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Moments of Random Variables

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Presentation on theme: "Moments of Random Variables"— Presentation transcript:

1 Moments of Random Variables
The moment generating function

2 Examples The Binomial distribution (parameters p, n)
The Poisson distribution (parameter l)

3 The Exponential distribution (parameter l)
The Standard Normal distribution (m = 0, s = 1)

4 The Gamma distribution (parameters a, l)
The Chi-square distribution (degrees of freedom n) (a = n/2, l = 1/2)

5 Properties of Moment Generating Functions
mX(0) = 1

6 The log of Moment Generating Functions
Let lX (t) = ln mX(t) = the log of the moment generating function

7 Thus lX (t) = ln mX(t) is very useful for calculating the mean and variance of a random variable

8 Examples The Binomial distribution (parameters p, n)

9 The Poisson distribution (parameter l)

10 The Exponential distribution (parameter l)

11 The Standard Normal distribution (m = 0, s = 1)

12 The Gamma distribution (parameters a, l)

13 The Chi-square distribution (degrees of freedom n)

14

15

16 Jointly distributed Random variables
Multivariate distributions

17 Discrete Random Variables

18 The joint probability function;
p(x,y) = P[X = x, Y = y]

19 Marginal distributions
Conditional distributions

20 Continuous Random Variables

21 Definition: Two random variable are said to have joint probability density function f(x,y) if

22 Marginal distributions
Conditional distributions

23 Independence

24 Definition: Two random variables X and Y are defined to be independent if if X and Y are discrete if X and Y are continuous Thus in the case of independence marginal distributions ≡ conditional distributions

25 The Multiplicative Rule for densities
if X and Y are discrete if X and Y are continuous

26 Proof: This follows from the definition for conditional densities: Hence and The same is true for continuous random variables.

27 Example: Suppose that a rectangle is constructed by first choosing its length, X and then choosing its width Y. Its length X is selected form an exponential distribution with mean m = 1/l = 5. Once the length has been chosen its width, Y, is selected from a uniform distribution form 0 to half its length. Find the probability that its area A = XY is less than 4.

28 Solution:

29 xy = 4 y = x/2

30

31 This part can be evaluated This part may require Numerical evaluation


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