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Do Now 12/14/18 y = 2x + 5 3x + y = 10 9x + 2y = 39 6x + 13y = -9

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Presentation on theme: "Do Now 12/14/18 y = 2x + 5 3x + y = 10 9x + 2y = 39 6x + 13y = -9"— Presentation transcript:

1 Do Now 12/14/18 y = 2x + 5 3x + y = 10 9x + 2y = 39 6x + 13y = -9
Take out HW from last night. Punchline worksheets 8.2 & 8.5 Copy HW in your planner. Text p. 257, #4-24 evens, 25 Quiz sections Tuesday In your notebook, explain the 3 different methods there are for solving a system. Then identify which method you use to solve the systems below. Solve each system. y = 2x + 5 3x + y = 10 9x + 2y = 39 6x + 13y = -9

2 + “Solve Linear Systems by Elimination Multiplying First!!”
Eliminated x (2) 9x + 2y = 39 18x + 4y = 78 Equation 1 + x (-3) -18x - 39y = 27 6x + 13y = -9 Equation 2 -35y = 105 y = -3 9x + 2y = 39 Equation 1 Substitute value for y into either of the original equations 9x + 2(-3) = 39 9x - 6 = 39 x = 5 9(5) + 2(-3) = 39 39 = 39 The solution is the point (5,-3). Substitute (5,-3) into both equations to check. 6(5) + 13(-3) = -9 -9 = -9

3 “Solve Linear Systems by Substituting”
y = 2x + 5 Equation 1 3x + y = 10 Equation 2 3x + y = 10 3x + (2x + 5) = 10 Substitute 3x + 2x + 5 = 10 5x + 5 = 10 x = 1 y = 2x + 5 Equation 1 Substitute value for x into the original equation y = 2(1) + 5 y = 7 (7) = 2(1) + 5 7 = 7 The solution is the point (1,7). Substitute (1,7) into both equations to check. 3(1) + (7) = 10 10 = 10

4 Homework Punchline worksheet 8.2
DID YOU HEAR ABOUT the antelope who was getting dressed when he was trampled by a herd of buffalo? WELL, as far as we know, this was the first self-dressed, stamped antelope

5 Homework Punchline worksheet 8.5
What Does Cate Often Call Her Twin Sister?? DUPLICATE

6 Learning Goal Learning Target
Students will be able to write and graph systems of linear equations. Learning Target Students will be able to special types systems of linear equations

7 “How Do You Solve a Linear System???”
(1) Solve Linear Systems by Graphing (5.1) (2) Solve Linear Systems by Substitution (5.2) (3) Solve Linear Systems by ELIMINATION!!! (5.3)

8 Section 5.4 “Solve Special Types of Linear Systems”
consists of two or more linear equations in the same variables. Types of solutions: (1) a single point of intersection – intersecting lines (2) no solution – parallel lines (3) infinitely many solutions – when two equations represent the same line

9 “Solve Linear Systems by Elimination” Multiplying First!!”
Eliminated x (2) 4x + 5y = 35 8x + 10y = 70 Equation 1 + x (-5) 15x - 10y = 45 -3x + 2y = -9 Equation 2 23x = 115 “Consistent Independent System” x = 5 4x + 5y = 35 Equation 1 Substitute value for x into either of the original equations 4(5) + 5y = 35 20 + 5y = 35 y = 3 4(5) + 5(3) = 35 35 = 35 The solution is the point (5,3). Substitute (5,3) into both equations to check. -3(5) + 2(3) = -9 -9 = -9

10 “Solve Linear Systems with No Solution”
Eliminated Eliminated 3x + 2y = 10 Equation 1 _ + -3x + (-2y) = -2 3x + 2y = 2 Equation 2 This is a false statement, therefore the system has no solution. 0 = 8 “Inconsistent System” No Solution By looking at the graph, the lines are PARALLEL and therefore will never intersect.

11 “Solve Linear Systems with Infinitely Many Solutions”
Equation 1 x – 2y = -4 Equation 2 y = ½x + 2 Use ‘Substitution’ because we know what y is equals. Equation 1 x – 2y = -4 x – 2(½x + 2) = -4 x – x – 4 = -4 This is a true statement, therefore the system has infinitely many solutions. -4 = -4 “Consistent Dependent System” Infinitely Many Solutions By looking at the graph, the lines are the SAME and therefore intersect at every point, INFINITELY!

12 + 5x + 3y = 6 -5x - 3y = 3 “Inconsistent System” 0 = 9 No Solution
“Tell Whether the System has No Solutions or Infinitely Many Solutions” Eliminated Eliminated 5x + 3y = 6 Equation 1 + -5x - 3y = 3 Equation 2 This is a false statement, therefore the system has no solution. “Inconsistent System” 0 = 9 No Solution

13 Infinitely Many Solutions
“Tell Whether the System has No Solutions or Infinitely Many Solutions” Equation 1 -6x + 3y = -12 Equation 2 y = 2x – 4 Use ‘Substitution’ because we know what y is equals. Equation 1 -6x + 3y = -12 -6x + 3(2x – 4) = -12 -6x + 6x – 12 = -12 This is a true statement, therefore the system has infinitely many solutions. -12 = -12 “Consistent Dependent System” Infinitely Many Solutions

14 How Do You Determine the Number of Solutions of a Linear System?
First rewrite the equations in slope-intercept form. Then compare the slope and y-intercepts. y -intercept slope y = mx + b Number of Solutions Slopes and y-intercepts One solution Different slopes No solution Same slope Different y-intercepts Infinitely many solutions Same y-intercept

15 “Identify the Number of Solutions”
Without solving the linear system, tell whether the system has one solution, no solution, or infinitely many solutions. 5x + y = -2 -10x – 2y = 4 6x + 2y = 3 6x + 2y = -5 3x + y = -9 3x + 6y = -12 Infinitely many solutions No solution One solution y = -5x – 2 – 2y =10x + 4 y = 3x + 3/2 y = 3x – 5/2 y = -3x – 9 y = -½x – 2

16 What Did You Learn?

17

18 PARCC Prep Homework Text p. 257, #4-24 evens, 25


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