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Homework Solutions
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June 2010 Odd vertices A, B, C, M AB + CM = or 73 AC + BM = or 73 AM + BC = or 70 Repeat AM + BC = 70 Min = = 454 bii) 8 edges at F so F will be visited 8 ÷ 2 = 4
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The ODD VERTICES are noted down A, C, D, F
The COMBINATIONS with DISTANCES AC + DF = = 40 AD + CF = = 62 AF + CD = = 42 REPEAT the SHORTEST DISTANCE AC + DF = = 40 TOTAL DISTANCE = 204
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b) Start / Finish A or C Repeat DF = 22 TOTAL DISTANCE = 186 ci) You need to repeat the shortest pair = AF Repeat AF = 12 TOTAL DISTANCE = 176 cii) Start / Finish at C / D
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The ODD VERTICES are noted down A, B, C, D
June 08 The ODD VERTICES are noted down A, B, C, D The COMBINATIONS with DISTANCES AB + CD = = 540 AC + BD = = 580 AD + BC = = 530 REPEAT the SHORTEST DISTANCE AD + BC = = 530 TOTAL DISTANCE = 2450
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bi) Repeats BC (Length = =) 2190 (metres) ci) She needs to repeat the shortest repeated distance which is AD = 260 (Length = =) 2180 (metres) cii) B or C
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The ODD VERTICES are noted down B, C, F, H
The COMBINATIONS with DISTANCES BC + FH = = 480 BF + CH = = 570 BH + CF = = 800 REPEAT the SHORTEST DISTANCE BC + FH = = 480 TOTAL DISTANCE = 2890
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