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Simultaneous Equations – Forming & Solving– Higher – GCSE Questions

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Presentation on theme: "Simultaneous Equations – Forming & Solving– Higher – GCSE Questions"— Presentation transcript:

1 Simultaneous Equations – Forming & Solving– Higher – GCSE Questions
These questions are the same format as previous GCSE exams. COPY means they use the exact same numbers as the original GCSE question. Otherwise, they are clone questions using different numbers. The worksheets are provided in a variety of sizes.

2 Printing To print handouts from slides -
Select the slide from the left. Then click: File > Print > ‘Print Current Slide’ To print multiple slides - Click on a section title to highlight all those slides, or press ‘Ctrl’ at the same time as selecting slides to highlight more than one. Then click: File > Print > ‘Print Selection’ To print double-sided handouts - Highlight both slides before using ‘Print Selection’. Choose ‘Print on Both Sides’ and ‘Flip on Short Edge’.

3 GCSE GCSE Edexcel Higher: November 2017 Paper 1, Q11
2 cakes and 3 rolls have a total cost of £7.20 5 cakes and 6 rolls have a total cost of £15.60 Work out the cost on one cake and the cost of one roll. 1 2 cakes and 3 rolls have a total cost of £7.20 5 cakes and 6 rolls have a total cost of £15.60 Work out the cost on one cake and the cost of one roll. cake £ cake £ roll £ roll £ (Total for Question 1 is 4 marks) (Total for Question 1 is 4 marks)

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5 GCSE Edexcel Higher: November 2017 Paper 1, Q11
2 cakes and 3 rolls have a total cost of £7.20 5 cakes and 6 rolls have a total cost of £15.60 Work out the cost on one cake and the cost of one roll. cake £ roll £ (Total for Question 1 is 4 marks)

6 Solve by balancing coefficients
GCSE Edexcel Higher: November 2017 Paper 1, Q11 1 2 cakes and 3 rolls have a total cost of £7.20 5 cakes and 6 rolls have a total cost of £15.60 Work out the cost on one cake and the cost of one roll. 2c + 3r = 720 5c + 6r = 1560 x 2 4c + 6r = 1440 Solve by balancing coefficients and then elimination 5c + 6r = 1560 Subtract 4c + 6r = 1440 c + 0r = 120 c = 120 720 - 240 480 Substitute to find r (2 x 120) + 3r = 720 r = 720 3r = 480 1.20 cake £ r = 160 1.60 roll £ (Total for Question 1 is 4 marks)

7 tom@goteachmaths.co.uk Questions? Comments? Suggestions?
…or have you found a mistake!? Any feedback would be appreciated . Please feel free to


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