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Asoc.Prof. HALA MOUSTAFA

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Presentation on theme: "Asoc.Prof. HALA MOUSTAFA"— Presentation transcript:

1 Asoc.Prof. HALA MOUSTAFA
Electric Field Asoc.Prof. HALA MOUSTAFA

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4 The direction of the field is determined by the force.
The Concept of a Field A field is defined as a property of space around the electric charge The direction of the field is determined by the force.

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8 Field is Property of Space
Electric Field + Q . r E Electric Field + Q . r Force on +q is with field direction. F - -q + +q F Force on -q is against field direction. The field E at a point exists whether there is a charge at that point or not. The direction of the field is away from the +Q charge.

9 Field Near a Negative Charge
Electric Field . r + +q F - -Q Force on +q is with field direction. E Electric Field . r - -q F -Q Force on -q is against field direction. Note that the field E in the vicinity of a negative charge –Q is toward the charge—the direction that a +q test charge would move.

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11 The Magnitude of E-Field
The magnitude of the electric field intensity at a point in space is defined as the force per unit charge (N/C) that would be experienced by any test charge placed at that point. Electric Field Intensity E The direction of E at a point is the same as the direction that a positive charge would move IF placed at that point.

12 The Resultant Electric Field.
The resultant field E in the vicinity of a number of point charges is equal to the vector sum of the fields due to each charge taken individually. Consider E for each charge. E2 + - q1 q2 q3 A E1 Vector Sum: E = E1 + E2 + E3 ER E3 Magnitudes are from: Directions are based on positive test charge.

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19 The Gravitational Field
Note that the force F is real, but the field is just a convenient way of describing space. B A F F The field at points A or B might be found from: If g is known at every point above the earth then the force F on a given mass can be found. The magnitude and direction of the field g is depends on the weight, which is the force F.

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21 The electric dipole The electric dipole is positive charge and negative charge of equal magnitude المناظر للأبرة المغناطيسية في الكهربائية بمعنى الشحنة الموجبة والشحنة السالبة متساويتا

22 The E-Field at a distance r from a single charge Q
Consider a test charge +q placed at P a distance r from Q. + Q . r P E + Q . r P F + +q The outward force on +q is: The electric field E is therefore:

23 Electric Field . - -Q P +2 nC Example 1. A +2 nC charge is placed at a distance r from a –8 mC charge. If the charge experiences a force of 4000 N, what is the electric field intensity E at point P? + +q 4000 N E E r –8 mC First, we note that the direction of E is toward –Q (down). E = 2 x 1012 N/C Downward Note: The field E would be the same for any charge placed at point P. It is a property of that space.

24 Example 2. A constant E field of 40,000 N/C is maintained between the two parallel plates. What are the magnitude and direction of the force on an electron that passes horizontally between the plates.c - e- The E-field is downward, and the force on e- is up. E . F F = 6.40 x N, Upward

25 Example 3. What is the electric field intensity E at point P, a distance of 3 m from a negative charge of –8 nC? First, find the magnitude: . r P -Q 3 m -8 nC E = ? E = 8.00 N/C The direction is the same as the force on a positive charge if it were placed at the point P: toward –Q. E = 8.00 N, toward -Q

26 Example 4. A charge of 2μC experiences a force of 34 N when placed at a point in an electric field. Calculate the electric field strength at the point?  Q = 2μC= 2x 10-6 C F = 34 N E=F/Q (N/C) E=34 N /2x 10-6 C = 68x (N/C)

27 Example 5. A charge of 2µC experiences a force of 34 N when placed at a point in an electric field.calculate the electric field strength at the point?  F=34 N q = 2µC E=F/q E = = 1.7x107 ( N/C) 2x10-6


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