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ECE 6341 Spring 2016 Prof. David R. Jackson ECE Dept. Notes 34
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Example Line current By using a Fourier-transform method, the exact solution is where, for y > 0, (Please see the appendix.)
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Example (cont.) The vertical wavenumber is
The wavenumber ky is interpreted as (This follows from the radiation condition at infinity.) A convenient change of variables is the “steepest-descent transformation”.
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Example (cont.) Then The path C in the complex -plane is not unique until we choose either + or – here. This is because the path is not uniquely determined by only To see this in more detail, write
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Example (cont.) Because kx is real, Hence or
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Example (cont.) There are four possible paths.
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Example (cont.) kx will vary from - to along each of these paths.
The path must be chosen so that along the path Assume we choose the + sign (an arbitrary choice):
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Example (cont.) Correct path C : C
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Example (cont.) Now proceed with the change of variables:
Hence, we have
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Example (cont.) Next, let
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Example (cont.) The integral then becomes
Ignoring the constant in front, we can identify: Hence
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Example (cont.) SDP: so Hence (SDP or SAP)
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Example (cont.) Using we also see that
This will help us determine which curve is the SDP and which is the SAP.
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Example (cont.) SDP SAP (SDP or SAP)
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Example (cont.) SDP Examination of the original path allows us to determine the direction of integration along the SDP.
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Example (cont.) Calculate : so or
From the figure we see that the correct choice is
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Example (cont.) Method of steepest-descent recipe: We then have or
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Example (cont.) The exact solution is:
It can easily be verified that the asymptotic result is correct, since so that
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Appendix Derivation of formula TMz :
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Appendix (cont.) Introduce the Fourier transform pair: We then have
Define:
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Appendix (cont.) Boundary conditions at y = 0:
(satisfied automatically)
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Appendix (cont.) Hence We then have
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Appendix (cont.) Hence And then
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