset of has a sub-subset that sums up to f(n,1) = 2n-1 [ Erdos, Ginzburg, Ziv] f(n,d) · cd n [Alon, Dubiner] f(n,d) ¸ (9/8)d/3 (n-1)2d+1 [Elsholtz] f(n,2) = ? [conjectured equal to 4n-3]

4 dimensionality restrictions
is an arbitrary subset of size p(d+2) numbers of subsets of A summing up to what is the probability that the number of zero-sum subsets of A is odd, when p=2? how smaller can the number of zero-sum subsets be, than then number of v-sum subsets?

5 dimensionality restrictions
is an arbitrary subset numbers of subsets of A summing up to what is the probability that the number of 0-sum subsets of A is odd, when p=2? [ prob = 1 ] how smaller can the number of zero-sum subsets be, than then number of v-sum subsets? [zero is attractive : worst case one less ]

6 motivation The Set Packing problem: Given a collection C of sets on a universe U of n elements, is there a sub-collection of k mutually disjoint sets ? Algebraization: Assign variables xi to the elements of U for each set S, let

7 motivation Let If there are k disjoint terms, there is a multilinear term. If not, fk is in the ideal <x12,x2,2,..>

8 example Define the sets Then :

9 motivation Let If there are k disjoint terms, there is a multilinear term. If not, fk is in the ideal <x12,x2,2,..> Basic idea: evaluate fk over a ‘small’ commutative ring with a polynomial number of operations and exploit the squares

10 example Assign distinct to element i and substitute v0+xvi in xi
Then for every i If there is no set packing of size k, then fk is a multiple of (1+x)2 How large must d be so that the multilinear term is not a multiple of (1+x)2 ? [must be linear, unfortunately]

11 representation theory for
each element is represented by a matrix addition is isomorphic to matrix multiplication 1-1: elements with entries in the first row

12 representation theory for
The coefficient of xi in H(1,j) is the number of vj-sum sets of cardinality i in A. For x=1, H(1,1) = #zero-sum+1 H(1,j) = #vj-sum

13 representation theory for
All matrices  are simultaneously diagonalizable V is a Hadamard matrix, every entry is 1 or -1 () is diagonal, containing the eigenvalues which are all 1 and -1

14 parity of zero sum subsets
For x=1, H(1,1) = #zero-sum+1, H(1,j) = #vj-sum Each matrix (I+() ) has eigenvalues 0 and 2 For d +1 terms in the product, the eigenvalues are either 0 or 2d+1. All entries of H are even. #zero-sum+1 = even , #vj-sum=even

15 number of zero-sum subsets
2dH(1,1) = trace(H) = sum of eigenvalues 2dH(1,j) = weight eigenvalues by 1 and -1 H(1,1)¸ H(1,j) [zero is attractive : #zero sum +1 ¸ #vj-sum]

16 restrictions on sums Let N(v,k) be the number of v-sum subsets of cardinality k Theorem: Given N(v,2t) mod 2,for 1· t · 2log n, the numbers N(v,2t) mod 2, for t>2log n can be determined completely .

17 restrictions on sums - outline
Form Also v’ has only a 1 in the extra dimension The coefficient aj of xj in H’, is zero mod 2 when j¸ 4d aj is a linear combination of the coefficients of xj for j\leq 4d in H

18 restrictions on sums Let N(v,k) be the number of v-sum subsets of cardinality k Theorem: Given N(v,2t) mod 2,for 1· t · 2log n, the numbers N(v,2t) mod 2, for t>2log n can be completely determined. Question: What are the ‘admissible’ values for the 2log n free numbers, over selections ?

19 generalizations to

20 conclusions – back to motivation
Assign distinct to element i and substitute v0+xvi in xi Then for every i If there is no set packing of size k, then fk is a multiple of (1+x)2 How large must d be so that the multilinear term is not a multiple of (1+x)2 ? [must be linear, unfortunately]

21 conclusions – back to motivation
If there is no set packing of size k, then fk is a multiple of (1+x)2 But now, we know that fk must also satisfy many linear restrictions Question: Can we exploit this algorithmically?


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