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Published byαΌ©Οα½Ό ΞλΡξάνδΟΞΏΟ Modified over 5 years ago
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Solving linear equations: Variable on both sides and brackets
Silent Teacher Intelligent Practice Narration Your Turn 2(π₯+3)=π₯+5 3(π₯+3)=2(π₯+5) Practice
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Worked Example Your Turn 2(π₯+1)=π₯+5 3(π₯+1)=π₯+5 @mathsmiles_k
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π₯+5=3 π₯+1 3 π₯β5 =3(2π₯+1) 3 π₯+5 =π₯+1 3 π₯β5 =β3(2π₯+1) 3 π₯+5 =3(2π₯+1)
1. 7. 3 π₯β5 =3(2π₯+1) 3 π₯+5 =π₯+1 2. 8. 3 π₯β5 =β3(2π₯+1) 3. 3 π₯+5 =3(2π₯+1) 9. β3 π₯+5 =β3(2π₯+1) 4. 3 π₯+5 =3(2π₯β1) 10. β3 π₯β5 =β3(2π₯+1) 5. 3 π₯β5 =3(2π₯β1) 11. β3 π₯β5 =β3(2π₯β1) 6. 3 2π₯β5 =3(π₯β1) 12. β3 2π₯β1 =β3(π₯β5) @mathsmiles_k
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π₯+5=3 π₯+1 3 π₯β5 =β3(2π₯+1) π₯=1 π₯=β6 3 π₯+5 =π₯+1 β3 π₯+5 =β3(2π₯+1) π₯=-7
π₯= 12 9 3 π₯+5 =3(2π₯+1) π₯=4 β3 π₯β5 =β3(2π₯+1) π₯=4 3 π₯+5 =3(2π₯β1) π₯=6 β3 π₯β5 =β3(2π₯β1) 3 π₯β5 =3(2π₯β1) π₯=β4 π₯=β4 β3 2π₯β1 =β3(π₯β5) π₯=β4 3 2π₯β5 =3(π₯β1) π₯=4 @mathsmiles_k
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