1. Hardy-Weinberg Lab Data
Mutation
Gene Flow
Genetic Drift
Selection
Non-random mating

2. Hardy Weinberg Lab: Equilibrium
Original population
Case #1 F5
18 individuals
36 alleles
p (A): 0.5
q (a): 0.5
total alleles = 36
p (A): (4+4+7)/36 = .42
q (a): (7+7+7)/36 = .58 AA 4 Aa 7 aa 7 AA
.25 Aa
.50 aa
.25 AA
.22 Aa
.39 aa
.39
How do you explain these data?

3. Hardy Weinberg Lab: Selection
Original population
Case #2 F5
15 individuals
30 alleles
p (A): 0.5
q (a): 0.5
total alleles = 30
p (A): (9+9+6)/30 = .80
q (a): (0+0+6)/30 = .20 AA 9 Aa 6 aa AA
.25 Aa
.50 aa
.25 AA
.60 Aa
.40 aa
How do you explain these data?

4. Hardy Weinberg Lab: Heterozygote Advantage Original population
Case #3 F5
15 individuals
30 alleles
p (A): 0.5
q (a): 0.5
total alleles = 30
p (A): (4+4+11)/30 = .63
q (a): (0+0+11)/30 = .37 AA 4 Aa 11 aa AA
.25 Aa
.50 aa
.25 AA
.27 Aa
.73 aa
How do you explain these data?

5. Hardy Weinberg Lab: Heterozygote Advantage Original population
Case #3 F10
15 individuals
30 alleles
p (A): 0.5
q (a): 0.5
total alleles = 30
p (A): (6+6+9)/30 = .70
q (a): (0+0+9)/30 = .30 AA 6 Aa 9 aa AA
.25 Aa
.50 aa
.25 AA .4 Aa .6 aa
How do you explain these data?

6. Hardy Weinberg Lab: Genetic Drift
Original population
Case #4 F5-1
6 individuals
12 alleles
p (A): 0.5
q (a): 0.5
total alleles = 12
p (A): (4+4+2)/12 = .83
q (a): (0+0+2)/12 = .17 AA 4 Aa 2 aa AA
.25 Aa
.50 aa
.25 AA
.67 Aa
.33 aa
How do you explain these data?

7. Hardy Weinberg Lab: Genetic Drift
Original population
Case #4 F5-2
5 individuals
10 alleles
p (A): 0.5
q (a): 0.5
total alleles = 10
p (A): (0+0+4)/10 = .4
q (a): (1+1+4)/10 = .6 AA Aa 4 aa 1 AA
.25 Aa
.50 aa
.25 AA Aa .8 aa .2
How do you explain these data?

8. Hardy Weinberg Lab: Genetic Drift
Original population
Case #4 F5-3
5 individuals
10 alleles
p (A): 0.5
q (a): 0.5
total alleles = 10
p (A): (2+2+2)/10 = .6
q (a): (1+1+2)/10 = .4 AA 2 Aa 2 aa 1 AA
.25 Aa
.50 aa
.25 AA .4 Aa .4 aa .2
How do you explain these data?

9. Hardy Weinberg Lab: Genetic Drift
Original population
Case #4 F5
5 individuals
10 alleles
p (A): 0.5
q (a): 0.5
AA Aa aa p q AA
.25 Aa
.50 aa
.25
How do you explain these data?

10. Any Questions??