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dO LENS F= 4.3 cm OBJECT BEYOND 2F Distance to Object dO = 10 cm

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Presentation on theme: "dO LENS F= 4.3 cm OBJECT BEYOND 2F Distance to Object dO = 10 cm"— Presentation transcript:

1 dO LENS F= 4.3 cm OBJECT BEYOND 2F Distance to Object dO = 10 cm
Height of Object hO = 2.5 cm scale 1cm = 1cm ho dO F F' 2F' 2F

2 dO 1. Draw ray from top of object parallel to principal
LENS F= 4.3 cm OBJECT BEYOND 2F Distance to Object dO = 10 cm Height of Object hO = 2.5 cm scale 1cm = 1cm 1. Draw ray from top of object parallel to principal axis to center of lens. ho dO F F' 2F' 2F

3 dO 2. Extend ray from center of lens through F' ho 2F 2F' F F'
LENS F= 4.3 cm OBJECT BEYOND 2F Distance to Object dO = 10 cm Height of Object hO = 2.5 cm scale 1cm = 1cm 2. Extend ray from center of lens through F' ho dO F F' 2F' 2F

4 dO 3. Draw ray from top of object through center of
LENS F= 4.3 cm OBJECT BEYOND 2F Distance to Object dO = 10 cm Height of Object hO = 2.5 cm 3. Draw ray from top of object through center of lens at principal axis. scale 1cm = 1cm ho dO F F' 2F' 2F

5 dO 4. Draw image where rays intersect. ho 2F 2F' F F'
LENS F= 4.3 cm OBJECT BEYOND 2F Distance to Object dO = 10 cm Height of Object hO = 2.5 cm scale 1cm = 1cm 4. Draw image where rays intersect. ho dO F F' 2F' 2F

6 5. Label and measure di. 6. Label and measure h dO hi di ho i 2F 2F' F
LENS F= 4.3 cm OBJECT BEYOND 2F Distance to Object dO = 10 cm Height of Object hO = 2.5 cm scale 1cm = 1cm 5. Label and measure di. 6. Label and measure h i ho di hi dO F F' 2F' 2F

7 dO hi di ho Measured di = 7.6 cm hi = 2.0 cm scale 1cm = 1cm
LENS F= 4.3 cm OBJECT BEYOND 2F Distance to Object dO = 10 cm Height of Object hO = 2.5 cm scale 1cm = 1cm Measured di = 7.6 cm hi = 2.0 cm ho di hi dO F F' 2F' 2F

8 dO hi di ho Measured di = 7.7 cm hi = 2.0 cm scale 1cm = 1cm
LENS F= 4.3 cm OBJECT BEYOND 2F Distance to Object dO = 10 cm Height of Object hO = 2.5 cm scale 1cm = 1cm Measured di = 7.7 cm hi = 2.0 cm ho di hi dO F F' 2F' 2F Theoretical Distance to Image Height of Image 1/do + 1/di = 1/f m = -di/do hi = m(ho) 1/10 + 1/di = 1/ m = / hi = .75(2.5) di = 7.54 cm m = hi = 1.88cm % deviation = 2.12% inverted % deviation = 6.38% < 1 smaller


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