1. Substitution – With a Calculator – Bingo Method
Students should choose nine answers from the grid and place them
randomly into a 3x3 square in their book.
You may want to pause your display and choose questions
according to difficulty during the game.
Depending on time, students could win with
a line, an X, or a ‘full house’ (all).

2. Printing To print handouts from slides -
Select the slide from the left. Then click:
File > Print > ‘Print Current Slide’
To print multiple slides -
Click on a section title to highlight all those slides,
or press ‘Ctrl’ at the same time as selecting slides to
highlight more than one. Then click:
File > Print > ‘Print Selection’
To print double-sided handouts -
Highlight both slides before using ‘Print Selection’.
Choose ‘Print on Both Sides’ and ‘Flip on Short Edge’.

3. BINGO! 45 54 23 82 37 12 76 25 91
Substitution with
a Calculator

4. Choose your numbers… −7.7 19.8 9.7 22.4 12.6 −6.6 11.5 48.5 −8.2 13.2
0.4
−2.8
−12.1
0.1
10.8
−7.4
Draw a 3x3 grid in your book.

5. Substitute the values for the variables to find the answer.
𝑇=0.4
𝑔=0
𝑚=−2.2
𝑝=3
𝑇2−𝑝=
−2.84
0.42−3=
=−2.8
Give your answer to 1 dp.

6. Substitute the values for the variables to find the answer.
𝑎=3.2
𝑏=−1.4
𝑐=−0.6
𝑑=3
𝑎2+𝑑=
13.24
3.22+3=
=13.2
Give your answer to 1 dp.

7. Substitute the values for the variables to find the answer.
𝐺=0.8
𝑖=−1.4
𝐻=2.6
𝑡=−2
5𝑡−3𝐺3=
−11.536
5×−2 −3×0.83=
=−11.5
Give your answer to 1 dp.

8. 2𝑚2+3𝑔= 9.68 =9.7 𝑇=0.4 𝑔=0 𝑚=−2.2 𝑝=3 2×(−2.2)2+3×0=
Substitute the values for the variables to find the answer.
𝑇=0.4
𝑔=0
𝑚=−2.2
𝑝=3
2𝑚2+3𝑔=
9.68
2×(−2.2)2+3×0=
Do we need to include the negative
in this calculation?
=9.7
Give your answer to 1 dp.

9. Substitute the values for the variables to find the answer.
𝑤=−2
𝑥=4.5
𝑦=−2.7
𝑧=0.4
3𝑦−𝑤2=
−12.1
3×−2.7 − −2 2=
Give your answer to 1 dp.

10. Substitute the values for the variables to find the answer.
𝑎=3.2
𝑏=−1.4
𝑐=−0.6
𝑑=3
2𝑎2+𝑏2=
22.44
2×3.22+(−1.4)2=
=22.4
Give your answer to 1 dp.

11. Substitute the values for the variables to find the answer.
𝑤=−2
𝑥=4.5
𝑦=−2.7
𝑧=0.4
2𝑧2+𝑤3=
−7.68
2×0.42+ −2 3=
=−7.7
Give your answer to 1 dp.

12. 𝑎2+𝑏2+𝑐2= 12.56 =12.6 𝑎=3.2 𝑏=−1.4 𝑐=−0.6 𝑑=3 3.22+ −1.4 2+ −0.6 2=
Substitute the values for the variables to find the answer.
𝑎=3.2
𝑏=−1.4
𝑐=−0.6
𝑑=3
𝑎2+𝑏2+𝑐2=
12.56
3.22+ − −0.6 2=
Do we need to include negatives
in these calculations?
=12.6
Give your answer to 1 dp.

13. Substitute the values for the variables to find the answer.
𝑤=−2
𝑥=4.5
𝑦=−2.7
𝑧=0.4
0.5𝑥𝑧2=
0.36
0.5×4.5×0.42=
=0.4
Give your answer to 1 dp.

14. Substitute the values for the variables to find the answer.
𝑎=3.2
𝑏=−1.4
𝑐=−0.6
𝑑=3
3𝑐𝑑−𝑏2=
−7.36
3×−0.6×3 − −1.4 2=
=−7.4
Give your answer to 1 dp.

15. Substitute the values for the variables to find the answer.
𝑇=0.4
𝑔=0
𝑚=−2.2
𝑝=3
𝑔𝑇+3𝑚𝑝=
19.8
0×0.4+3×−2.2×3=
Give your answer to 1 dp.

16. Substitute the values for the variables to find the answer.
𝐺=0.8
𝑖=−1.4
𝐻=2.6
𝑡=−2
3𝐻−𝑖2+5=
10.84
3×2.6− − =
=10.8
Give your answer to 1 dp.

17. Substitute the values for the variables to find the answer.
𝐺=0.8
𝑖=−1.4
𝐻=2.6
𝑡=−2
2𝐻𝑖+𝐺2=
−6.64
2×2.6×− =
=−6.6
Give your answer to 1 dp.

18. Substitute the values for the variables to find the answer.
𝑇=0.4
𝑔=0
𝑚=−2.2
𝑝=3
𝑝𝑇2 8 =
3×(−0.4)2 8 =
0.06
=0.1
Give your answer to 1 dp.

19. Substitute the values for the variables to find the answer.
𝑤=−2
𝑥=4.5
𝑦=−2.7
𝑧=0.4
2𝑥2−𝑤3=
48.5
2×4.52− −2 3=
Give your answer to 1 dp.

20. Substitute the values for the variables to find the answer.
𝐺=0.8
𝑖=−1.4
𝐻=2.6
𝑡=−2
𝑡2+3𝑖3−5𝐺=
−8.232
−2 2+3× −1.4 3−5×0.8=
=−8.2
Give your answer to 1 dp.

22. tom@goteachmaths.co.uk Questions? Comments? Suggestions?
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