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Integral Calculus Problems 8/26/2019 rd.

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Presentation on theme: "Integral Calculus Problems 8/26/2019 rd."— Presentation transcript:

1 Integral Calculus Problems 8/26/2019 rd

2 2-Variable Function with a Maximum
z = f(x,y) 8/26/2019 rd

3 Sequence Problem Solving
?? ? ? 77 7*7 = 49 Skip every other prime 31 ?

4 2-Variable Function with both Maxima and Minima
z = f(x,y) 8/26/2019 rd

5 2-Variable Function with a Saddle Point
z = f(x,y) 8/26/2019 rd

6 Natural Logarithms With x/h = n tending to infinity yielding e
8/26/2019 rd

7 Integration Integral Calculus Stochastic (Probability) Models
Differential Equations Dynamic Models 8/26/2019 rd

8 Integration If F(x) is a function whose derivative F’(x) = f(x), then
F(x) is called the integral of f(x) For example, F(x) = x3 is an integral of f(x) = 3x2 Note also that G(x) = x3 + 5 and H(x) = x3 – 6 are also integrals of f(x) 8/26/2019 rd

9 Indefinite Integral The indefinite integral of f(x), denoted by
where C is an arbitrary constant is the most general integral of f(x) The indefinite integral of f(x) = 3x2 is 8/26/2019 rd

10 …or use a table of integrals
A Strategy Guess and Test the integrand …or use a table of integrals 8/26/2019 rd

11 Methods Of Integration
Integrating Power Functions Fundamental Arithmetic Integration Rules Basic Integration Formulas Tables of Integrals Non-Integrability Partial Fractions Integration by Parts xe-xdx = -xe-x + e-x dx let u = x; dv = e-x dx du = 1; v = -e-x 8/26/2019 rd

12 Integration by Parts d(uv) = udv + vdu udv = uv - vdu Show that xnexdx = xnex - nxn-1exdx + C let u = xn; dv = exdx then du = nxn-1dx; v = ex + C Thus, xnexdx = xnex - nxn-1ex dx + C 8/26/2019 rd

13 The top five 8/26/2019 rd

14 Basic Rules of Integration
8/26/2019 rd

15 The top four and the basic rules in action…
8/26/2019 rd

16 Initial Conditions The rate at which annual income (y) changes with respect to years of education (x) is given by where y = 28,720 when x = 9. Find y. 8/26/2019 rd

17 Integrating au , a > 0 8/26/2019 rd

18 Helpful Methods 8/26/2019 rd

19 Use some algebra 8/26/2019 rd

20 Adjusting for “du” – method of substitution
8/26/2019 rd

21 More du’s 8/26/2019 rd

22 Integrate x(x - 1)1/2 8/26/2019 rd

23 Partial Fractions 8/26/2019 rd

24 Integration by Parts derived from the product rule for derivatives
8/26/2019 rd

25 Another one? 8/26/2019 rd

26 Integration by Tables A favorite integration formula of engineering students is: 8/26/2019 rd

27 Check it out! 8/26/2019 rd

28 Another Table Problem 8/26/2019 rd

29 An Engineer’s Favorite Table
8/26/2019 rd

30 The Definite Integral Areas under the curve 8/26/2019 rd

31 Definite Integral Given a function f(x) that is continuous on the interval [a,b] we divide the interval into n subintervals of equal width, x, and from each interval choose a point, xi*.  Then the definite integral of f(x) from a to b is 8/26/2019 rd

32 Area under the curve f(x) x x 8/26/2019 rd

33 The Fundamental Theorem of Calculus
Let f be a continuous real-valued function defined on a closed interval [a, b]. Let F be a function such that                    for all x in [a, b] then                                  . 8/26/2019 rd

34 Fundamental Theorem 8/26/2019 rd

35 Evaluating a definite integral
8/26/2019 rd

36 Changing Limits 8/26/2019 rd

37 The Area under a curve The area under the curve of a probability density function over its entire domain is always equal to one. Verify that the following function is a probability density function: 8/26/2019 rd

38 Area between Curves Find the area bounded by y = 4 – 4x2 and y = x2 - 1 y1 = 4 – 4x2 y1 - y2 = 5 – 5x2 (-1, 0) (1, 0) y2 = x2 - 1 8/26/2019 rd

39 Area Find area bounded by y2 – x = 0 and y – x + 6 = 0. Curves intersection at y2 – y – 6 = 0; (y-3)(y+2) (x – 6)2 - x = 0 => (x – 9)(x – 4) = 0 (9,3) (4, -2) (+ 32/3 54/3 -81/ / ) -->125/6 8/26/2019 rd

40 Rectilinear Motion A particle moves right from the origin on the x-axis with acceleration a = 5 – 2t and v0 = 0. How far does it go? a = 5 – 2t => v = 5t – t2 + v0 => s = 5t2/2 – t3/3 v = 0 when = 5t – t2 = 0 or when t = 5 s(5) = 125/2 -125/3 = 125/6 ft 8/26/2019 rd

41 Y = x; x2; x3 8/26/2019 rd

42 Improper Integrals 8/26/2019 rd

43 Example – an Improper Integral
8/26/2019 rd

44 Let’s do another one… 8/26/2019 rd

45 The Engineers Little Table of Improper Definite Integrals
8/26/2019 rd

46 Some Applications Taking it to the limit… 8/26/2019 rd

47 The Crime Rate The total number of crimes is increasing at the rate of 8t + 10 where t = months from the start of the year. How many crimes will be committed during the last 6 months of the year? 8/26/2019 rd

48 Learning Curves Cumulative Cost
hours to produce ith unit cumulative direct labor hrs to produce x units average unit hours to produce x units 8/26/2019 rd

49 Learning Curves Approximate Cumulative Cost
8/26/2019 rd

50 Learning Curves - example
Production of the first 10 F-222’s, the Air Force’s new steam driven fighter, resulted in a 71 percent learning curve in dollar cost where the first aircraft cost $18 million. What will be cost of the second lot of 10 aircraft? (sim-lc 18e ) (sim-lc 18e ) 8/26/2019 rd

51 The Average of a Function
The average or mean value of a function y = f(x) over the interval [a,b] is given by: Find the average of the function y = x2 over the interval [1,3]: 8/26/2019 rd

52 Average profit An oil company’s profit in dollars for the qth million gallons sold is given by P = P(q) = 369q – 2.1q2 – 400 If the company sells 100 million gallons this year, what is the average profit per gallon sold? 8/26/2019 rd

53 An Inventory Problem Demand for an item is constant over time at the rate of 720 per year. Whenever the on-hand inventory reaches zero, a shipment of 60 units is received. The inventory holding cost is based upon the average on-hand inventory. Let y = 60 – 720t be the on-hand inventory as a function of time where t is in years. It takes 60/720 = 1/12 yr to go from an inventory of 60 to 0. 60 t 8/26/2019 rd

54 Annuities A is the present value of a continuous income stream
Let A = the present value of a continuous annuity at an annual rate r (compounded continuously) for T years if a payment at time t is at the rate of f(t) per year. Then A is the present value of a continuous income stream 8/26/2019 rd

55 Annuity Example Determine the present value of a continuous annuity at an annual rate of 8% for 10 years if the payment at time t is at the rate of 1000t dollars per year. 8/26/2019 rd

56 Annuities Let S = the accumulated amount of a continuous annuity at an annual rate r (compounded continuously) for T years if a payment at time t is at the rate of f(t) per year. Then 8/26/2019 rd

57 Back to the example 8/26/2019 rd

58 More of that example Recall continuous compounding 8/26/2019 rd

59 Iterated Integrals Evaluate 8/26/2019 rd

60 Double Integral Evaluate the integral over R where R is the triangle formed by y = x, y = 0, x = 1. 8/26/2019 rd

61 f(x, y) = 2 for 0 < x < y < 1
Find 8/26/2019 rd

62 Area between Regions Find the area bounded by y = x3 - 4x and y = 3x Curves intersect at (cubic )  ( ) 8/26/2019 rd

63 Quadratic Equation Derivation
ax2 + bx + c = 0 x2 + (b/a)x + (c/a) = 0 Complete the square x2 + (b/a)x + (c/a) + (b2/4a2) = (b2/4a2) (x + b/2a)2 = -c/a + b2/4a2 x = -b/2a + (- c/a + b2/4a2)1/2 = - b  (b2 – 4ac)1/2 2a 8/26/2019 rd

64 Partial Fractions Solve for A and B by the cover-up method and integrate to get 3 ln(x - 2) + 2 ln(x + 4) + C or ln(x - 2)3(x + 4)2 + C 8/26/2019 rd

65 Sketch the Plane 2x + 3y + 4 = 12 z 3 4 y 6 x 8/26/2019 rd

66 Tangent Find the equation of the tangent to the curve y = x ln x – x where x = 1. y' = 1 + ln x – 1 = ln x or ln 1 = 0 y = -1 at x = 1 with slope 0. (y +1) = 0(x – 1) => y = -1 8/26/2019 rd

67 Predator/Prey # prey attack y = K(1 - ex), K and  constants dy/dx = Kex and ex = -y/K +1 => dy/dx = K(-y/K + 1) = (K – y) 8/26/2019 rd

68 Average Value of a Function over [a, b].
Find the average value of f(x) = 2 – 3x2 over [-1, 2] 8/26/2019 rd


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