Download presentation
Presentation is loading. Please wait.
Published byMadlyn Hopkins Modified over 5 years ago
1
Solve Quadratic Equations by Finding Square Roots Lesson 1.5
Honors Algebra 2 Solve Quadratic Equations by Finding Square Roots Lesson 1.5
2
Goals Goal Rubric Simplify radicals. Rationalize the denominator.
Solve Quadratic Equations by finding square roots. Level 1 – Know the goals. Level 2 – Fully understand the goals. Level 3 – Use the goals to solve simple problems. Level 4 – Use the goals to solve more advanced problems. Level 5 – Adapts and applies the goals to different and more complex problems.
3
Vocabulary Square root Radical Radicand Rationalizing the denominator
Conjugates
4
These numbers are called the
Perfect Squares The terms of the following sequence: 1, 4, 9, 16, 25, 36, 49, 64, 81… 12,22,32,42, 52 , 62 , 72 , 82 , 92… These numbers are called the Perfect Squares.
5
Square Roots The number r is a square root of s, if r2 = s.
This is usually written 𝑠 =𝑟. Any positive number has two real square roots, one positive and one negative, 𝑠 and − 𝑠 = 2 and -2, since 22 = 4 and (-2)2 = 4 The positive square root is called the principal square root. The expression 𝑠 is called a radical. The symbol is a radical sign. The number or expression under the radical symbol is called the radicand.
6
Properties of Square Roots
Square roots have special properties that help you simplify, multiply, and divide them.
7
Simplifying Square Root
The properties of square roots allow us to simplify radical expressions. A radical expression is in simplest form when: The radicand has no perfect-square factor other than 1. and There’s no radical in the denominator.
8
EXAMPLE 1 Use properties of square roots Simplify the expression. a. 80 5 16 = 5 = 4 b. 6 21 126 = 9 14 = = 3 14 c. 4 81 = 4 81 = 2 9 d. 7 16 = 7 16 = 4 7
9
GUIDED PRACTICE Your Turn: for Example 1 27 3 98 2
Simplify the expression. 27 3 ANSWER 98 2 7 ANSWER
10
GUIDED PRACTICE Your Turn: for Example 1 10 15 6 5 8 28 14
Simplify the expression. 10 15 ANSWER 6 5 8 28 ANSWER 14 4
11
GUIDED PRACTICE Your Turn: for Example 1 9 64 3 8 15 4 2 15
Simplify the expression. 9 64 3 8 ANSWER 15 4 2 15 ANSWER
12
GUIDED PRACTICE Your Turn: for Example 1 11 25 5 11 36 49 7 6
Simplify the expression. 11 25 5 11 ANSWER 36 49 7 6 ANSWER
13
Rationalizing the Denominator
If a fraction has a denominator that is a square root, you simplify it by rationalizing the denominator. To do this, multiply both the numerator and denominator by a number that produces a perfect square under the radical sign in the denominator. That simplifies to a rational number.
14
Rationalizing the Denominator
For a fraction with a denominator of the 𝑏 or 𝑎± 𝑏 , The table below shows how to eliminate the radical from the denominator. The expressions 𝑎+ 𝑏 and 𝑎− 𝑏 are conjugates. The product of conjugates is always a rational number.
15
EXAMPLE 2 Rationalize denominators of fractions. 5 2 3 7 + 2 Simplify (a) and (b) SOLUTION (a) 5 2 = 5 2 = 5 2 2 10 =
16
EXAMPLE 2 Rationalize denominators of fractions. SOLUTION = 3 7 + 2 7 – (b) 3 7 + 2 = 21 – 3 2 49 – – 2 = 21 – 3 2 47
17
GUIDED PRACTICE Your Turn: for Example 2 6 5 9. 5 30 9 8 10. 2 4 3
Simplify the expression. 6 5 9. 5 30 ANSWER 9 8 10. 2 4 3 ANSWER
18
GUIDED PRACTICE Your Turn: for Example 2 17 12 11. 51 6 19 21 399 21
Simplify the expression. 17 12 11. 51 6 ANSWER 19 21 399 21 ANSWER
19
Your Turn: for Example 2 – 6 7 – 5 – 21 – 3 5 22 2 4 + 11 8 – 2 11 5
Simplify the expression. – 6 7 – 5 – 21 – 3 5 22 ANSWER 2 4 + 11 8 – 2 11 5 ANSWER
20
Your Turn: for Example 2 – 1 9 + 7 – 9 + 7 74 4 8 – 3 32 + 4 3 61
Simplify the expression. – 1 9 + 7 – 9 + 7 74 ANSWER 4 8 – 3 32 + 4 3 61 ANSWER
21
Solving Quadratic Equations by Finding Square Roots
Some types of quadratic equations can be solved by finding square roots. Quadratic equations of the form x2 = s (the equation contains a perfect square term and has no linear term), where x is an algebraic expression and s is a nonzero real number, can be solved by finding Square Roots. If x is an algebraic expression and s is a nonzero real number, then x2 = s has exactly two solutions: 𝑥= 𝑠 or 𝑥=− 𝑠 Equivalently, if x2 = s, then 𝑥=± 𝑠 .
22
Solving Quadratic Equations by Finding Square Roots
Procedure Step 1: Isolate the expression containing the square term. Step 2: Take the square root of both sides of the equation. Don’t forget the symbol. Step 3: If necessary, isolate the variable and solve. Step 4: Check. Verify your solutions.
23
EXAMPLE 3 Solve 3x2 + 5 = 41. 3x2 + 5 = 41 3x2 = 36 x2 = 12 x = + 12
Solve a quadratic equation Solve 3x2 + 5 = 41. 3x2 + 5 = 41 Write original equation. 3x2 = 36 Subtract 5 from each side. x2 = 12 Divide each side by 3. x = + 12 Take square roots of each side. x = + 4 3 Product property x = + 2 3 Simplify.
24
The solutions are – 3 + and – 3 – 35
EXAMPLE 4 Standardized Test Practice 1 5 (z + 3)2 = 7 Write original equation. (z + 3)2 = 35 Multiply each side by 5. z + 3 = + 35 Take square roots of each side. z = – 3 + 35 Subtract 3 from each side. The solutions are – and – 3 – 35 The correct answer is C.
25
Your Turn: for Examples 3, and 4 5x2 = 80 The solutions are and . 4 –
Solve the equation. 5x2 = 80 ANSWER The solutions are and . 4 – z2 – 7 = 29 ANSWER The solutions are and . 6 – 3(x – 2)2 = 40 The solutions are 2 30 3 2 + ANSWER
26
EXAMPLE 5 Model a dropped object with a quadratic function Science Competition For a science competition, students must design a container that prevents an egg from breaking when dropped from a height of 50 feet. How long does the container take to hit the ground ?
27
EXAMPLE 5 h = – 16t 2 + h0 0 = – 16t 2 + 50 – 50 = – 16t 2 50 16 50 +
Model a dropped object with a quadratic function SOLUTION h = – 16t 2 + h0 Write height function. 0 = – 16t Substitute 0 for h and 50 for h0. – = – 16t 2 Subtract 50 from each side. 50 16 = t2 Divide each side by – 16. 50 16 + = t Take square roots of each side. t Use a calculator.
28
EXAMPLE 5 Model a dropped object with a quadratic function ANSWER Reject the negative solution, – 1.8, because time must be positive. The container will fall for about 1.8 seconds before it hits the ground.
29
GUIDED PRACTICE Your Turn: for Example 5
WHAT IF? In Example 5, suppose the egg container is dropped from a height of 30 feet. How long does the container take to hit the ground? ANSWER The container will fall for about 1.4 seconds before it hits the ground.
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.