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Warm up Honors Algebra 2 3/14/19
The advertised mass of a box of cereal is 453 grams. A quality control manager measures 12 boxes and records the following masses in grams. 450, 453, 451, 456, 455, 454, 456, 452, 453, 495, 453, Find the mean of the data. 2. Find the median of the data. 3. Which value in the data set above is most likely to be considered an outlier? 4. How does the mean of the data set change if this outlier is removed? 5. How does the median of the data set change if this outlier is removed?
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Outlier An extreme value that is much less than or much greater than the other data values Have a strong effect on the mean and standard deviation Can be a result of measurement error or may represent data from the wrong population (in these cases, the value is usually removed) In order to determine if a value is an outlier, look for data values that are more than three standard deviations from the mean
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For numerical data, the weighted average of all those outcomes is called the expected value for that experiment. The probability distribution for an experiment is the function that pairs each outcome with its probability
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**USE WEIGHTED AVERAGE**
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Finding Expected Value (CONT)
πΈπ₯ππππ‘ππ ππππ’π: ( 1 2 ) 1 πΈπ₯ππππ‘ππ ππππ’π: =2.05 Expected number of successful free throws is 2.05 The total will always be 1 since it is probability!!
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πΈπ₯ππππ‘ππ ππππ’π: =0.37 The expected number of accidents is 0.37
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Find the mean, median, and range of the following data sets:
{19, 20, 21} {0, 20, 40} Mean: 20 Median: 20 Range: 2 Mean: 20 Median: 20 Range: 40 The two data sets have the same mean and median, but the sets are very different in the way they are spread out!!
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Variation A measure of variation is a value that describes the spread of the data set. Range Interquartile range Variance Standard Deviation
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Measures of Variation Variance Standard Deviation π 2
Average of the squared differences from the mean. π The square root of the variance One of the most common measures of variation
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Standard Deviation Low standard deviations indicate data that are clustered near the measures of central tendency. High standard deviations indicate data that are spread out from the center
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Finding Variance and Standard Deviation
Find the mean of the data, π₯ Find the difference between the mean and each data value, and square it Find the variance, π 2 , by adding the squares of all the differences from the mean, and dividing by the number of data values. Find the standard deviation, π, by taking the square root of the variance.
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Find the mean and standard deviation.
This data set represents the number of people getting on and off a bus for several stops: {6,8,7,5,10,6,9,8,4} 1. Find the mean π₯ = =7 ππππππ
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2. Find the difference between the mean and each data value, then square it.
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4. Find the standard deviation
3. Find the variance Find the average of the last data row. The average of the differences squared. π 2 = β3.333 4. Find the standard deviation Find the average of the last data row. Take the square root of the variance π= β1.83 ππππππ
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Finding Stats in a calculator!!
This data set represents the number of elevator stops for several rides: {0,3,1,1,0,5,1,0,3,0} Enter the data into the STAT ο EDIT table (in L1) STAT ο CALC ο 1) 1-VAR STATS
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Relevant Statistics: π₯ :ππππ=1.4 ππ₯:ππ‘ππππππ π·ππ£πππ‘πππ=1.6 πππ:ππππππ=1 ππππ:ππππππ’π=0 π1:πΉπππ π‘ ππ’πππ‘πππ=0 π3:πβπππ ππ’πππ‘πππ=3 πππ₯π:πππ₯πππ’π=5
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Box-and-Whiskers Plot in Calculator
STAT ο EDIT (values in L1) 2nd Y= (STAT PLOT) ο 1: PLOT1 Turn on Select first box-and-whiskers plot ZOOM ο 9: ZOOMSTAT TRACE allows you to trace each value of the box- and-whisker plot Min, Max, Q1, Q3, and Median Show on calculator
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Find the following of the data set WITHOUT the use of a calculator:
{4,6,10,7,7,8,9,3,4,5} Mean Median IQR Standard deviation
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1. Mean π₯ = = =6.3 2. Median 3, 4, 4, 5, 6, 7, 7, 8, 9, 10 6+7 2 = 13 2 =6.5
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3. IQR 3, 4, 4, 5, 6, 7, 7, 8, 9, 10 πΌππ
=π3βπ1=8β4=4 First quartile (Q1) 4 Third quartile (Q3) 8
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4. Standard Deviation π= π 2 = 4.81 =2.19 x 3 4 5 6 7 8 9 10 π₯ βπ₯ 3.3
2.3 1.3 0.3 -0.7 -1.7 -2.7 -3.7 π₯ βπ₯ 2 10.89 5.29 1.69 0.09 0.49 2.89 7.29 13.69 π 2 = =4.81 π= π 2 = =2.19
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Find the following of the data set WITH the use of a calculator:
The temperatures for this week are represented by the data set: {55, 65, 67, 51, 47, 50, 50, 52} Mean IQR Standard deviation Variance Median
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Stats: Mean: π₯ =54.6 IQR: π3βπ1:60β50=10 Standard deviation: π=6.91
Variance: π 2 = =47.75 Median: 51.5 Extra practice if time
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