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MR G’s Water Rocket experiment

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Presentation on theme: "MR G’s Water Rocket experiment"— Presentation transcript:

1 MR G’s Water Rocket experiment

2 3. Maximum Gravitational Potential energy 2. Maximum Kinetic energy 1. Maximum Strain Potential energy 4. Maximum Kinetic energy

3 “ROCKET SCIENCE” 100g Rocket 500g water ? m/s 5 m/s

4 Momentum of exhaust = Momentum of Rocket
“ROCKET SCIENCE” 100g Rocket 500g water ? m/s 5 m/s Momentum of exhaust = Momentum of Rocket

5 Momentum of exhaust = Momentum of Rocket
“ROCKET SCIENCE” 100g Rocket 500g water ? m/s 5 m/s Momentum of exhaust = Momentum of Rocket Mass of water x velocity of water = Mass of Rocket x velocity of Rocket

6 Momentum of exhaust = Momentum of Rocket
“ROCKET SCIENCE” 100g Rocket 500g water ? m/s 5 m/s Momentum of exhaust = Momentum of Rocket Mass of water x velocity of water = Mass of Rocket x velocity of Rocket 0.5 Kg x 5 m/s = Kg x VR

7 Momentum of exhaust = Momentum of Rocket
“ROCKET SCIENCE” 100g Rocket 500g water ? m/s 5 m/s Momentum of exhaust = Momentum of Rocket Mass of water x velocity of water = Mass of Rocket x velocity of Rocket 0.5 Kg x 5 m/s = Kg x VR 0.5 Kg x 5 m/s = VR 0.10

8 Momentum of exhaust = Momentum of Rocket
“ROCKET SCIENCE” 100g Rocket 500g water ? m/s 5 m/s Momentum of exhaust = Momentum of Rocket Mass of water x velocity of water = Mass of Rocket x velocity of Rocket 0.5 Kg x 5 m/s = Kg x VR 0.5 Kg x 5 m/s = VR 0.10 VR = 25 m/s

9 Momentum of exhaust = Momentum of Rocket
“ROCKET SCIENCE” 100g Rocket 500g water ? m/s 5 m/s Momentum of exhaust = Momentum of Rocket Mass of water x velocity of water = Mass of Rocket x velocity of Rocket 0.5 Kg x 5 m/s = Kg x VR 0.5 Kg x 5 m/s = VR 0.10 VR = 25 m/s = 56 mph

10 “ROCKET SCIENCE” V = 0 m/s a = - 10 m/s/s uR = 25 m/s
Maximum height ? ( ignore drag forces) a = - 10 m/s/s uR = 25 m/s

11 “ROCKET SCIENCE” V = 0 m/s a = - 10 m/s/s uR = 25 m/s
Maximum height ? ( ignore drag forces) a = - 10 m/s/s a = v – u t uR = 25 m/s

12 “ROCKET SCIENCE” V = 0 m/s a = - 10 m/s/s uR = 25 m/s
Maximum height ? ( ignore drag forces) a = - 10 m/s/s a = v – u t uR = 25 m/s Flight time: t = v – u a

13 “ROCKET SCIENCE” V = 0 m/s a = - 10 m/s/s uR = 25 m/s
Maximum height ? ( ignore drag forces) a = - 10 m/s/s a = v – u t uR = 25 m/s Flight time: t = v – u a t = – = 2.5 sec -10

14 “ROCKET SCIENCE” V = 0 m/s a = - 10 m/s/s uR = 25 m/s
Maximum height ? ( ignore drag forces) a = - 10 m/s/s a = v – u t uR = 25 m/s Flight time: t = v – u a t = – = 2.5 sec -10 Velocity m/s time/s

15 “ROCKET SCIENCE” V = 0 m/s a = - 10 m/s/s uR = 25 m/s
Maximum height ? ( ignore drag forces) a = - 10 m/s/s a = v – u t uR = 25 m/s Flight time: t = v – u a t = – = 2.5 sec -10 Velocity m/s 25 m/s 2.5 s time/s

16 Area = distance travelled = 2.5 x 25
“ROCKET SCIENCE” V = 0 m/s Maximum height ? ( ignore drag forces) a = - 10 m/s/s a = v – u t uR = 25 m/s Flight time: t = v – u a t = – = 2.5 sec -10 Velocity m/s 25 m/s Area = distance travelled = x 25 2 2.5 s time/s

17 Area = distance travelled = 2.5 x 25
“ROCKET SCIENCE” V = 0 m/s Maximum height ? ( ignore drag forces) a = - 10 m/s/s a = v – u t uR = 25 m/s Flight time: t = v – u a t = – = 2.5 sec -10 Velocity m/s 25 m/s Area = distance travelled = x 25 2 2.5 s time/s

18 Area = distance travelled = 2.5 x 25
“ROCKET SCIENCE” V = 0 m/s Maximum height ? ( ignore drag forces) a = - 10 m/s/s a = v – u t uR = 25 m/s Flight time: t = v – u a t = – = 2.5 sec -10 Velocity m/s 25 m/s Area = distance travelled = x 25 2 Maximum height reached = m 2.5 s time/s


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