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11.5 Inscribed Angles
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Goal Use properties of inscribed angles.
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Key Vocabulary Inscribed Angle Intercepted Arc Inscribed Circumscribed
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Theorems 11.7 Inscribed Angle Theorem 11.8 Inscribed Triangle
11.9 Inscribed Quadrilateral
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Inscribed Angle Inscribed Angle: An angle whose vertex lies on a circle and whose sides are chords of the circle (or one side tangent to the circle). Examples: 3 1 2 4 No! Yes! No! Yes!
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Intercepted Arc Intercepted Arc: An angle intercepts an arc if and only if each of the following conditions holds: 1. The endpoints of the arc lie on the angle. 2. All points of the arc, except the endpoints, are in the interior of the angle. 3. Each side of the angle contains an endpoint of the arc.
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Theorem - Inscribed Angles
Theorem 11.7 (Inscribed Angle Theorem): The measure of an inscribed angle equals ½ the measure of its intercepted arc (or the measure of the intercepted arc is twice the measure of the inscribed angle). C A B mACB = ½m or 2 mACB = m
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Inscribed Angle Theorem
The measure of an inscribed angle is equal to ½ the measure of the intercepted arc. Y 110 Inscribed Angle 55 X Z Intercepted Arc
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Example 1a A. Find mX. Answer: mX = 43
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Example 1b B. = 2(252) or 104
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Your Turn: A. Find mC. A. 47 B. 54 C. 94 D. 188
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Your Turn: B. A. 47 B. 64 C. 94 D. 96
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Example 2 In and Find the measures of the numbered angles.
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Example 2 First determine Arc Addition Theorem Simplify.
20 40 108 Simplify. Subtract 168 from each side. Divide each side by 2.
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Example 2 So, m 20 40 108
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Example 2 20 40 108 Answer:
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Your Turn: A. 30 B. 60 C. 15 D. 120
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Your Turn: A. 110 B. 55 C. 125 D. 27.5
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Your Turn: A. 30 B. 80 C. 40 D. 10
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Your Turn: A. 110 B. 55 C. 125 D. 27.5
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Your Turn: A. 110 B. 55 C. 125 D. 27.5
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Comparing Measures of Inscribed Angles
Find mACB, mADB, and mAEB. The measure of each angle is half the measure of the intercepted arc. All three angles intercept the same arc, arc AB, whose measure is 60˚. So the measure of each angle is 30°.
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Congruent Inscribed Angles
If two inscribed angles of a circle intercept the same arc or congruent arcs, then the inscribed angles are congruent.
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Example 3 Find mR. R S R and S both intercept .
mR mS Definition of congruent angles 12x – 13 = 9x + 2 Substitution x = 5 Simplify. Answer: So, mR = 12(5) – 13 or 47.
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Your Turn: Find mI. A. 4 B. 25 C. 41 D. 49
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Example 4: Find the value of x and y in the figures
x 50˚ A B C E F y 40˚ x 50˚ A B C D E
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Polygons Inscribed Polygon:
A polygon inside the circle whose vertices lie on the circle. Circumscribed Polygon : A polygon whose sides are tangent to a circle.
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Angles of Inscribed Polygons
Theorem 11.8: An inscribed angle of a triangle intercepts a diameter or semicircle if and only if the angle is a right angle. i.e. If AC is a diameter of ⊙O, then the mABC = 90° o
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Example 5 Find mB. ΔABC is a right triangle because C inscribes a semicircle. mA + mB + mC = 180 Angle Sum Theorem (x + 4) + (8x – 4) + 90 = 180 Substitution 9x + 90 = 180 Simplify. 9x = 90 Subtract 90 from each side. x = 10 Divide each side by 9. Answer: So, mB = 8(10) – 4 or 76.
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Your Turn: Find mD. A. 8 B. 16 C. 22 D. 28
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Lesson 4 Ex4 Ex. 6:
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Your Turn: A. 45 B. 90 C. 180 D. 80
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Your Turn: A. 17 B. 76 C. 60 D. 42
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Your Turn: A. 17 B. 76 C. 60 D. 42
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Your Turn: A. 73 B. 30 C. 60 D. 48
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Angles of Inscribed Polygons
Theorem 11.9: If a quadrilateral is inscribed in a ⊙, then its opposite s are supplementary. i.e. Quadrilateral ABCD is inscribed in ⊙O, thus A and C are supplementary and B and D are supplementary. D A C B O
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Theorem 11.9 If a quadrilateral is inscribed in a circle, then its opposite angles are supplementary.
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Example 7: Quadrilateral QRST is inscribed in If and find and
Draw a sketch of this situation. Answer:
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Your Turn: Quadrilateral BCDE is inscribed in If and find and Answer:
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Example 8 An insignia is an emblem that signifies rank, achievement, membership, and so on. The insignia shown is a quadrilateral inscribed in a circle. Find mS and mT.
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Example 8 Since TSUV is inscribed in a circle, opposite angles are supplementary. S + V = S + V = 180 S = 180 (14x) + (8x + 4) = 180 S = 90 22x + 4 = 180 22x = 176 x = 8 Answer: So, mS = 90 and mT = 8(8) + 4 or 68.
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Your Turn: An insignia is an emblem that signifies rank, achievement, membership, and so on. The insignia shown is a quadrilateral inscribed in a circle. Find mN. A. 48 B. 36 C. 32 D. 28
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Review Problems
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Find the measure of the inscribed angle or the intercepted arc.
Example 1 Find Measures of Inscribed Angles and Arcs Find the measure of the inscribed angle or the intercepted arc. a. b. SOLUTION mNMP = mNP 2 1 The measure of an inscribed angle is half the measure of its intercepted arc. a. Substitute 100° for mNP (100°) 2 1 = = 50° Simplify. 44
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Example 1 b. b. 1 mZYX = mZWX 2 1 105° = mZWX 2 210° = mZWX
Find Measures of Inscribed Angles and Arcs b. b. mZYX = mZWX 2 1 The measure of an inscribed angle is half the measure of its intercepted arc. 105° = mZWX 2 1 Substitute 105° for mZYX. 210° = mZWX Multiply each side by 2. 45
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Your Turn: Find the measure of the inscribed angle or the intercepted arc. 1. ANSWER mBAC = 45° 2. ANSWER mDEF = 80° 3. ANSWER mKNP = 240°
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Find the values of x and y.
Example 2 Find Angle Measures Find the values of x and y. SOLUTION Because ∆ABC is inscribed in a circle and AB is a diameter, it follows from Theorem 11.8 that ∆ABC is a right triangle with hypotenuse AB. Therefore, x = 90. Because A and B are acute angles of a right triangle, y = 90 – 50 = 40. 47
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Your Turn: Find the values of x and y in C. 4. ANSWER x = 90; y = 55 5. ANSWER x = 45; y = 90 6. ANSWER x = 30; y = 90
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Find the values of y and z.
Example 3 Find Angle Measures Find the values of y and z. SOLUTION Because RSTU is inscribed in a circle, by Theorem 11.9 opposite angles must be supplementary. S and U are opposite angles. R and T are opposite angles. mS + mU = 180° mR + mT = 180° 120° + y° = 180° z° + 80° = 180° y = 60 z = 100 49
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Your Turn: Find the values of x and y in C. 7. ANSWER x = 85; y = 80 8. ANSWER x = 90; y = 90 9. ANSWER x = 130; y = 100
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66˚
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54˚
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43˚
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90˚
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54˚
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50˚
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54˚
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36˚
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50˚
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72˚
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180˚
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In the figure, find the value of x.
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Find the value of x. X = 21.5
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Assignment Pg. 617 – 619; #1 – 29 odd, 33 – 49 odd
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