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From Chapter 2, we have ( II ) Proof is shown next

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Presentation on theme: "From Chapter 2, we have ( II ) Proof is shown next"— Presentation transcript:

1 From Chapter 2, we have ( II ) Proof is shown next
This property is known as “convolution” (الإلتواء التفاف ) Proof is shown next

2 Proof Define the pulse of width D as

3 We now can approximate the function In terms of the pulse function
Approximation

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6 This integral is called the convolution

7 Another proof for Sifting properties

8 Linear –Time Invariant
Impulse Input Impulse response Shifted Impulse Input Shifted Impulse Response

9 Linear –Time Invariant
Convolution Integral

10 constant with respect to t
Linear –Time Invariant constant with respect to t Integration with respect to l Operator with respect to t

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12 Example 2-7 Moving Fix

13 Sep 1 : make the functions or signals in terms of the variable l

14 Sep 2 : make the moving function in terms of -l
Sep 2 : add t to to form ( t- l) Moving to the right

15 For t ≤ 4 there is no overlapping between the functions

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19 For t ≥ 10 For t ≥ 10 there is no overlapping between the functions

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29 TO be down

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40 2.6 Superposition Integral “convolution” in terms of step response
Impulse response Now if the input is a step function, step response step response

41 Objective is to write y(t) in terms of the step response a(t)
Now if the input is x(t) , The output in terms of the impulse response h(t) Objective is to write y(t) in terms of the step response a(t)

42 Now if the input is x(t) , Integrating by parts , step response
Over dot denotes differentiation

43 Now we can write y(t) in terms of the step response a(t)
Integrating by parts , Now we can write y(t) in terms of the step response a(t)

44 The system is initially unexcited
and

45 In term of impulse response
In term of step response Note

46 Objective is the ramp response b(t)
Impulse input Impulse response step response Step input Ramp response Ramp input Objective is the ramp response b(t)

47 Now if x(t) is the ramp r(t)

48 Impulse input Step input Ramp input

49 To be Done From the notes RC circuit - DFE X(t) = impulse  h(t) X(t) is switch u(t)  a(t) X(t) is ramp r(t)  b(t) X(t) is X(t) = r(t)-2r(t-1)+r(t-2) BIBO condition


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