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Unit 13 – Acid, Bases, & Salts
Titrations Titration Calculations Print 1, 3-5, 7-8
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ACID + BASE SALT + WATER
Neutralization Reactions (REVIEW) Neutralization – chemical reaction between an acid and a base. HCl + NaOH NaCl + HOH H2O = ACID + BASE SALT + WATER
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A. Titration Titration Process used to determine the concentration of a solution by adding a known concentration (the standard) to a measured amount of the solution of unknown concentration
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A. Titration Equivalence Point moles of H+ = moles of OH–
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A. Titration A steep rise in the pH of the acid solution indicates that all the H+ ions from the acid have been neutralized by the OH- ions of the base.
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A. Titration End Point indicator permanently changes color
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A. Titration Phenolphthalein
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Acid/Base Indicators
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MAVA = MBVB MAVA = MBVB a b
B. Calculations For neutralization reactions with a 1:1 ratio: MAVA = MBVB For neutralization reactions with a non 1:1 ratio: MAVA = MBVB a b a = acid coefficient b = base coefficient
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MAVA = MBVB B. Calculations 0.160 M HCl Example (find conc.)
A 25.0 mL solution of HCl was completely neutralized by 40.0 mL of standard M NaOH. What is the concentration of the HCl? HCl + NaOH NaCl + H2O MA x (25.0 mL) = (0.100 M) x (40.0 mL) MA = (40.0 mL) x (0.100 M) = (25.0 mL) 0.160 M HCl
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MAVA = MBVB B. Calculations 0.357 M KOH Example (find conc.)
A 20.4 mL solution of KOH was completely neutralized by 48.5 mL of M HNO3. What is the concentration of the KOH? HNO3 + KOH KNO3 + H2O (0.150 M) x (48.5 mL) = MB x (20.4 mL) (0.150 M) x (48.5 mL) = MB = (20.4 mL) 0.357 M KOH
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MAVA = MBVB a b B. Calculations Example (find conc.)
A 159 mL sample of KOH is titrated to equivalence with 100. mL of 1.50 M H2SO4 . Calculate the molarity of the KOH solution. H2SO4(aq) KOH(aq) 2 H2O(l) + K2SO4(aq) (1.50 M) x (100 mL) = MB x (159 mL) MB = (1.50 M) x (100 mL) x 2 = 1 x (159 mL) 1.89 M KOH
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Quick Quiz! 1) When the moles of acid equals the moles of base you have reached the… A) titration point B) end point C) equivalence point D) neutralization point 13
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Quick Quiz. 2) If 20. mL of 0.50 M HCl is titrated to equivalence by 40. mL of NaOH, then the NaOH concentration must be ___. A) 2.0 M B) 1.0 M C) 0.50 M D) 0.25 M moles of H+ = moles of OH– 0.020 L 0.50 M 0.040 L ??? M 14
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