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The Equilibrium Expression and the Equilibrium Constant (p.57m)
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Eqm Constant & Expression (p.57)
Remember questions 6 & 7 from earlier in this unit where we graphed [A] and [B]? The ratio of [B]/[A] was 5.0 and after we added some B the eqm shifted but the ratio remained equal to 5.0 What one finds is that for the general rxn: a A + b B c C + d D is that The expression is called the eqm expression while the value of Keq is called the eqm constant [C]c x [D]d [A]a x [B]b Keq = a constant =
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Characteristics of Eqm (p.40m)
Let’s look at the eqm A B where we start with lots of A and no B. Plotting the [A] and [B] on p. 40 you get:
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Examples (p.57m) H2O(g) + CO(g) H2(g) + CO2(g)
PCl5(g) PCl3(g) + Cl2(g) H2(g) + F2(g) 2 HF(g) Note that 2 HF is the same as HF + HF [H2] x [CO2] [H2O] x [CO] Keq = [PCl3] x [Cl2] [PCl5] Keq = [HF]2 [H2] x [F2] Keq =
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One More Thing… (p.58m) Consider CaF2(s) Ca2+(aq) + 2 F-(aq)
You might expect to include [CaF2] but CaF2 has a constant density of 3.18 x 103 g/L We can convert this to a molar concentration [CaF2] = 40.7 M (this is a constant) The Keq value is 8.4 x (also a constant) Rather than have 2 constants, we can combine them [Ca2+] x [F-]2 40.7 Keq = 8.4 x = Keq = 3.4 x = [Ca2+] x [F-]2
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General Rule (p.59t) Things that have a constant concentration are not included in the eqm expression (their molarities are already included in the constant’s value) What things have a constant [ ] ? Solids Pure liquids (a liquid is pure if it is the only liquid on either side of the eqn) Everything else must be included: Gases, aqueous ions, mixtures of liquids
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Examples (p.59m) Br2(l) + H2(g) 2 HBr(g)
CH3COCH3(l) + Cl2(g) CH3COCH2Cl(l) + HCl(g) Cl2(g) + 8 H2O(l) Cl2•8H2O(s) Note that solids and pure liquids have no effect on shifting eqm when added b/c [ ] = constant [HBr]2 [H2] Keq = [CH3COCH2Cl][HCl] [CH3COCH3][Cl2] Keq = 1 [Cl2] Keq =
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LeChat’s Principle and Keq (p.61t)
When conc. or pressure is changed, the system will readjust to the same Keq. The only factor that changes Keq is temperature. A change in temp ALWAYS changes the value of Keq. If you look at the graphs from the last lesson, you should be able to see that this can make sense.
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Example (p.61m) For the eqm:
2 NO(g) + Cl2(g) 2 NOCl(g) + 76 kJ a decrease in temp shifts eqm right, therefore, [NOCl] goes up while [NO] and [Cl2] go down. Since Keq is [products]/[reactants], the value of Keq increases. If a rxn shifts to reactants, Keq decreases.
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Meaning of the Size of Keq (p.61b)
If Keq = 1 then the ratio of [products] / [reactants] is equal. If Keq is large (> 1) then there must be a large amount of products present at eqm. If Keq is small (< 1) there must be a small amount of products present at eqm.
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Homework Hebden #31 odds, 32, 34, 35 odds, 36-38, 40, 44-46.
Quiz on Friday.
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