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differentiate shoulder pulse

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Presentation on theme: "differentiate shoulder pulse"— Presentation transcript:

1 differentiate shoulder pulse

2 Pileup 100% 0.75% 99.25%

3 Pileup 98.9% 97.65% 95.14% 85.88%

4 GOOD 100% 0.608% 99.4%

5 GOOD 98.9% 98.1% 95.8% 88.1%

6 percentage of pulse Pileup GOOD number pileup pulse = 54260
number of single pulse = (56.24%) number of double pulse = (41.58%) number of triple pulse = 956 ( 1.76%) number of quadruple pulse = 247 ( 0.46%) GOOD number of good pulse = number of single pulse = (81.64%) number of double pulse = (17.99%) number of triple pulse = ( 0.26%) number of quadruple pulse = ( 0.11%)

7 1. single? shoulder? bad fit!!

8 ΔADC ADC Δ(ΔADC))

9 threshold normalized Δ(ΔADC)) Δ(ΔADC)) Δ(ΔADC)) (zoom in) fail

10 threshold normalized Δ(ΔADC)) Δ(ΔADC)) Δ(ΔADC)) (zoom in) fail

11 threshold normalized Δ(ΔADC)) Δ(ΔADC)) Δ(ΔADC)) (zoom in) fail

12 2. shoulder? single? bad fit!!

13 2.neighboring pulse ΔADC Δ(ΔADC)) ADC

14 3. shoulder? single? bad fit!!
the same case 1. lay 6 dipangle 8 hid

15 3.neighboring pulse ΔADC Δ(ΔADC)) ADC

16 4.single, bad fit!!

17 4.neighboring pulse ΔADC Δ(ΔADC)) ADC

18 pile up pulse, TDC cut =3 number of pileup pulse = 54260
number of single pulse = (56.24%) number of double pulse = (41.58%) number of triple pulse = 956 ( 1.76%) number of quadruple pulse = 247 ( 0.46%) number of (1) pulse =18 (0.0074%) (percentage in double pulse (0.0177%)) (chi_square>4 , single pulse) number of ( ) pulse =89 (0.16%) (percentage in double pulse (0.39%))

19 5.shoulder, bad fit!! the same case 1. lay 6 dipangle 14 hid

20 5.neighboring pulse ΔADC ADC Δ(ΔADC)) the same case
1. lay 6 dipangle 14 hid

21 pile up pulse, TDC cut =3 number of pileup pulse = 54260
number of single pulse = (56.24%) number of double pulse = (41.58%) number of triple pulse = 956 ( 1.76%) number of quadruple pulse = 247 ( 0.46%) number of (4) pulse =3 (0.0055%) (percentage in double pulse (0.013%)) (chi_square>4 , single pulse)

22 6.double, bad fit!!

23 6.neighboring pulse ΔADC ADC Δ(ΔADC))

24 longer new fit bound old (([tdc2] - [tdc1])*7. + [tdc2])
new (([tdc2] - [tdc1])*15. + [tdc2]) new fit option which can get shoulder pulse not only in single pulse also use longer new fit bound

25 7.double, bad fit!!

26 7.neighboring pulse ΔADC ADC Δ(ΔADC))

27 not about new fit bound the default fitbound is before newfitbound (([tdc2] - [tdc1])*7. + [tdc2])
new fit option which can get shoulder pulse not only in single pulse also use longer fit bound

28 8.double, bad fit!!

29 8.neighboring pulse ΔADC ADC Δ(ΔADC))

30 8.new fit option can not save it
which can get shoulder pulse not only in single pulse also use longer fit bound

31 pile up pulse, TDC cut =3 number of pileup pulse = 54260
number of single pulse = (56.24%) number of double pulse = (41.58%) number of triple pulse = 956 ( 1.76%) number of quadruple pulse = 247 ( 0.46%) number of (8) pulse =10 (0.0055%) (percentage in double pulse (0.013%)) (chi_square>4 , single pulse)

32 pile up pulse, TDC cut =3 number of all kind of saturate pulse (chi_square>4) =216 (0.39%) (percentage in double pulse (0.96%))

33 Pileup chi2 >100 0.74% peakadc <7 5.67%

34 small pulse number of small pulse (chi_square>4) =216 (0.39%)
=216 (0.39%) (percentage in double pulse (0.96%)) chi2>4.and.chi2<10.and.peakadc1<15 the chi2 save by another pulse dipangle hid peakadc1 115 dipangle hid peakadc1 18 dipangle hid peakadc1 32 dipangle hid peakadc dipangle hid peakadc1 133

35 9. chi2>4. and. chi2<9999. and
9.chi2>4.and.chi2<9999.and.peakadc1<15 the chi2 save by another pulse

36 9.neighboring pulse

37 backup


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