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Lecture #9 OUTLINE The capacitor The inductor Chapter 3 Reading.

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Presentation on theme: "Lecture #9 OUTLINE The capacitor The inductor Chapter 3 Reading."— Presentation transcript:

1 Lecture #9 OUTLINE The capacitor The inductor Chapter 3 Reading

2 The Capacitor Q = CVab Two conductors (a,b) separated by an insulator:
difference in potential = Vab => equal & opposite charge Q on conductors Q = CVab where C is the capacitance of the structure, positive (+) charge is on the conductor at higher potential (stored charge in terms of voltage) Parallel-plate capacitor: area of the plates = A separation between plates = d dielectric permittivity of insulator =  => capacitance

3 Units: Farads (Coulombs/Volt)
Symbol: Units: Farads (Coulombs/Volt) Current-Voltage relationship: C C (typical range of values: 1 pF to 1 mF) ic + vc Note: Q (vc) must be a continuous function of time

4 Voltage in Terms of Current

5 Op-Amp Integrator C ic – vC + R in vin + + vn vo + vp

6 Stored Energy You might think the energy stored on a capacitor is QV, which has the dimension of Joules. But during charging, the average voltage across the capacitor was only half the final value of V for a linear capacitor. Thus, energy is Example: A 1 pF capacitance charged to 5 Volts has ½(5V)2 (1pF) = 12.5 pJ

7 A more rigorous derivation
ic + vc

8 Example: Current, Power & Energy for a Capacitor
v (V) v(t) + 10 mF 1 t (ms) 1 2 3 4 5 i (mA) vc must be a continuous function of time; however, ic can be discontinuous. t (ms) 1 2 3 4 5 Note: In “steady state” (dc operation), time derivatives are zero  C is an open circuit

9 p (W) i(t) v(t) + 10 mF t (ms) 1 2 3 4 5 w (J) t (ms) 1 2 3 4 5

10 Capacitors in Parallel
+ v(t) i(t) C1 C2 + v(t) i(t) Ceq Equivalent capacitance of capacitors in parallel is the sum

11 Capacitors in Series C + = + v1(t) – + v2(t) – + v(t)=v1(t)+v2(t) – C1
Ceq 2 1 C eq + =

12 Capacitive Voltage Divider
Q: Suppose the voltage applied across a series combination of capacitors is changed by Dv. How will this affect the voltage across each individual capacitor? DQ1=C1Dv1 Note that no net charge can can be introduced to this node. Therefore, -DQ1+DQ2=0 Q1+DQ1 + v1+Dv1 C1 -Q1-DQ1 v+Dv + Q2+DQ2 + v2(t)+Dv2 C2 -Q2-DQ2 DQ2=C2Dv2 Note: Capacitors in series have the same incremental charge.

13 Application Example: MEMS Accelerometer
Capacitive position sensor used to measure acceleration (by measuring force on a proof mass) g1 g2 FIXED OUTER PLATES

14 Sensing the Differential Capacitance
Begin with capacitances electrically discharged Fixed electrodes are then charged to +Vs and –Vs Movable electrode (proof mass) is then charged to Vo Circuit model Vs C1 Vo C2 –Vs

15 Practical Capacitors A capacitor can be constructed by interleaving the plates with two dielectric layers and rolling them up, to achieve a compact size. To achieve a small volume, a very thin dielectric with a high dielectric constant is desirable. However, dielectric materials break down and become conductors when the electric field (units: V/cm) is too high. Real capacitors have maximum voltage ratings An engineering trade-off exists between compact size and high voltage rating

16 The Inductor An inductor is constructed by coiling a wire around some type of form. Current flowing through the coil creates a magnetic field and a magnetic flux that links the coil: LiL When the current changes, the magnetic flux changes  a voltage across the coil is induced: + vL(t) iL _ Note: In “steady state” (dc operation), time derivatives are zero  L is a short circuit

17 Units: Henrys (Volts • second / Ampere)
Symbol: Units: Henrys (Volts • second / Ampere) Current in terms of voltage: L (typical range of values: mH to 10 H) iL + vL Note: iL must be a continuous function of time

18 ò p ( t ) = v ( t ) i ( t ) = w ( t ) = p ( t ) d t = 1 1 w ( t ) = Li
Stored Energy Consider an inductor having an initial current i(t0) = i0 p ( t ) = v ( t ) i ( t ) = t ò w ( t ) = p ( t ) d t = t 1 1 2 w ( t ) = Li 2 - Li 2 2

19 Equivalent inductance of inductors in series is the sum
+ v1(t) – + v2(t) – + v(t)=v1(t)+v2(t) L1 L2 i(t) i(t) + + v(t) v(t) Leq Equivalent inductance of inductors in series is the sum

20 Inductors in Parallel + v(t) + v(t) i1 i2 i(t) i(t) Leq L1 L2

21 Summary Capacitor v cannot change instantaneously
i can change instantaneously Do not short-circuit a charged capacitor (-> infinite current!) n cap.’s in series: n cap.’s in parallel: Inductor i cannot change instantaneously v can change instantaneously Do not open-circuit an inductor with current (-> infinite voltage!) n ind.’s in series: n ind.’s in parallel:


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