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Probability – Mutually Exclusive & Exhaustive – Bingo Method
Students should choose nine answers from the grid and place them randomly into a 3x3 square in their book. You may want to pause your display and choose questions according to difficulty during the game. Depending on time, students could win with a line, an X, or a ‘full house’ (all).
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Mutually Exclusive & Exhaustive Outcomes
BINGO! 45 54 23 82 37 12 76 25 91 Mutually Exclusive & Exhaustive Outcomes
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Choose your numbers… 9 13 2 7 5 9 7 10 11 13 6 13 8 11 1 5 8 15 5 12 7 9 5 13 9 14 9 11 5 17 4 11 Draw a 3x3 grid in your book.
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Joe picks a button at random.
What is P(red or black)? P(red or black) = P(red) + P(black) = =
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Joe picks a button at random. What is P(not red or black)?
P(not red or black) = 1 − P(red or black) P(red or black) = P(red) + P(black) = = 5 7 P(not red or black) = 1 − 5 7 = 2 7
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In a bag there are red, blue and black buttons.
Joe picks a button at random. What is P(red or black)? P(red or black) = P(red) + P(black) P(red) = 2 9 = P(blue) = 2 9 = 7 9 P(black) = 5 9
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Joe picks a button at random. What is P(yellow or black)?
P(yellow or black) = P(yellow) + P(black) = =
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In a bag there are yellow, green and blue buttons.
Joe picks a button at random. What is P(green or blue)? P(green or blue) = P(green) + P(blue) P(yellow) = 1 11 = P(green) = 7 11 = P(blue) = 2 11
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Joe picks a button at random. What is P(not green or blue)?
P(not green or blue) = 1 − P(green or blue) P(green or blue) = P(green) + P(blue) = = P(not green or blue) = 1 − =
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In a bag there are black, green and red buttons.
Joe picks a button at random. What is P(green or red)? P(green or red) = P(green) + P(red) P(yellow) = 3 11 = P(green) = 5 11 = P(red) = ?
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Joe picks a button at random. What is P(blue or yellow)?
P(blue or yellow) = P(blue) + P(yellow) = =
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In a bag there are black, white and blue buttons.
Joe picks a button at random. What is P(not white or blue)? P(not white or blue) = 1 − P(white or blue) P(white or blue) = P(white) + P(blue) P(black) = 5 13 = P(white) = 5 13 = P(not white or red) = 1 − = P(blue) = ?
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In a bag there are red, blue and green buttons.
Joe picks a button at random. What is P(not red or blue)? P(not red or blue) = 1 − P(red or blue) P(red or blue) = P(red) + P(blue) P(red) = 1 5 = P(blue) = 3 5 = 4 5 P(green) = 1 5 P(not red or blue) = 1 − 4 5 = 1 5
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Joe picks a button at random. What is P(pink or green)?
P(pink or green) = P(pink) + P(green) = =
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Joe picks a button at random. What is P(not yellow or red)?
P(not yellow or red) = 1 − P(yellow or red) P(yellow or red) = P(yellow) + P(red) = = P(not yellow or red) = 1 − =
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In a bag there are pink, blue and yellow buttons.
Joe picks a button at random. What is P(pink or yellow)? P(pink or yellow) = P(pink) + P(yellow) P(pink) = 5 13 = P(blue) = 2 13 = P(yellow) = ?
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Joe picks a button at random. What is P(not blue or green)?
P(not blue or green) = 1 − P(blue or green) P(blue or green) = P(blue) + P(green) = = P(not blue or green) = 1 − =
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In a bag there are green, yellow and red buttons.
Joe picks a button at random. What is P(not green or red)? P(not green or red) = 1 − P(green or red) P(green or red) = P(green) + P(red) P(green) = 2 9 = P(yellow) = 5 9 = 4 9 P(red) = 2 9 P(not green or red) = 1 − 4 9 = 5 9
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In a bag there are green, pink and white buttons.
Joe picks a button at random. What is P(not green or white)? P(not green or white) = 1 − P(green or white) P(green or white) = P(green) + P(white) P(green) = 7 17 = P(pink) = 5 17 = P(white) = ? P(not green or white) = 1 − =
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tom@goteachmaths.co.uk Questions? Comments? Suggestions?
…or have you found a mistake!? Any feedback would be appreciated . Please feel free to
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